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A snowboarder starts from rest at the top of a double black diamond hill. As she rides down the slope, GPS coordinates are used to determine her displacement as a function of time:
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- Starting from rest at home plate, a baseball player runs to first base (90 ft away). He uniformly accelerates over the first 13.8 ft to his maximum speed, which is then maintained until he crosses first base. If the overall run is completed in 3.7 seconds, determine his maximum speed, the acceleration over the first 13.8 feet, and the time duration of the acceleration. t = 0 A & 13.8 Answers: Vmax= a = t= i i i 76.2¹ t = 3.7 sec ft/sec ft/sec² secarrow_forwarda_av = 3.9051 m/s^2arrow_forwardA human-powered vehicle (HPV) team wants to model the acceleration during the 260-m sprint race (the first 60 m is called a flying start) using a= A- Cv2, where a is acceleration in m/s2 and v is the velocity in m/s. From wind tunnel testing, they found that C = 0.0012 m-1 . Knowing that the cyclist is going 100 km/h at the 260-meter mark, what is the value of A?arrow_forward
- At a football tryout, a player runs a 40-yard dash in t, = 4.70 seconds. If the reaches his maximum speed at the 14-yard mark L, with a constant acceleration and then maintains that speed for the remainder of the run, determine his acceleration over the fırst 14 yards, his maximum speed, and the time duration of the acceleration. t = 0 Amswers: His acceleration: i ft/sec2 a = His maximum speed: i ft/sec The time duration of the acceleration: t= i secarrow_forwardKindly show the complete step-by-step solution. I hope the picture of the asnwer will be clear. Please see the attached photo for the given problem. I will rate you with “like/upvote” after if its clear and understandable.arrow_forwardA particle moving along the s-axis has a velocity given by v = 22.3 -3.7t² ft/sec, where t is in seconds. When t = 0, the position of the particle is given by so = 3.9 ft. For the first 3.5 seconds of motion, determine the total distance D traveled, the net displacement As, and the value of s at the end of the interval. Answers: Total distance traveled, Net Displacement, The value of s at the end of the interval, D= As = S= i i i ft ft ftarrow_forward
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- After a vigorous soccer match, Tina and Michael decide to have a glass of their favorite refreshment. They each run in a straight line along the indicated paths at a speed of 10 ft/sec. Tina Michael Michael Write parametric equations for the motion of Tina and Michael individually after t seconds. (Round all numerical values to four decimal places as needed.) X = Tina y = Michael X = (-50, 200) ● beet juice y = -0.4286t+ 128.5714 ● (200, 300) soy milk (300, 50) Find when Tina and Michael are closest to one another. (Round your answer to four decimal places.) t = S (x, y) = Tina Find where Tina and Michael are closest to one another. (Round your answers to three decimal places.) (x, y) =arrow_forward1- A particle moves along the x axis. Its position varies with time according to the expression x=-41+ 2f where x is in meters and t is in seconds. The position-time graph for this motion is shown in Figure. Note that the particle moves in the negative x direction for the first second of motion, is momentarily at rest at the moment 1 = 1 s, and moves in the positive x direction at times /> 1 s. (A) Determine the displacement of the particle in the time intervals t=0 to 1=1 s and t= 1 s to / = 3 s. B) Calculate the average velocity during these two-time intervals C) determine the instantaneous velocity and instantaneous speed at t= 0.5 s. x(m) Slope = 4 m/s 10 00 8 9 10 O Slope =-2 m/s 1 2 015 t(s)arrow_forwardThe motion of a particle is given by the equation s = 2t to the 4th power minus t cubes over 6 plus 2t squared where s is in mm and t in seconds. Compute the values of velocity (v) and acceleration (a) when t = 2 sec. Graph and label the v-t and a-t relations.arrow_forward
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