Concept explainers
Based on experimental observations, the acceleration of a particle is defined by the relation
(a)
The velocity of particle when x = -1 m.
Answer to Problem 11.19P
Velocity
Explanation of Solution
Given information:
The acceleration of the particle is given by the equation:
Where (a) in m/s2 and (x) is in meters.
Also the given condition is that: v=1m/s when x=0 and b=0.8 m.
The basic kinematics relation is given by the equation, if
Now, integrate the above equation within the limits when x=0, v=1 m/s.
Put x=-1 in the equation, we get:
Conclusion:
The velocity of the particle when x=-1 m is
(b)
The position where the velocity is maximum.
Answer to Problem 11.19P
The position is
Explanation of Solution
Given information:
The motion of the particle is given by the equation:
Where (a) in m/s2 and (x) is in meters.
Also the given condition is that: v=1m/s when x=0 and b=0.8 m.
When v=vmax, a=0
From above given equation:
Conclusion:
The position when velocity is maximum is
(c)
The maximum velocity.
Answer to Problem 11.19P
The maximum velocity
Explanation of Solution
Given information:
The motion of the particle is given by the equation:
Where (a) in m/s2 and (x) is in meters.
Also, the given condition is that: v=1m/s when x=0 and b=0.8 m.
The basic kinematics relation is given by the equation:
Now, integrate the above equation within the limits when x=0, v=1 m/s.
Put x=-0.0801 in the equation, we get:
Conclusion:
The velocity of the particle when x=-0.0801 m is
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Chapter 11 Solutions
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