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Based on observations, the speed of a jogger can be approximated by the relation
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Vector Mechanics for Engineers: Dynamics
- 1. please provide handwritten solutionarrow_forwardmoments = 0) in order to determine a force or moment requires a complete free body diagram. Absence of a free body diagram may result in a grade of 'O' for the problem. %3D 1. The acceleration of a particle is directly proportional to time, t, i.e., a = at where a is a constant. At t = 0 s, the position of the particle is -150 mm. Knowing that v = 200 mm/s and x = 75 mm whent = 3 s, determine the position and velocity when t = 5 s.arrow_forwardThe acceleration of a particle moving along the x-axis is given by the relation a = kt m/s?., where k is a constant, and i is in seconds. Supposed that v = -10 m/s, x = x, when / = 0 and x = 0, v = 0 when t = 6 s, determine (a) the value of the constants k and x,, (b) the position as a function of t. %3Darrow_forward
- I need help with this question please. thank youarrow_forwardStarting from rest, a bicyclist travels around a horizontal circular path, p= 10 m, at a speed of (0.09t2 + 0.1t) m/s, where t is in seconds. Part A Determine the magnitude of his velocity when he has traveled s = 3 m. Express your answer to three significant figures and include the appropriate units. HA ? Value Units v = Submit Request Answer Part B Determine the magnitude of his acceleration when he has traveled s = 3 m. Express your answer to three significant figures and include the appropriate units. HẢ Value Units a = Submit Request Answerarrow_forwardJack run on a marathon with a speed that can be approximated by the relation v= 6.5(1.2 - 0.05x) ^ 0.3, where v and x are expressed in mi/h and miles respectively. Knowing that x= 0 at t = 0, determine (a.) the distance Jack has run when t =1h, (b) Jack's acceleration in ft/s^2 at t=0, (c.) the time required for him to run 6 mi. helppparrow_forward
- 1) Some civil engineers are designing an Autobahn connecting Reno and Vegas to reduce the drive time. There are several hilly stretches between the two cities. They would like to keep the magnitude of acceleration on the drivers to be less than one g. They run a test where the speed of a biker decreased uniformly with time from 150 km/h at A to 100 km/h at B over 10 seconds. The radius of curvature for dip A is 200 m. If the magnitude of the total acceleration of the center of the mass of the bike is the same at B as at A, compute the radius of curvature rs of the hill in the road at B. The center of the mass of the car is 0.5 m from the road. [Ans. To Check: re-88.5m] TA = 200 m A VA= 150 km/h H = 0.5 m B VB = 100 km/h TB = ? marrow_forwardDr. Wang was doing donuts (i.e. driving in a circle) in his car over the weekend and used his iPhone to measure the acceleration he experienced (this is a true story). The plot below shows the lateral acceleration recorded by his iPhone. Knowing that he was maintaining a constant speed and that the radius of his donuts was 10 meters, determine how fast he was driving and approximately how many donuts (laps) did he completed in the 6 seconds shown?arrow_forwardAn automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile at a constant acceleration of 1.96 m/s . The motorist noticed the police car in his rearview mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s . (Hint: The police will not go against the law.) a) Find the total time required for the police car to overtake the automobile. b) Find the total distance travelled by the police car while overtaking the automobile. c) Find the speed of the police car a the time it overtakes the automobile. d) Find the speed of theautomobile at the time it was overtaken by the police car.arrow_forward
- e V:.. | %A£ ]n. Time left 0:19:30 Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB = 23.4 km/hr. at t = 0.0. Knowing that automobile A has a constant acceleration of 0.8 m/s2 and automobile B has a constant deceleration of 0.4 m/s2. The speed of B when it is overtaken by A is: A Side view 73.579 m/s 34.621 m/s 11.564 m/s 2.718 m/s 43.578 m/s IIarrow_forwardX Incorrect Car A rounds a curve of 172-m radius at a constant speed of 37 km/h. At the instant represented, car B is moving at 97 km/h but is slowing down at the rate of 2.5 m/s². Determine the velocity and acceleration of car A as observed from car B. A 172 m 10.278 j) m/s 1.885 j) m/s² Answer: VA/B = aA/B = -26.94 0.164 (E) B i + i i + iarrow_forwardA particle moves along a straight line such that its position is defined by s = (t2 – 6t +5) m Part B Determine the average speed of the particle whent = 5.9 s. Express your answer to three significant figures and include the appropriate units. HA ? (Vsp)avg = Value Units Submit Request Answer Part C Determine the acceleration of the particle when t = 5.9 s. Express your answer to three significant figures and include the appropriate units. HA ? Value Units a =arrow_forward
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