Explanation Given information: Angle α = 25 ° For a uniformly accelerated motion, x = x 0 + v 0 t + 1 2 a t 2 In above equation, x - End distance x 0 - Start distance v 0 - Initial velocity t - Elapsed time a -Acceleration Calculation: For the projectile motion, Assume origin as point A Therefore, x 0 = 0 y 0 = 0 According to given information, x B = 30 f t y B = − 18 f t For horizontal motion, velocity is equal to, v x = v 0 cos 25 ° The distance traveled is equal to, x = ( v 0 cos 25 ° ) t For vertical motion, velocity is equal to, v y = v y 0 + a t v y = ( v 0 sin 25 ° ) − g t The distance is equal to, y = y 0 + v y 0 t + 1 2 a t 2 y = ( v 0 sin 25 ° ) t − 1 2 g t 2 According to below equation, x = ( v 0 cos 25 ° ) t At point B, v 0 t B = x cos 25 ° = 30 cos 25 ° = 33 To determine (b) The radius of curvature?

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 11, Problem 11.191RP

To determine

(a)

The speed v0 of the belt.

To determine

(b)

The radius of curvature?

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Chapter 11, Problem 11.190RP

Chapter 11, Problem 11.192RP

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