
(a)
Interpretation:
The most reactive non-metal needs to be determined.
Concept Introduction:
By accepting electrons, non -metals achieve a stable half-filled or full-filled configuration and these non-metals are most reactive in nature.
(a)

Answer to Problem 72A
Fluorine is the most reactive non-metal.
Explanation of Solution
The electronic configuration of fluorine is
(b)
Interpretation:
The smallest lanthanide element needs to be determined.
Concept Introduction:
The lanthanide contraction decreases more in ionic radii of the elements in the lanthanide series than expected.
(b)

Answer to Problem 72A
Lutetium is smallest lanthanide element.
Explanation of Solution
With an increase in the
Since the atomic number of lutetium is
(c)
Interpretation:
The largest metalloid in the periodic table needs to be determined.
Concept Introduction:
The metalloids are the elements which show the behavior of metals as well as non-metals.
(c)

Answer to Problem 72A
Polonium (Po) is the largest metalloid.
Explanation of Solution
As we move downwards, protons and electrons are being added to the same principal energy level. These electrons are gradually attracted closer to the nucleus. So, the radius of the atom decreases.
Since polonium is present in period 6 and group 16, its size is largest among metalloids.
(d)
Interpretation:
The metal with the lowest ionization energy has to be determined.
Concept Introduction:
Ionization energy is a measure of the difficulty in removing an electron from an atom or ion or the tendency of an atom or ion to lose an electron. This is the energy required. So, the process is endothermic.
(d)

Answer to Problem 72A
The element with the smallest ionization energy is cesium.
Explanation of Solution
Electronic configuration of cesium is
As we move downwards, the value of ionization energy decreases because the valence electrons are going away from the nucleus and feel more shielding and weak attraction Hence, Cesium has the lowest ionization energy.
(e)
Interpretation:
The least reactive halogen has to be determined.
Concept Introduction:
Halogens get less reactive as we go down the group.
(e)

Answer to Problem 72A
Astatine is the least reactive among the halogens.
Explanation of Solution
The electrons in the outer shell move away from the nucleus as we go down the group and the attractive pull between the electrons and the nucleus becomes less. So, the gain of an electron is not effective. Therefore, the reactivity of the atom reduces.
Since astatine is down the group in the halogen series it is least reactive.
(f)
Interpretation:
The least reactive member of the fifth period has to be determined.
Concept Introduction:
There are 10
(f)

Answer to Problem 72A
Cadmium is the least reactive member of the fifth period.
Explanation of Solution
The electronic configuration of Cadmium is
To react, an atom either gains or donates an electron. That is only possible if the valence electron shell is not filled completely.
If Cd undergoes reaction it has to break its highly stable full-filled outer electronic configuration.
(g)
Interpretation:
The actinide with the highest nuclear charge has to be determined.
Concept Introduction:
The nuclear charge is the charge an electron experiences in an atom with multiple other electrons present in the same atom.
In general
(g)

Answer to Problem 72A
Lawrencium has the highest nuclear charge.
Explanation of Solution
Actinides start from actinium
Since lawrencium has the highest number of protons, its nuclear charge among the actinide is also highest.
Chapter 11 Solutions
World of Chemistry
- Draw the major product of this reaction. Ignore inorganic byproducts. N S S HgCl2, H2SO4 く 8 W X Parrow_forwardtab esc く Drawing the After running various experiments, you determine that the mechanism for the following reaction occurs in a step-wise fashion. Br + OH + Using this information, draw the correct mechanism in the space below. 1 Explanation Check F2 F1 @2 Q W A os lock control option T S # 3 80 F3 Br $ 4 0105 % OH2 + Br Add/Remove step X C F5 F6 6 R E T Y 29 & 7 F D G H Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce A F7 DII F8 C Ո 8 * 9 4 F10 F C J K L C V Z X B N M H command P ge Coarrow_forwardIndicate compound A that must react with ethylbenzene to obtain 4-ethylbenzene-1-sulfonic acid. 3-bromo-4-ethylbenzene-1-sulfonic acid.arrow_forward
- Part 1 of 2 Draw the structure of A, the minor E1 product of the reaction. esc I Skip Part Check H₂O, D 2 A + Click and drag to start drawing a structure. -0- F1 F2 1 2 # 3 Q A 80 F3 W E S D F4 $ 4 % 5 F5 ㅇ F6 R T Y F G X 5 & 7 + Save 2025 McGraw Hill LLC. All Rights Reserved. DII F7 F8 H * C 80 J Z X C V B N 4 F9 6arrow_forwardFile Preview The following is a total synthesis of the pheromone of the western pine beetle. Such syntheses are interesting both because of the organic chemistry, and because of the possibility of using species specific insecticides, rather than broad band insecticides. Provide the reagents for each step. There is some chemistry from our most recent chapter in this synthesis, but other steps are review from earlier chapters. (8 points) COOEt COOEt A C COOEt COOEt COOH B OH OTS CN D E See the last homework set F for assistance on this one. H+, H₂O G OH OH The last step is just nucleophilic addition reactions, taking the ketone to an acetal, intramolecularly. But it is hard to visualize the three dimensional shape as it occurs. Frontalin, pheromone of the western pine beetlearrow_forwardFor the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. C Major Product: Check + ◎ + X ง © Cl I F2 80 F3 I σ F4 I F5 NaOH Click and drawing F6 A 2025 McGraw Hill LLC. All Rights E F7 F8 $ # % & 2 3 4 5 6 7 8 Q W E R T Y U A S D F G H Jarrow_forward
- Can I please get help with this graph. If you can show exactly where it needs to pass through.arrow_forwardN Draw the major product of this reaction. Ignore inorganic byproducts. D 1. H₂O, pyridine 2. neutralizing work-up V P W X DE CO e C Larrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. N O' 1. H2O, pyridine 2. neutralizing work-up く 8 W aarrow_forward
- Ideal Gas Law Practice Name If you need a refresher on Ideal Gas Law, go back to your Ideal Gas Law Reading Assignment from last week! On all of the following, you'll need to make sure to convert pressures to atm and convert temperatures to Kelvin in order to be able to use the R gas constant on your equation sheet! Given: Ideal Gas Law = then P= pressure V = volume R= ideal gas consent PV=nRT namount of substance n=PV/TR P=nRT/V I = temperature V=nRT/P T=PV/nR R=PV/nT 1. What pressure is required to contain 0.023 moles of nitrogen gas in a 4.2 L container at a temperature of 20.°C? 2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volume of 10.0 L. What temperature must be maintained on 0.500 moles of this gas in order to maintain this pressure? Express the temperature in degrees Celsius. 3. How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100. °C? After determining the number of moles,…arrow_forward1. The following conversion includes chemistry we have covered very recently, some chemistry from last term, and chemistry from the first chapter of this unit. Provide curly arrows and an explanation for this mechanism. Use the reagents in the order given. You do not need any other reagents. 1. NaOEt OEt 2.arrow_forwardCOOEt COOEt Step 1 Step 2 Step 3 COOEt COOEt COOH Step 6 OH Step 4 Step 7 (racemic) cyclizes under conditions (8) OTS Step 5 Step 8 ОН OH (racemic) Frontalin (racemic) Shown above are the steps in one of the several published syntheses of Frontalin, a pheromone of the western pine beetle. From the choices provided, show the reagents and conditions by which step 3 of this synthesis might be accomplished. List the reagent(s) in order that will accomplish this transformation. No more than 4 steps are required. List your answer as a single letter (single-step transformation) or a series of letters (multi-step transformation) with no commas separating them. For example, "ab" corresponds to: 1. Eto Na+ 2. NaOH, H₂O NOTE: The order in which you list your letters matters! Reagents: a. Eto Na* g. NaCN b. NaOH, H₂O h. SOCI₂ c. H3O+, heat i. (CH3)2CuLi, ether, -78°C d. LiAlH4 j. H₂O e. p-TsCI, pyridine k. RCO3H f. Br I. H3O+ 1,024arrow_forward
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