
(a)
Interpretation:
The general valence configuration of N needs to be given.
Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.
(a)

Answer to Problem 63A
The general valence configuration of Nitrogen is,
Explanation of Solution
Nitrogen has 7 electrons as its
(b)
Interpretation:
The general valence configuration of francium needs to be given.
Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.
(b)

Answer to Problem 63A
The general valence configuration of Francium is,
Explanation of Solution
Francium has 87 electrons as its atomic number is given to be 87. So they are arranged as:
(c)
Interpretation:
The general valence configuration of chlorine needs to be given.
Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.
(c)

Answer to Problem 63A
The general valence configuration of Chlorine is,
Explanation of Solution
Chlorine has 17 electrons as its atomic number is given to be 17. So they are arranged as:
(d)
Interpretation:
The general valence configuration of Se element needs to be given.
Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.
(d)

Answer to Problem 63A
The general valence configuration of Selenium is,
Explanation of Solution
Selenium has 34 electrons as its atomic number is given to be 34. So they are arranged as:
(e)
Interpretation:
The general valence configuration of the given element Mg needs to be given.
Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.
(e)

Answer to Problem 63A
The general valence configuration of Magnesium is,
Explanation of Solution
Magnesium has 12 electrons as its atomic number is given to be 12. So they are arranged as:
Chapter 11 Solutions
World of Chemistry
- Explain how, based on physical gas adsorption isotherms, we can determine whether multi-walled C nanotubes are open at their ends. Explain this.arrow_forwardcan somone answer pleasearrow_forwardConstruct a molecular orbital energy-level diagram for BeH2. Sketch the MO pictures (schematic representation) for the HOMO and LUMO of BeH2 [Orbital Potential Energies, H (1s): -13.6 eV; Be (2s): -9.3 eV, Be (2p): -6.0 eV]arrow_forward
- Indicate the isomers of the A(H2O)6Cl3 complex. State the type of isomerism they exhibit and explain it briefly.arrow_forwardState the formula of the compound potassium μ-dihydroxydicobaltate (III) tetraoxalate.arrow_forwardConsider the reaction of the cyclopentanone derivative shown below. i) NaOCH2CH3 CH3CH2OH, 25°C ii) CH3!arrow_forward
- What constitutes a 'reference material', and why does its utilization play a critical role in the chemical analysis of food products? Provide examples.arrow_forwardExplain what calibration is and why it is essential in relation to food analysis. Provide examples.arrow_forwardThe cobalt mu-hydroxide complex cobaltate(III) of potassium is a dinuclear complex. Correct?arrow_forward
- The cobalt mi-hydroxide complex cobaltate(III) of potassium is a dinuclear complex. Correct?arrow_forward3. Arrange the different acids in Exercise B # 2 from the strongest (1) to the weakest acid (10). 1. 2. (strongest) 3. 4. 5. 6. 7. 8. 9. 10 10. (weakest)arrow_forwardName Section Score Date EXERCISE B pH, pOH, pка, AND PKD CALCULATIONS 1. Complete the following table. Solution [H+] [OH-] PH РОН Nature of Solution A 2 x 10-8 M B 1 x 10-7 M C D 12.3 6.8 2. The following table contains the names, formulas, ka or pka for some common acids. Fill in the blanks in the table. (17 Points) Acid Name Formula Dissociation reaction Ka pka Phosphoric acid H₂PO₁ H3PO4 H++ H₂PO 7.08 x 10-3 Dihydrogen H₂PO H₂PO H+ HPO 6.31 x 10-6 phosphate Hydrogen HPO₁ 12.4 phosphate Carbonic acid H2CO3 Hydrogen HCO 6.35 10.3 carbonate or bicarbonate Acetic acid CH,COOH 4.76 Lactic acid CH₂CHOH- COOH 1.38 x 10 Ammonium NH 5.63 x 10-10 Phenol CH₂OH 1 x 10-10 Protonated form CH3NH3* 3.16 x 10-11 of methylaminearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





