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Concept explainers
Interpretation: Theuse of excess energy of the atom needs to be explained which is released when an atom returns back to the group state from the excited state.
Concept interpretation:An electron jumps from lower energy level to higher energy level by absorbing energy equal to the difference in the energy between the two levels.
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Answer to Problem 12A
When electron jumps from higher energy level to lower energy level it losses energy equal to the energy difference between the levels by the process of emission. This emission of energy takes the form of a visible light. For example, emission of energy from copper shows green color and the color varies on the amount of energy release from different atoms.
Explanation of Solution
Although the energy absorbed by the electron follows the law of conservation of energy the energy that is absorbed by the electron to go into the higher state is equal to the energy emitted by the electron to return back to the ground state. So the color shown in atom while emitting have the same amount of energy.
Hence, the excess energy released from an electron while returning to ground state is equal to the energy absorbed while going to excited state and that emitted energy is shown in the form of visible light.
Chapter 11 Solutions
World of Chemistry
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- There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forwardA mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forward
- Provide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forwardWhat units (if any) does K have? Does K depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)? in calculating the response factorarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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