Chapter 11, Problem 62A

(a)

Interpretation Introduction

Interpretation: Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for the given elements is to be given.

Concept Introduction: Electronic configuration is the arrangement of electrons in the increasing order of energy in the sub-shells of an atom. Atomic number is equal to the number of electrons present in the atom of an element.

Explanation of Solution

Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for an element with atomic number 19 are

  ${}_{19}K=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^1$

  

and

  ${}_{19}K=\left[Ar\right]4s¹$ respectively.

(b)

Interpretation Introduction

Interpretation: Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for the given elements is to be given.

Concept Introduction: Electronic configuration is the arrangement of electrons in the increasing order of energy in the sub-shells of an atom. Atomic number is equal to the number of electrons present in the atom of an element.

Answer to Problem 62A

Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for an element with atomic number 22 are

  ${ }_{22}Ti=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{2}4s^2$

  

and

  ${ }_{22}Ti=\left[Ar\right]3d^{2}4s^2$ respectively.

Explanation of Solution

The filling of electrons in the sub-shells follows Hund’s rule according to which lower energy orbitals are filled first followed by higher energy orbitals and Pauli’s exclusion principle according to which only two electrons will be present in an orbital and that too with opposite spin.

(c)

Interpretation Introduction

Interpretation: Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for the given elements is to be given.

Concept Introduction: Electronic configuration is the arrangement of electrons in the increasing order of energy in the sub-shells of an atom. Atomic number is equal to the number of electrons present in the atom of an element.

Answer to Problem 62A

Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for an element with atomic number 19 are

  ${}_{14}Si=1s^2 2s^2 2p^6 3s^{2}3p^2$

  

and

  ${}_{14}Si=\left[Ne\right]3s^{2}3p^2$ respectively.

Explanation of Solution

The filling of electrons in the sub-shells follows Hund’s rule according to which lower energy orbitals are filled first followed by higher energy orbitals and Pauli’s exclusion principle according to which only two electrons will be present in an orbital and that too with opposite spin.

(d)

Interpretation Introduction

Interpretation: Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for the given elements is to be given.

Concept Introduction: Electronic configuration is the arrangement of electrons in the increasing order of energy in the sub-shells of an atom. Atomic number is equal to the number of electrons present in the atom of an element.

Answer to Problem 62A

Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for an element with atomic number 26 are

  ${}_{26}Fe=1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2$

  

and

  ${}_{26}Fe=\left[Ar\right]3d^6 4s^2$ respectively.

Explanation of Solution

The filling of electrons in the sub-shells follows Hund’s rule according to which lower energy orbitals are filled first followed by higher energy orbitals and Pauli’s exclusion principle according to which only two electrons will be present in an orbital and that too with opposite spin.

(e)

Interpretation Introduction

Interpretation: Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for the given elements is to be given.

Concept Introduction: Electronic configuration is the arrangement of electrons in the increasing order of energy in the sub-shells of an atom. Atomic number is equal to the number of electrons present in the atom of an element.

Answer to Problem 62A

Full electronic configuration, orbital box diagram and the noble gas shorthand configuration for an element with atomic number 30 are

  ${}_{30}Zn=1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10}4s^2$

  

and

  ${}_{30}Zn=\left[Ar\right]3d^{10}4s^2$ respectively.

Explanation of Solution

The filling of electrons in the sub-shells follows Hund’s rule according to which lower energy orbitals are filled first followed by higher energy orbitals and Pauli’s exclusion principle according to which only two electrons will be present in an orbital and that too with opposite spin.