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(a)
Interpretation: Among the elements in a group (Li, C and O), the one which is expected to have highest ionization energy is to be given.
Concept Introduction: Ionization energy is defined as the minimum energy required to eject out the outermost electron from an isolated gaseous atom. Also it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy.
(a)
Explanation of Solution
O is the most electronegative among the given elements. Since, it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy. Thus, O has the highest ionization energy.
(b)
Interpretation: Among the elements in a group (Fr, Rb and Na), the one which is expected to have highest ionization energy is to be given.
Concept Introduction: Ionization energy is defined as the minimum energy required to eject out the outermost electron from an isolated gaseous atom. Also it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy.
(b)
Explanation of Solution
Na is the most electronegative among the given elements. Since, it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy. Thus, Na has the highest ionization energy.
(c)
Interpretation: Among the elements in a group (Ra, Ca and Mg), the one which is expected to have highest ionization energy is to be given.
Concept Introduction: Ionization energy is defined as the minimum energy required to eject out the outermost electron from an isolated gaseous atom. Also it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy.
(c)
Explanation of Solution
Mg is the most electronegative among the given elements. Since, it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy. Thus, Mg has the highest ionization energy.
(d)
Interpretation: Among the elements in a group (At, Br and F), the one which is expected to have highest ionization energy is to be given.
Concept Introduction: Ionization energy is defined as the minimum energy required to eject out the outermost electron from an isolated gaseous atom. Also it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy.
(d)
Explanation of Solution
F is the most electronegative among the given elements. Since, it is the most difficult to eject an electron from the atom of an element with most electronegative nature and so it will have the highest ionization energy. Thus, F has the highest ionization energy.
Chapter 11 Solutions
World of Chemistry
- For each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forwardThe following reaction is run in which the initial conditions include only methane (CH4) at a concentration of0.115 M. Once equilibrium was established, the concentration of acetylene (C2H2) was measured to be 0.035M. What is the value of the equilibrium constant, K?2 CH4 (g) ⇋ C2H2 (g) + 3 H2 (g)arrow_forwardCalculate the equilibrium concentration of carbon dioxide for the following reaction:2 COF2 (g) ⇋ CF4 (g) + CO2 (g) Kc = 2.00 at 10.00 °C. at equilibrium [COF2] = 0.255M; [CF4] = 0.118Marrow_forward
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- Indicate the compound resulting from adding NaOH cyclopentane-CH2-CHO.arrow_forwardUse the provided information to calculate Kc for the following reaction at 550 °C: H2(g) + CO2(g) ⇌ CO(g) + H2O(g) Kc = ?CoO(s) + CO(g) ⇌ Co(s) + CO2(g) Kc1 = 490CoO(s) + H2(g) ⇌ Co(s) + H2O(g) Kc2 = 67arrow_forwardCalculate Kc for the reaction: I2 (g) ⇋ 2 I (g) Kp = 6.26 x 10-22 at 298Karrow_forward
- For each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forwardTo convert cyclopentane-CH2-CHO to cyclopentane-CH2-CH3, compound A is added, followed by (CH3)3CO-K+, DMS at 100oC. Indicate which compound A is.arrow_forwardIndicate how to obtain the compound 2-Hydroxy-2-phenylacetonitrile from phenylmethanol.arrow_forward
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