Engineering Economic Analysis13th EditionDonald G. Newnan, Ted G. Eschenbach, Jerome P. Lavelle Publisher: Oxford University PressISBN: 9780190296902
Engineering Economic Analysis
Solutions for Engineering Economic Analysis
Browse All Chapters of This Textbook
Chapter 1 - Making Economics DecisionsChapter 2 - Estimating Engineering Costs And BenefitsChapter 3 - Interest And EquivalenceChapter 4 - Equivalence For Repeated Cash FlowsChapter 5 - Present Worth AnalysisChapter 6 - Annual Cash Flow AnalysisChapter 7 - Rate Or Return AnalysisChapter 7A - Difficulties In Solving For An Interest RateChapter 8 - Chossing The Best AlternativeChapter 9 - Other Analysis Techniques
Chapter 9A - Investing For Retirement And Other Future NeedsChapter 10 - Uncertainty In Future EventsChapter 10A - Diversification Reduces RiskChapter 11 - DepreciationChapter 12 - Income Taxes For CorporationsChapter 12A - Taxes And Personal Financial Decision MakingChapter 13 - Replacement AnalysisChapter 14 - Inflation And Price ChangeChapter 15 - Selection Of A Minimum Attractive Rate Of ReturnChapter 16 - Economic Analysis In The Public SectorChapter 17 - Accounting And Engineering EconomyChapter B - Time Value Of Money Calculations Using Spreadsheets And CalculatorsChapter D - Fundamentals Of Engineering (fe) Exam Practice Problems
Sample Solutions for this Textbook
We offer sample solutions for Engineering Economic Analysis homework problems. See examples below:
The marketplace dynamics which drive the developing of electric vehicles are: High demand for...Given information: Car mileage − 28 miles per gallon Local price of gasoline − $3.95/gallon Travel...Given information: Mileage at 60 mph − 24mpg Mileage at 70 mph − 20mpg Distance trip − 500 miles Gas...There are several general models and techniques to estimate costs and benefits which can be used to...Given information: Price charged by company = $6000/month Operating expenses = $600,000 per month...Given: Load on the machine is 30 hp. Electricity rates are as follows: First 50 kWh at 12.6 per kWh...Given information: Total Cost of System I = 0.90x+1.0 Total Cost of System II = 0.10x+5.0 Fixed cost...Given information: Charges per camper or price charged = $480 per week. Fixed costs = $192,000 per...Concept used: Total revenue refers to the total amount of money collected from the sale of goods and...
Given information: P = -0.25D + 250 P = unit sales price D = annual quantity demanded for the...Given information: Time required to produce 1st unit = 3500 manual labor hours Learning curve = 92%...Given information: Time required to install 1st unit = 75 hours Learning curve = 90% Learning Curve:...With the improvement in production process, the quality of product increases with less wastage and...Given: Loan Years Rate (a) $1000 2 5% (b) $1500 5 6% (c) $10,000 10 10% (d) $25,000 15 15% (e)...Given: Two different cash flows. $500 will be received today. $1000 will be received after 3 years....Given: Interest rate is 2.4%. Time period is 10 years. Calculation: Write the expression to...Given information: The nominal annual interest rate = 4% Compounded every three months Effective...Given information: The interest 238% compounded annually The interest 214% compounded quarterly The...Note that, sunk costs are those costs which cannot be recovered. The ISU panels were purchase by the...Given information: Using linear interpolation, values to be found for (F/A,11%,15) and (F/P,16%,25)....Given: Cash- flow moment-equation. Concept used: Cash-flow movement equation shows equilibrium from...Given: (A/F,i,n) = (A/P,i,n)−i. Calculation: The following relationship is required to be proved:...Given information: Maintenance cost for 1st year (A1) = $75 Cost will increase by $150 each year, so...Given information: Maintenance cost for 1st year (A1) = $85,000 Cost will increase by $150 each...Given information: Loan amount: $1,000 Duration: 12 Months Amount of monthly payment is $ 93.12....Given information: Loan amount: $5,000 Interest rate: 12% per annum, compounded semi-annually. Loan...Given information: Loan Amount - $900 Time period − 1 years Rate of Interest − 6% per annum Capital...Given information: Loan Amount - $900 Time period − 1 years Rate of Interest − 4-14% per annum...Given information: Loan Amount - $15,000 Time period − 36 months & 60 months. Rate of Interest −...Given: Retirement period from now: 40 years Amount required: $ 2 M Interest Rate = 10%. Calculation:...The money is well utilized by the Canada. They can now generate 2730-megawatt electricity and can...Given information: Installation Costs in Year 0: Foxhill Instrument $35,000 Quicksilver $40,000...Given information: Option 1: Install one cable now for 4000 lines. Installation cost $20,000 and...Given information: (all costs in $Million) Installation Cost: Suspension Bridge $585 Cantilever...Given information: Initial Cost: Labor Intensive Process $0 Automated Process $55,000 Installation...Given: Interest Rate is 6% A B C Installed Cost $10,000 $15,000 $20,000 Annual Benefit 1,625 1,530...Given: Interest Rate = 8%. Concept used: RATE OF RETURN: It is a return which usually an investor...Given information: Minimum rate of return = 10%. Six stocks are available. Calculate the ratio of PW...Given information: Installation Cost: Flat Solar Panels$87 Million Mechanized Solar Panels $101...Given information: Option A: Receive $2,000 per month from age 66 − 85 i.e. 19 Years Option B:...The reason for using family size and lifestyle for calculating average is necessary because we...Given: Vehicle down payment is $2200. Vehicle payments is $5500 for period 1−4. Prepaid insurance...Given: Number of barrels of ethanol to be sold per year is 150000. The time period is 10 years...Given for Route 105: Cost is $500000, annual saving is $100000 and useful life is 6 year....Given for alternative A : Cost is $10000. Annual benefit is $1000. Useful life is infinite years....Given: Cost & Details Machine A Machine B Initial cost of machine $15000 $25000 Annual...Given: The cost of machine A is $12500. The salvage value after 3 years is $2000. The maintenance...The cars average distance covered by car is 80000 km a year and interest is 6%. Calculation:...Given: The cost of land is $3.2 M. The cost of building is $4.8 M. The annual operating and...Given information: A clothing manufacturer is considering using RFID tags to track all the new...Given: Time: 10 years Alternative A has a cost of $10000 Annual benefits of $4500 Alternative B...Given: Purchase Price: $ 380000 Time: 6 years Salvage value is 15% of the first cost Leased for...Given: The loan amount is $18000. The time period is 60 months. The interest rate is 9%. Concept...Given: The amount is $220,000. Time period is 30 years. Loan origination fees is 3%. Concept used:...Given information: Year Cash Flow 0 -$1000 1 3400 2 -5700 3 3800 The formula for Rate of return =...Given information: In this case, B purchased a vacation lot by making a down payment of $9000 and...No, while choosing between the rigid pavement or flexible pavement the transport agency should they...Given information: Interest Rate is from 0% to 100%. Year A B 0 ($10,000) ($15,000) 1--5 3200 4500...Given: Annual Profit = $370000 Leasing Period = 5 years Expenditure on store fixtures = $1200000...Given: Cost of resurfacing a road = $1.5 M Annual Maintenance = $120K Time period = 10 years....Given: Deluxe Regular Economy First Cost $220,000 $125,000 $75,000 Useful Life 5 6 7 Salvage Value...Given: Availability of Magazine for $58 for 1 year Availability of Magazine for $108 for 2 year...Green buildings are those which have better access to natural light, efficient heating-ventilating...Given: Cost of land is $100000 and the interest rate is 8%. Concept used: Write the expression for...Given: A B User benefits ($M/yr) 2.1 2.6 User dis-benefits ($M/yr) 1.2 2.1 First cost ($M) 6.9 9.9...Given: MARR is 8% Useful life is 20 years. Calculation: Write the expression to calculate the...Write the Equation for Payback period. Payback period=CostAnnual Benefit ...... (I) Calculate the...Calculation: Write the equation for Payback period. Payback period=CostAnnual Benefit ...... (I)...Calculations: The table for cash flow and cumulative cash flow for project E is shown below. Year...Given: B’s first cost is $1200. Concept used: Write the expression to calculate the equivalent...Given: For alternative A: The initial cost is $8900. The resale value is $1700. The operation cost...Given: The cost saving percentage per vehicle minute for autos is $0.0375. The cost saving...Given: Annual income is $65000. Number of year is 30. Future Value is $2000000. Calculation: Write...Given: Salary is $60000. Interest rate for stock fund is 7.3%. Calculation: Make the table for cash...There are some methods to quantify the uncertainty in a specific software development effort and are...Given: Purchasing cost of used pickup is $14000. Fuel cost is $1500 per year. The drop of salvage...Given: The first cost is $150000. The salvage value is zero. The interest rate is 20%. Calculations:...Given: If optimistic growth is used in a city, then expansion will be needed in 4 years and it’s...Given: Optimistic probability is 20%, most likely probability is 50% and pessimistic probability is...Given: The present worth of optimistic projection is $94,125. The present worth of most-likely...Given: Cost of robot = $81000 Probability for optimistic annual savings of $22000 is 0.1 Probability...Given: The compound amount in future is $2000000. The time period is 30 years. The earning of...Given: The compound amount in future is $2000000. The time period is 35 years. The earning of...Intangible Assets: are the assets that are not tangible i.e these are not physical in nature....Given: The cost basis of the asset is $20,000. Concept used: MACRS is known as modified accelerated...Given: Cost of the printing machine is $25,000. Time period is 7 years. Concept used: Write the...Given: The cost of the capsulating machine is $76,000. Time period is 5 years. Concept used: Write...Given: Cost of the handling device is $20,000. Time period is 5 years. Salvage value is $2,000....Given: Cost of the crystal extraction device is $50,000. Time period is 8 years. Salvage value is...Given: Cost of machine = $200000 Useful Life = 10 years. Calculation: A 10-year property class with...Given: Useful Life = 5 years Cost of asset = $85000 Salvage Value = $15000 ADR life = 8 years....The Production Tax Credit (PTC) is defined as a federal incentive which provides financial support...Given: Annual receipts is $650000. Annual disbursements is $225000. Total asset value is of...Given: The cost of installing a machine is $200,000. The useful life is 20 years. Salvage value is...Concept used: Write the expression for depreciation. D=2n×BVt−1 ......(I) Here, book value is BV and...Given data: Investing amount is $18,000. Estimate gross income is $4500. Increment per year is $500....Given: Combined tax rate is 40%. Initial cost is $2M. Annual receipt is $650000. Annual...Given: After-tax minimum attractive rate of return is 12%. Combined incremental income tax rate is...Given: The after-tax MARR is 25%. The project life is 5 years. The combined incremental tax rate is...Given: The taxable income is $150,000. After tax MARR is 15%. The selling price is 25% of the...Given: Taxable income is $5000. Concept used: Tax slab rates for single taxpayers are as follows....Given: The after tax income of household is $120,000. The monthly expenses of the family are as...Given: The purchase price of the house is $170000. The down payment required is 5%. The insurance is...Given: The purchase price of the house is $260000. The down payment required is 10%. The insurance...Deficient bridge: Structurally deficient means that there are certain elements of the bridge that...Given: The first cost is $50000. Decline in its value per annum is 20%. Operating and maintenance...Given: The annual cost of new car is $22000. The depreciation rate for new as well as old car is...Given: The interest rate is 10%. Concept used: The minimum cost of life is where the equivalent...Calculate the net present value of old truck. Year Cost of maintenance(A) Tax saving (B)(A×0.4)...Given for Machine A : Cost of machine A is $54000. The overhauled cost of Machine A is $9000. Life...Alternative A : Calculate the present value for alternative A. Year Operating expense after tax(A)...In spite of inflation increasing more prices, the price of solar power is declining. Also, in...Concept used: Write the expression for annual percentage increase in nth year. (Annual % increase in...Given: The increase in the price after 12 year is 55%. Further increase in price for 8 year is 25%....Given: Initial Amount is $10000. Interest per year is $3.5%. The MARR is 28%. Inflation rate is 2%....Given: Purchase amount is $10000. MACRS 5 year depreciation. Net Benefit is $2500 at the end of year...Given: Net annual income to the owner is 10.5% of the market value. Purchase amount of the property...Given: The first cost is $18,000. The maintenance cost per year is $1300. The salvage value is...Given: Cost of land is $17,500. Cost of the house is $67,500. Net income is $8000. Calculation:...Calculation: Alternative 1: Continue to rent the duplex home. Determine the payment for year 1....Given: Year A B 0 −$420 −$300 1 $200 $150 2 $200 $150 3 $200 $150 MARR is 8%. Combined income tax...Tajikistan, is a small country in Central Asia, this country is heavily dependent upon hydropower...Given: Project First cost Annual benefits Life(years) 1 $200,000 $50,000 15 2 $300,000 $70000 10 3...Given: Project First cost Annual benefits Life (years) A $150,000 $44,290 5 B $200,000 $61,730 5 C...Given: Project First cost Annual benefits Salvage Value Life(years) 1 $20,000 $4,000 20 2 $20,000...There are certain situations when we have to address such a topic to such an audience which is...Given: The annual benefit is $500000. The annual disbenefit is $25000. The first cost is $1500000....Given: The table for data given is shown below. Year Cash flow A Cash flows B 0 $300 $450 1−15(A1)...Given: Interest rate is 8%. Project life is 30 years. Concept used: Write the expression to...Given: The MARR is 15%. Concept used: Net present worth is the difference between the net present...Given: Decades of Focus First Second Third Fourth Fifth Annual benefits (In thousands of dollars)...A basic knowledge of accounting and finance is required for each and every person. Since every field...Calculation: Make the balance sheet and categorise as asset or liabilities. Item Amount Location on...Calculation: Calculate the total revenue. Total Revenue=(Operating Revenue)+(Non Operating Revenue)...Given: Production is, 5000. The number of run required are 1500 machines hours, three set ups of the...Given: Cost of machinery is $70,000. Savings are $18,000 annually. Salvage value is $12,500....Engineering economic analysis is analyzing the economy and its effect on the engineering. How our...Given: Total book lot is 160. Number of semester is 4. Textbook cost for producer is $25 per book....Given: Total book lot is, 160. Number of semester is, 4. Textbook cost for producer is, $25....Given: Cost of the product is $120,000. Salvage value is $10,000. Time period is 10 years. Annual...Given: The interest rate is 15%. A company considering two alternatives Alternative I Alternative II...Given data: Cost of the tank is $150,000. Salvage value is $7,500. Time period is 10 years. Annual...Given: Year Alternative I Alternative II 0 −$1000 −$3000 1 100 500 2 100 550 3 100 600 4 200 650 5...Given: Face value is $10,000. Bond interest rate is 4%. Maturity time is 7 years. Bond is bold at...Concept used: Write the expression for present worth of cost. PWC=−C+AO[( 1+i)n−1i( 1+i)n] .........Given: First cost is $350,000. Cost of the operation is $45,000. Salvage value is $15,000. Project...Given: Data Line 1 Line 2 Line 3 Line 3 Annual production 4000 3500 9800 675 Cost of direct...
More Editions of This Book
Corresponding editions of this textbook are also available below:
ENGINEERING ECO ALANYSIS W/STUDY GUIDE
14th Edition
ISBN: 9780190072537
ENGINEERING ECONOMIC ENHANCED EBOOK
14th Edition
ISBN: 9780190931940
ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN: 9780190931919
ENGR.ECONOMIC ANALYSIS W/DASHBOARD
14th Edition
ISBN: 9780190063467
Engineering Economic Analysis
14th Edition
ISBN: 9780190931988
ECONOMIC ANALYSIS- LOOSELEAF
14th Edition
ISBN: 9780190932015
Engineering Economic Analysis
12th Edition
ISBN: 9780199339358
ENGR.ECONOMIC ANALYSIS-W/CD+STD.GDE.
12th Edition
ISBN: 9780199364497
Engineering Economic Analysis, Study Guide
12th Edition
ISBN: 9780199339341
EBK ENGINEERING ECONOMIC ANALYSIS
12th Edition
ISBN: 8220101278609
Engineering Economic Analysis
12th Edition
ISBN: 9780199339273
Engr.economic Analysis-text
12th Edition
ISBN: 9780199370191
Engineering Economic Analysis (Custom Edition for Professor Khokiat Kengskool, Florida International University) w/Formula and Interest Tables, Understanding Engineering Economy-A Practical Approach
12th Edition
ISBN: 9780190654450
ENGR.ECONOMIC ANALYSIS-W/CD
10th Edition
ISBN: 9780195335415
ENGINEERING ECO ANALYSIS W/STUDY GUIDE
13th Edition
ISBN: 9780190693053
Study Guide for Engineering Economic Analysis
13th Edition
ISBN: 9780190297022
ENG. ECONOMIC ANALYSIS (LOOSELEAF)
13th Edition
ISBN: 9780190647537
Engr.economic Analysis-w/cd
9th Edition
ISBN: 9780006440598
Engineering Economic Analysis
11th Edition
ISBN: 9780199778041
Engr.economic Analysis-w/cd+st
11th Edition
ISBN: 9780199836765
Engineering Economic Analysis
11th Edition
ISBN: 9780199778126
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