Engineering Economic Analysis
Engineering Economic Analysis
13th Edition
ISBN: 9780190296902
Author: Donald G. Newnan, Ted G. Eschenbach, Jerome P. Lavelle
Publisher: Oxford University Press
Question
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Chapter 10A, Problem 2P
To determine

(a)

The annual investment.

Expert Solution
Check Mark

Answer to Problem 2P

The annual investment is $12133.84.

Explanation of Solution

Given:

The compound amount in future is $2000000.

The time period is 35years.

The earning of engineer is $68000 per year.

Concept used:

Write the expression for annual investment.

A=F[i(1+i)n1] ...... (I)

Here, the compound amount in future is F, the interest rate is i and time period is n.

Calculations:

As per the table of return data for capital allocation line, the interest rate is 7.8% for portfolio of 20% of T-bills, 40% stocks and 40% bonds.

Calculate the annual investment.

Substitute $2000000 for F, 7.8% for i and 35 for n in Equation (I).

A=$2000000[0.078(1+0.078)351]=$2000000[0.078(1.078)351]=$2000000(0.00606)=$12133.84.

Conclusion:

Thus, the annual investment is $12133.84.

To determine

(b)

The annual investment.

Expert Solution
Check Mark

Answer to Problem 2P

The annual investment is $8136.83.

Explanation of Solution

Given:

The compound amount in future is $2000000.

The time period is 40years.

The earning of engineer is $68000 per year.

Calculations:

Calculate the annual investment.

Substitute $2000000 for F, 7.8% for i and 40 for n in Equation (I).

A=$2000000[0.078(1+0.078)401]=$2000000[0.078(1.078)401]=$2000000(0.004068)=$8136.83.

Conclusion:

Thus, the annual investment is $8136.83.

To determine

(c)

The investment per year by the employee and the employer.

Expert Solution
Check Mark

Answer to Problem 2P

The investment by employer is $2720 per year.

The investment by employee is $9413.84 per year.

Explanation of Solution

Given:

The compound amount in future is $2000000.

The time period is 35years.

The earning of engineer is $68000 per year.

4% of the salary is contributed each year to the retirement savings.

Calculations:

Calculate the annual investment.

Substitute $2000000 for F, 7.8% for i and 35 for n in Equation (I).

A=$2000000[0.078(1+0.078)351]=$2000000[0.078(1.078)351]=$2000000(0.00606)=$12133.84

The annual investment is $12133.84.

Calculate amount to be investment by the employer.

A=$68000×4%=$68000×4100=$2720

The amount to be investment by employer is $2720 per year.

Calculate the amount to be investment by employee.

Ai=$12133.84$2720=$9413.84

The amount to be investment by employee is $9413.84 per year.

Conclusion:

Thus, the amount to be invested by the employer is $2720 per year.

The amount to be invested by the employee is $9413.84 per year.

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