Solutions for ENGR.ECONOMIC ANALYSIS W/DASHBOARD
Browse All Chapters of This Textbook
Chapter 1 - Making Economics DecisionsChapter 2 - Estimating Engineering Costs And BenefitsChapter 3 - Interest And EquivalenceChapter 4 - Equivalence For Repeated Cash FlowsChapter 5 - Present Worth AnalysisChapter 6 - Annual Cash Flow AnalysisChapter 7 - Rate Or Return AnalysisChapter 7A - Difficulties In Solving For An Interest RateChapter 8 - Chossing The Best AlternativeChapter 9 - Other Analysis Techniques
Chapter 9A - Investing For Retirement And Other Future NeedsChapter 10 - Uncertainty In Future EventsChapter 10A - Diversification Reduces RiskChapter 11 - DepreciationChapter 12 - Income Taxes For CorporationsChapter 12A - Taxes And Personal Financial Decision MakingChapter 13 - Economic Life And Replacement AnalysisChapter 14 - Inflation And Price ChangeChapter 15 - Selection Of A Minimum Attractive Rate Of ReturnChapter 16 - Economic Analysis In The Public SectorChapter 17 - Accounting And Engineering EconomyChapter B - Time Value Of Money Calculations Using Spreadsheets And CalculatorsChapter D - Fundamentals Of Engineering (fe) Exam Practice Problems
Sample Solutions for this Textbook
We offer sample solutions for ENGR.ECONOMIC ANALYSIS W/DASHBOARD homework problems. See examples below:
When a restaurant uses third-party services, it may face some operational issues. Some of these...The driver has three options to pick given that local price is $3.5 per gallon and the car has a...To determine the optimum level of speed at which 525miles trip will be done, we need to compare the...There are several general models and techniques to estimate costs and benefits which can be used to...Given information: Price charged by company = $6000/month Operating expenses = $600,000 per month...Given: Load on the machine is 30 hp. Electricity rates are as follows: First 50 kWh at 12.6 per kWh...Given information: Total Cost of System I = 0.90x+1.0 Total Cost of System II = 0.10x+5.0 Fixed cost...Given information: Charges per camper or price charged = $480 per week. Fixed costs = $192,000 per...Concept used: Total revenue refers to the total amount of money collected from the sale of goods and...
Given information: P = -0.25D + 250 P = unit sales price D = annual quantity demanded for the...Given information: Time required to produce 1st unit = 3500 manual labor hours Learning curve = 92%...Given information: Time required to install 1st unit = 75 hours Learning curve = 90% Learning Curve:...With the improvement in production process, the quality of product increases with less wastage and...Given: Loan Years Rate (a) $1000 2 5% (b) $1500 5 6% (c) $10,000 10 10% (d) $25,000 15 15% (e)...Given: Two different cash flows. $500 will be received today. $1000 will be received after 3 years....FV = PV (1+r) n 160 = 150 (1+r) 1 160 150 = (1+r) 1 1.0666 = (1+r) 1 Next, the first square root of...FV = PV (1+r) n 2600 = 2000 (1+r) 2 2600 2000 = (1+r) 2 1.3 = (1+r) 2 The next step is to calculate...Given information: The nominal annual interest rate = 4% Compounded every three months Effective...Note that, sunk costs are those costs which cannot be recovered. The ISU panels were purchase by the...Given information: Using linear interpolation, values to be found for (F/A,11%,15) and (F/P,16%,25)....Given: Cash- flow moment-equation. Concept used: Cash-flow movement equation shows equilibrium from...Given: (A/F,i,n) = (A/P,i,n)−i. Calculation: The following relationship is required to be proved:...Given information: Maintenance cost for 1st year (A1) = $75 Cost will increase by $150 each year, so...Given information: Loan amount: $1,000 Duration: 12 Months Amount of monthly payment is $ 93.12....Given information: Loan amount: $5,000 Interest rate: 12% per annum, compounded semi-annually. Loan...Given information: Loan Amount - $900 Time period − 1 years Rate of Interest − 6% per annum Capital...Given information: Loan Amount - $900 Time period − 1 years Rate of Interest − 4-14% per annum...Given information: Loan Amount - $15,000 Time period − 36 months & 60 months. Rate of Interest −...Given: Retirement period from now: 40 years Amount required: $ 2 M Interest Rate = 10%. Calculation:...The money is well utilized by the Canada. They can now generate 2730-megawatt electricity and can...Given information: Option 1: Install one cable now for 4000 lines. Installation cost $20,000 and...Given information: (all costs in $Million) Installation Cost: Suspension Bridge $585 Cantilever...Given information: LaborintensiveSystemAutomatedSystemInitial cost$0$110,000Installation...Given information: First CostO & M Cost/yearSalvageLifeA$14M$3.5M$2M8 yearsB22M3M7.5M16 years...Given: Interest Rate is 6% A B C Installed Cost $10,000 $15,000 $20,000 Annual Benefit 1,625 1,530...Given information: Minimum rate of return = 10%. Six stocks are available. Calculate the ratio of PW...Given information: Installation Cost: Flat Solar Panels$87 Million Mechanized Solar Panels $101...Given information: Option A: Receive $2,000 per month from age 66 − 85 i.e. 19 Years Option B:...The reason for using family size and lifestyle for calculating average is necessary because we...Given: Vehicle down payment is $2200. Vehicle payments is $5500 for period 1−4. Prepaid insurance...Given: Number of barrels of ethanol to be sold per year is 150000. The time period is 10 years...The cars average distance covered by car is 80000 km a year. The interest is 6%. Calculation:...Given: Cost & Details Machine A Machine B Initial cost of machine $15000 $25000 Annual...Given: The cost of machine A is $12500. The salvage value after 3 years is $2000. The maintenance...Given: Initial cost of the land is $3.4 M. Annual operation and maintenance cost is $25000 for 20...The cars average distance covered by car is 80000 km a year and interest is 6%. Calculation:...Given: The cost of land is $3.2 M. The cost of building is $4.8 M. The annual operating and...The impact of general public over the technological advancement is as follows: As the crimes...Given: Time: 10 years Alternative A has a cost of $10000 Annual benefits of $4500 Alternative B...Given: The loan amount is $18000. The time period is 60 months. The interest rate is 9%. Concept...Given: The amount is $220,000. Time period is 30 years. Loan origination fees is 3%. Concept used:...Given information: Year Cash Flow 0 -$1000 1 3400 2 -5700 3 3800 The formula for Rate of return =...Given information: In this case, B purchased a vacation lot by making a down payment of $9000 and...No, while choosing between the rigid pavement or flexible pavement the transport agency should they...Given information: Interest Rate is from 0% to 100%. Year A B 0 ($10,000) ($15,000) 1--5 3200 4500...NPV of South end =$285,000(P/A,i,5) NPV of South & North end...NPV of Alternative A =[450−800(A/P,i,2)](P/A,i,8) NPV of Alternative B...NPV of Alternative A =−2,500+850(P/A,i,5)+2,500(P/F,i,5) NPV of Alternative B...NPV of Plan A =−83,000−50,000+26,500(P/A,i,15)+50,000(P/F,i,15) NPV of Plan B...Reusing space rocket such as SpaceX can benefits the producer in substantially reducing the cost....Given: MARR is 10%. Useful life is 5 years. Calculation: Write the expression to calculate the...Given: MARR is 12%. Useful life is 15 years. Calculation: Write the expression to calculate the...Given: A B User benefits ($M/yr) 2.1 2.6 User dis-benefits ($M/yr) 1.2 2.1 First cost ($M) 6.9 9.9...Calculation: Write the equation for Payback period. Payback period=CostAnnual Benefit ...... (I)...Calculations: The table for cash flow and cumulative cash flow for project E is shown below. Year...Given: B’s first cost is $1200. Concept used: Write the expression to calculate the equivalent...Given: For alternative A: The initial cost is $8900. The resale value is $1700. The operation cost...Given: The cost saving percentage per vehicle minute for autos is $0.0375. The cost saving...Given: Annual income is $65000. Number of year is 30. Future Value is $2000000. Calculation: Write...He puts 4% percent of his salary into her new account and her employer will put 3% of her salary to...In crowdshipping, the courier closest to the delivery point is selected for the shipment. There are...Calculation: Calculate the joint probability. Net Revenue (a) Probability (b) First cost (c)...Calculation: Calculate the joint probability. Savings per year (a) Probability (b) Useful life...Given: The present worth of optimistic projection is $94,125. The present worth of most-likely...Given: $300,000 of damage occurs. The rate of return is 12%. Concept used: Write the expression for...Given: Useful Life = 10 year Interest Rate = 12%. Calculation: First Costs Probability Net Revenues...Given: Cost of robot = $81000 Probability for optimistic annual savings of $22000 is 0.1 Probability...Given: The compound amount in future is $2000000. The time period is 30 years. The earning of...Intangible Assets: are the assets that are not tangible i.e these are not physical in nature....Given: The cost basis of the asset is $20,000. Concept used: MACRS is known as modified accelerated...Given: Cost of the small motorboat is $35,000. Time period is 5 years. Concept used: Write the...Given: The cost of the capsulating machine is $76,000. Time period is 5 years. Concept used: Write...Given: Cost of the handling device is $20,000. Time period is 5 years. Salvage value is $2,000....Given: Cost of the crystal extraction device is $50,000. Time period is 8 years. Salvage value is...Given: Cost of machine = $200000 Useful Life = 10 years. Calculation: A 10-year property class with...Income tax is the amount paid as a tax to the federal government or state government levied every...Given: Capacity of each carton is 100 bags. Average quantity of bags in each carton is 105.5. The...Given: The cost of installing a machine is $200,000. The useful life is 20 years. Salvage value is...Concept used: Write the expression for depreciation. D=2n×BVt−1 ....... (I) Here, book value is BV...Concept used: Write the expression to calculate the depreciation by double declining method....Given data: Investing amount is $18,000. Estimate gross income is $4500. Increment per year is $500....Given: Cost of the barge is $13.2 million. Expected income from the barge is $7.5 million for the...Given: Taxable income is $5000. Concept used: Tax slab rates for single taxpayers are as follows....Given: The after tax income of household is $120,000. The monthly expenses of the family are as...Given: The purchase price of the house is $170000. The down payment required is 5%. The insurance is...Deficient bridge: Structurally deficient means that there are certain elements of the bridge that...Given: Machine first cost is $1,050,000 and the salvage value for machine is $225,000. Maintenance...First cost of machine = $24,000 Market value declines = 20% Firm’s MARR = 12% Market value =...Upgrade option Cost of upgrade = $12,000, i = 15%, n = 9 years EUAC of upgrade option=Cost×(...Calculate the net present value of old truck. Year Cost of maintenance(A) Tax saving (B)(A×0.4)...Old asset Annual depreciation =Total cost−Salvage ValueYears=50000−1500010= $3,500 Book Value as at...Alternative A : Calculate the present value for alternative A. Year Operating expense after tax(A)...In spite of inflation increasing more prices, the price of solar power is declining. Also, in...Given: The salary in year 1 is $60000. The annual raise is 5%. The inflation rate is 3%. Concept...Concept used: Write the expression for annual percentage increase in nth year. (Annual % increase in...Given: The increase in the price after 12 year is 55%. Further increase in price for 8 year is 25%....Given: Initial Amount is $10000. Interest per year is $3.5%. The MARR is 28%. Inflation rate is 2%....Given: Purchase amount is $10000. MACRS 5 year depreciation. Net Benefit is $2500 at the end of year...Given: Net annual income to the owner is 10.5% of the market value. Purchase amount of the property...Calculation: Alternative 1: Continue to rent the duplex home. Determine the payment for year 1....Given: Year A B 0 −$420 −$300 1 $200 $150 2 $200 $150 3 $200 $150 MARR is 8%. Combined income tax...Tajikistan, is a small country in Central Asia, this country is heavily dependent upon hydropower...Given: Project First cost Annual benefits Life(years) 1 $200,000 $50,000 15 2 $300,000 $70000 10 3...Given: Project First cost Annual benefits Salvage Value Life(years) 1 $20,000 $4,000 20 2 $20,000...Given: Salvage Value is 0. Duration is 5 years. Calculation: Write the expression to calculate the...There are certain situations when we have to address such a topic to such an audience which is...Given: The annual benefit is $500000. The annual disbenefit is $25000. The first cost is $1500000....Given: The table for data given is shown below. Year Cash flow A Cash flows B 0 $300 $450 1−15(A1)...Given: The table for given data is shown below. Year Particulars Full capacity tunnel Half capacity...Given: The MARR is 15%. Concept used: Net present worth is the difference between the net present...Calculations: Calculate the difference between cash flows A and cash flow B. Year Cash flow A Cash...A basic knowledge of accounting and finance is required for each and every person. Since every field...Calculation: Make the balance sheet and categorise as asset or liabilities. Item Amount Location on...Calculation: Calculate the total revenue. Total Revenue=(Operating Revenue)+(Non Operating Revenue)...Given: Production is, 5000. The number of run required are 1500 machines hours, three set ups of the...Given: Cost of machinery is $70,000. Savings are $18,000 annually. Salvage value is $12,500....Engineering economic analysis is analyzing the economy and its effect on the engineering. How our...Given: Cost of the product is $120,000. Salvage value is $10,000. Time period is 10 years. Annual...Given: The interest rate is 15%. A company considering two alternatives Alternative I Alternative II...Given data: Cost of the tank is $150,000. Salvage value is $7,500. Time period is 10 years. Annual...Given: Year Alternative I Alternative II 0 −$1000 −$3000 1 100 500 2 100 550 3 100 600 4 200 650 5...Given: Face value is $10,000. Bond interest rate is 4%. Maturity time is 7 years. Bond is bold at...Concept used: Write the expression for present worth of cost. PWC=−C+AO[( 1+i)n−1i( 1+i)n] .........Given: First cost is $350,000. Cost of the operation is $45,000. Salvage value is $15,000. Project...Given: Data Line 1 Line 2 Line 3 Line 3 Annual production 4000 3500 9800 675 Cost of direct...
More Editions of This Book
Corresponding editions of this textbook are also available below:
ENGINEERING ECO ALANYSIS W/STUDY GUIDE
14th Edition
ISBN: 9780190072537
ENGINEERING ECONOMIC ENHANCED EBOOK
14th Edition
ISBN: 9780190931940
ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN: 9780190931919
Engineering Economic Analysis
14th Edition
ISBN: 9780190931988
ECONOMIC ANALYSIS- LOOSELEAF
14th Edition
ISBN: 9780190932015
Engineering Economic Analysis
12th Edition
ISBN: 9780199339358
ENGR.ECONOMIC ANALYSIS-W/CD+STD.GDE.
12th Edition
ISBN: 9780199364497
Engineering Economic Analysis, Study Guide
12th Edition
ISBN: 9780199339341
EBK ENGINEERING ECONOMIC ANALYSIS
12th Edition
ISBN: 8220101278609
Engineering Economic Analysis
12th Edition
ISBN: 9780199339273
Engr.economic Analysis-text
12th Edition
ISBN: 9780199370191
Engineering Economic Analysis (Custom Edition for Professor Khokiat Kengskool, Florida International University) w/Formula and Interest Tables, Understanding Engineering Economy-A Practical Approach
12th Edition
ISBN: 9780190654450
ENGR.ECONOMIC ANALYSIS-W/CD
10th Edition
ISBN: 9780195335415
ENGINEERING ECO ANALYSIS W/STUDY GUIDE
13th Edition
ISBN: 9780190693053
Engineering Economic Analysis
13th Edition
ISBN: 9780190296902
Study Guide for Engineering Economic Analysis
13th Edition
ISBN: 9780190297022
ENG. ECONOMIC ANALYSIS (LOOSELEAF)
13th Edition
ISBN: 9780190647537
Engr.economic Analysis-w/cd
9th Edition
ISBN: 9780006440598
Engineering Economic Analysis
11th Edition
ISBN: 9780199778041
Engr.economic Analysis-w/cd+st
11th Edition
ISBN: 9780199836765
Engineering Economic Analysis
11th Edition
ISBN: 9780199778126
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