ELEMENTARY STATISTICS-ALEKS ACCESS CODE - 3rd Edition - by Navidi - ISBN 9781265787219

ELEMENTARY STATISTICS-ALEKS ACCESS CODE
3rd Edition
Navidi
Publisher: MCG
ISBN: 9781265787219

Solutions for ELEMENTARY STATISTICS-ALEKS ACCESS CODE

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Chapter 3 - Numerical Summaries Of DataChapter 3.1 - Measures Of CenterChapter 3.2 - Measures Of SpreadChapter 3.3 - Measures Of PositionChapter 4 - Summarizing Bivariate DataChapter 4.1 - CorrelationChapter 4.2 - The Least-squares Regression LineChapter 4.3 - Features And Limitations Of The Least-squares Regression LineChapter 5 - ProbabilityChapter 5.1 - Basic Concepts Of ProbabilityChapter 5.2 - The Addition Rule And The Rule Of ComplementsChapter 5.3 - Conditional Probability And The Multiplication RuleChapter 5.4 - CountingChapter 6 - Discrete Probability DistributionsChapter 6.1 - Random VariablesChapter 6.2 - The Binomial DistributionChapter 6.3 - The Poisson DistributionChapter 7 - The Normal DistributionChapter 7.1 - The Standard Normal CurveChapter 7.2 - Applications Of The Normal DistributionChapter 7.3 - Sampling Distributions And The Central Limit TheoremChapter 7.4 - The Central Limit Theorem For ProportionsChapter 7.5 - The Normal Approximation To The Binomial DistributionChapter 7.6 - Assessing NormalityChapter 8 - Confidence IntervalsChapter 8.1 - Confidence Intervals For A Population Mean, Standard Deviation KnownChapter 8.2 - Confidence Intervals For A Population Mean, Standard DeviationChapter 8.3 - Confidence Intervals For A Population ProportionChapter 8.4 - Confidence Intervals For A Standard DeviationChapter 8.5 - Determining Which Method To UseChapter 9 - Hypothesis TestingChapter 9.1 - Basic Principles Of Hypothesis TestingChapter 9.2 - Hypothesis Tests For A Population Mean, Standard Deviation KnownChapter 9.3 - Hypothesis Tests For A Population Mean, Standard Deviation UnknownChapter 9.4 - Hypothesis Tests For ProportionsChapter 9.5 - Hypothesis Tests For A Standard DeviationChapter 9.6 - Determining Which Method To UseChapter 9.7 - PowerChapter 10 - Two-sample Confidence IntervalsChapter 10.1 - Confidence Intervals For The Difference Between Two Means: Independent SamplesChapter 10.2 - Confidence Intervals For The Difference Between Two ProportionsChapter 10.3 - Confidence Intervals For The Difference Between Two Means: Paired SamplesChapter 11 - Two-sample Hypothesis TestsChapter 11.1 - Hypothesis Tests For The Difference Between Two Means: Independent SamplesChapter 11.2 - Hypothesis Tests For The Difference Between Two ProportionsChapter 11.3 - Hypothesis Tests For The Difference Between Two Means: Paired SamplesChapter 11.4 - Hypothesis Tests For Two Population Standard DeviationsChapter 11.5 - The Multiple Testing ProblemChapter 12 - Tests With Qualitative DataChapter 12.1 - Testing Goodness Of FitChapter 12.2 - Tests For Independence And HomogeneityChapter 13 - Inference In Linear ModelsChapter 13.1 - Inference On The Slope Of The Regression LineChapter 13.2 - Inference About The ResponseChapter 13.3 - Multiple RegressionChapter 14 - Analysis Of VarianceChapter 14.1 - One-way Analysis Of VarianceChapter 14.2 - Two-way Analysis Of VarianceChapter 15 - Nonparametric StatisticsChapter 15.1 - The Sign TestChapter 15.2 - The Rank-sum TestChapter 15.3 - The Signed-rank Test

Sample Solutions for this Textbook

We offer sample solutions for ELEMENTARY STATISTICS-ALEKS ACCESS CODE homework problems. See examples below:

Chapter 2.2, Problem 32EChapter 2.2, Problem 33EChapter 2.2, Problem 44EChapter 2.3, Problem 17EChapter 2.3, Problem 22EChapter 2.3, Problem 27EChapter 2, Problem 1CQChapter 2, Problem 6REChapter 2, Problem 7RECalculation: To construct the stem-and-leaf plot, the data needs to be sorted. The sorted data is...Chapter 2, Problem 9CSGiven: 18,10,47,22,52,13,38,23,40,16,20,76,46,14,19,20 Formula Used: Mean(x¯)=∑ x i nMedian={ ( n+1...Given:...Chapter 3.1, Problem 43EGiven:...Chapter 3.1, Problem 45EChapter 3.1, Problem 46EChapter 3.1, Problem 47EChapter 3.2, Problem 38EChapter 3.2, Problem 39EChapter 3.2, Problem 40EChapter 3.2, Problem 41EFormula: Mean: x¯=∑i=1nXin Population standard deviation: σ=∑ ( x i − x ¯ ) 2 n Calculation: Stocks:...Chapter 3.3, Problem 31EFormula: First quartile Q1: Q1=14(n+1)th value Third quartile Q3: Q3=34(n+1)th value Calculation:...Formula: First quartile Q1: Q1=14(n+1)th value Third quartile Q3: Q3=34(n+1)th value Calculation:...Formula: Median: Median=( n+12)thvalue First quartile Q1: Q1=14(n+1)th value Third quartile Q3:...Chapter 3, Problem 1CQGiven table:...May: First need to find mean. Formula: x¯=∑i=1nxin Formula: σ=∑ ( x i − x ¯ ) 2 n Calculation: Using...Chapter 3, Problem 7REChapter 3, Problem 12REChapter 4.1, Problem 19EChapter 4.1, Problem 20EChapter 4.1, Problem 43EChapter 4.2, Problem 23EChapter 4.2, Problem 26EChapter 4.2, Problem 35EChapter 4.3, Problem 23EChapter 4.3, Problem 24EChapter 4.3, Problem 26EChapter 4, Problem 1CQChapter 4, Problem 12REGiven: The inflation rate and the unemployment rate, both in percent, for the years 1988-2015 is as...Given: The inflation rate and the unemployment rate, both in percent, for the years 1988-2015 is as...Given information: The below table presents the inflation rate and unemployment rate, both in...Given: The inflation rate and the unemployment rate, both in percent, for the years 1988-2014 is as...Chapter 5.1, Problem 29EGiven: One red die and one blue die are rolled. The outcome of each die is a number between 1 and 6....Given: One red die and one blue die are rolled. The outcome of each die is a number between 1 and 6....Given: One red die and one blue die are rolled. The outcome of each die is a number between 1 and 6....Chapter 5.2, Problem 34EChapter 5.2, Problem 40EChapter 5.2, Problem 42EChapter 5.2, Problem 44EChapter 5.3, Problem 39EChapter 5.3, Problem 40EChapter 5.3, Problem 42EChapter 5.3, Problem 43EChapter 5.3, Problem 44EChapter 5.4, Problem 34EChapter 5.4, Problem 35EChapter 5.4, Problem 36EChapter 5, Problem 1CQGiven: Probability of female is 0.55, probability of business major is 0.2 and the probability that...Chapter 5, Problem 10REGiven: The life table is given as follows: Concept used: P(Alive at age x/Alive age y) is the...Given: The life table is given as follows: Concept used: P(Alive at age x/Alive age y) is the...Chapter 6.1, Problem 42EChapter 6.1, Problem 44EChapter 6.1, Problem 47EChapter 6.1, Problem 49EChapter 6.1, Problem 61EChapter 6.2, Problem 33EChapter 6.2, Problem 37EChapter 6.2, Problem 39EGiven: X be the event that occurs in a 1-second interval. Calculation: Let, Probability mass...Chapter 6, Problem 1CQGiven: x P ( x )60.2170.1280.2990.11100.01110.26 Concept used: Mean=∑x.P(x) x P ( x...Given: Number of TestsFrequency (in 1000s)1 9532 4233 1944 805 296 97 38 1Total1692 To get the...Chapter 7.1, Problem 27EChapter 7.1, Problem 28EChapter 7.1, Problem 29EChapter 7.1, Problem 30EChapter 7.2, Problem 9EChapter 7.2, Problem 27EChapter 7.2, Problem 28EIt is given in the question that, μ=75σ=8 Probability density function of normal distribution is...Chapter 7.3, Problem 17EGiven information:The data is shown below in table. DateTemperatureJuly 2169July 2275July 2379July...Chapter 7.3, Problem 20EChapter 7.4, Problem 21EChapter 7.4, Problem 22EChapter 7.5, Problem 16EChapter 7.5, Problem 22EGiven: The probability density curve is, Calculation: The proportion of population in between 2 to 4...Chapter 7, Problem 11CQChapter 7, Problem 4REChapter 7, Problem 5REChapter 8.1, Problem 64E. Given information: 95% Confidence interval = (9.6956,15.0084)Sample mean(x¯)=12.352Sample...Given information: 98% Confidence interval = (0.1233,5.1007)Sample mean(x¯)=2.657Sample...Given: The provided box plot is: The provided box plot shows the mean half -life. In this no outlier...Chapter 8.2, Problem 37EGiven information : Data points: 8.0 7.5 8.5 6.5 8.5 6.5 7.0 7.5 Calculation: The outlier is value...Chapter 8.3, Problem 43ELet’s calculate the confidence interval using exact one. Given, n=101s=40α=0.05 Using chi square...Chapter 8, Problem 1CQGiven information: The number of pollutants is 4 and the data is shown in table below. Year 1Year...Given information: The number of pollutants is 4 and the data is shown in table below. Year 1Year...Given: n = sample size = 100 σ = population standard deviation = 5000 α = Level of significance =...Chapter 9, Problem 1CQGiven information: The probability is p , H0:p=0.5 and H1:p>0.5 . The given data is shown in...Given information: The given data is shown in table below. DateHighYearLowYearMore RecentJan...Given information: The given data is shown in table below. DateHighYearLowYearMore RecentJan...Given information: The given data is shown in table below. DateHighYearLowYearMore RecentJan...Chapter 10.1, Problem 25EChapter 10.1, Problem 26EChapter 10, Problem 1CQGiven information: The sample is 76 , the mean annual income is $34214 and the standard deviation is...Chapter 11.1, Problem 11EChapter 11.2, Problem 10EGiven Information: Following is a sample of ten matched pairs. Sample 1 28 29 22 25 26 29 27 24 27...Chapter 11.4, Problem 13EGiven Information: The choices for the test are given below. A test for the difference between two...Given Information: The number of rods taken from machine A is n1=1000 The number of rods met...Chapter 11, Problem 3WAIGiven Information: The results for five factors are presented in the following table. Class...Chapter 12.1, Problem 22EChapter 12.1, Problem 29EChapter 12.2, Problem 14EChapter 12, Problem 1CQChapter 12, Problem 9CQGiven information :...Given information :...Given information : Concept Involved: In order to decide whether the presumed hypothesis for data...Given information: The data is shown below. x12173171611149y1314161314141314 Calculation: The...Chapter 13.1, Problem 31EGiven information: the sample size 25 , b0=3.25,b1=2.32,se=3.53,∑(x−x¯)2=224.05,x¯=0.98 Formula...Given information: The data is shown below. y(x1)(x2)(x3)y(x1)(x2)(x3)y(x1)(x2)(x3)y(x1)(x2)(x3)31.3...Chapter 13, Problem 1CQGiven information: x=20 and 95% prediction interval x2513161929191630y4020333050373437 Formula...Chapter 13, Problem 11REChapter 13, Problem 12REChapter 14.1, Problem 19EChapter 14.1, Problem 24EChapter 14, Problem 1CQGiven information: The given data is, PlantConcentrationA438619732638 B857101411538831053...Given information: The given data is, PlantConcentrationA438619732638 B857101411538831053...Given information: The value of α is 0.05 and the given data is, PlantConcentrationA438619732638...Chapter 15.1, Problem 11EGiven information: The level of significance is 0.05 and the given data is,...Chapter 15.3, Problem 17EGiven information: The data is 50,38,23,29,57,26,53,42,60,23 and the hypothesis are H0:m=30 and...

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Elementary Statistics 2nd Edition
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ELEMENTARY STATISITCS
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