a.
To find: Whether it could be assumed that the condition required to construct a confidence interval for
a.

Answer to Problem 35E
Yes
Explanation of Solution
Given:
The provided box plot is:
The provided box plot shows the mean half -life. In this no outlier is present, it could be said that this sample has been taken from the
b.
To find: The confidence interval for the mean half-life the provided size
b.

Answer to Problem 35E
The required confidence interval is
Explanation of Solution
Formula used:
Given:
Drug’s half-life of randomly selected 18 sample are:
3.3, 1.7, 2.0, 5.0, 1.2, 2.8, 3.7, 3.5, 4.8, 4.7, 4.9, 2.5, 5.1, 6.0, 3.9, 4.3, 2.1, 3.0
Calculation:
Since,
Sample mean and standard deviation for the provided sample data can be computed as:
Data | Data-Mean | (Data-mean) ^2 |
3.3 | -0.2 | 0.04 |
1.7 | -1.88 | 3.5344 |
2 | -1.58 | 2.4964 |
5 | 1.42 | 2.0164 |
1.2 | -2.38 | 5.6644 |
2.8 | -0.78 | 0.6084 |
3.7 | 0.12 | 0.0144 |
3.5 | -0.08 | 0.0064 |
4.8 | 1.22 | 1.4884 |
4.7 | 1.12 | 1.2544 |
4.9 | 1.32 | 1.7424 |
2.5 | -1.08 | 1.1664 |
5.1 | 1.52 | 2.3104 |
6 | 2.42 | 5.8564 |
3.9 | 0.32 | 0.1024 |
4.3 | 0.32 | 0.1024 |
2.1 | 1.32 | 1.7424 |
3 | -0.58 | 0.3364 |
The 95% confidence interval for the mean prices can be calculated as:
Degree of freedom = 18-1 = 17.
Thus, t- critical (table) value at 5% significance level and 17 degree of freedom is
c.
To find: whether this confidence interval (part b) contradict the national health claims that the mean half-life 3.51
c.

Answer to Problem 35E
Yes
Explanation of Solution
Since, the calculated confidence interval in part b ranges from 2.93 to 4.23, so it can be easily seen that the hypotheses value of national health includes in it
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Chapter 8 Solutions
ELEMENTARY STATISTICS-ALEKS ACCESS CODE
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