ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
7th Edition
ISBN: 9781319399849
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter F, Problem K.3AST
(a)
Interpretation Introduction
Interpretation:
Oxidation number of nitrogen in
Concept Introduction:
Oxidation state of a species is the one that has a specified oxidation number. Increase in oxidation number corresponds to oxidation while decrease in oxidation number corresponds to reduction. Rules for assigning oxidation number for an element is given as follows;
- The oxidation number is zero for the element that is present in uncombined state.
- Sum of the oxidation number of the atoms that is present in it is equal to the charge on the species.
- Oxidation number of the element is the charge that is possessed when the more electronegative atom is imagined to be an ion.
(b)
Interpretation Introduction
Interpretation:
Oxidation number of chlorine in
Concept Introduction:
Refer part (a).
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
Chapter F Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
Ch. F - Prob. A.1ASTCh. F - Prob. A.1BSTCh. F - Prob. A.2ASTCh. F - Prob. A.2BSTCh. F - Prob. A.3ASTCh. F - Prob. A.3BSTCh. F - Prob. A.4ASTCh. F - Prob. A.4BSTCh. F - Prob. A.5ASTCh. F - Prob. A.5BST
Ch. F - Prob. A.1ECh. F - Prob. A.2ECh. F - Prob. A.3ECh. F - Prob. A.4ECh. F - Prob. A.5ECh. F - Prob. A.6ECh. F - Prob. A.7ECh. F - Prob. A.8ECh. F - Prob. A.9ECh. F - Prob. A.10ECh. F - Prob. A.11ECh. F - Prob. A.12ECh. F - Prob. A.13ECh. F - Prob. A.14ECh. F - Prob. A.15ECh. F - Prob. A.16ECh. F - Prob. A.17ECh. F - Prob. A.18ECh. F - Prob. A.19ECh. F - Prob. A.20ECh. F - Prob. A.21ECh. F - Prob. A.22ECh. F - Prob. A.23ECh. F - Prob. A.24ECh. F - Prob. A.25ECh. F - Prob. A.26ECh. F - Prob. A.27ECh. F - Prob. A.28ECh. F - Prob. A.29ECh. F - Prob. A.30ECh. F - Prob. A.31ECh. F - Prob. A.32ECh. F - Prob. A.33ECh. F - Prob. A.34ECh. F - Prob. A.35ECh. F - Prob. A.36ECh. F - Prob. A.37ECh. F - Prob. A.38ECh. F - Prob. A.39ECh. F - Prob. A.40ECh. F - Prob. A.41ECh. F - Prob. A.42ECh. F - Prob. B.1ASTCh. F - Prob. B.1BSTCh. F - Prob. B.2ASTCh. F - Prob. B.2BSTCh. F - Prob. B.3ASTCh. F - Prob. B.3BSTCh. F - Prob. B.1ECh. F - Prob. B.2ECh. F - Prob. B.3ECh. F - Prob. B.4ECh. F - Prob. B.5ECh. F - Prob. B.6ECh. F - Prob. B.7ECh. F - Prob. B.8ECh. F - Prob. B.9ECh. F - Prob. B.10ECh. F - Prob. B.11ECh. F - Prob. B.12ECh. F - Prob. B.13ECh. F - Prob. B.14ECh. F - Prob. B.15ECh. F - Prob. B.16ECh. F - Prob. B.17ECh. F - Prob. B.18ECh. F - Prob. B.19ECh. F - Prob. B.20ECh. F - Prob. B.21ECh. F - Prob. B.22ECh. F - Prob. C.1ASTCh. F - Prob. C.1BSTCh. F - Prob. C.2ASTCh. F - Prob. C.2BSTCh. F - Prob. C.1ECh. F - Prob. C.2ECh. F - Prob. C.3ECh. F - Prob. C.4ECh. F - Prob. C.5ECh. F - Prob. C.6ECh. F - Prob. C.7ECh. F - Prob. C.8ECh. F - Prob. C.9ECh. F - Prob. C.10ECh. F - Prob. C.11ECh. F - Prob. C.12ECh. F - Prob. C.13ECh. F - Prob. C.14ECh. F - Prob. C.15ECh. F - Prob. C.16ECh. F - Prob. C.17ECh. F - Prob. C.18ECh. F - Prob. C.19ECh. F - Prob. C.20ECh. F - Prob. C.21ECh. F - Prob. C.22ECh. F - Prob. D.1ASTCh. F - Prob. D.1BSTCh. F - Prob. D.2ASTCh. F - Prob. D.2BSTCh. F - Prob. D.3ASTCh. F - Prob. D.3BSTCh. F - Prob. D.4ASTCh. F - Prob. D.4BSTCh. F - Prob. D.5ASTCh. F - Prob. D.5BSTCh. F - Prob. D.1ECh. F - Prob. D.2ECh. F - Prob. D.3ECh. F - Prob. D.4ECh. F - Prob. D.5ECh. F - Prob. D.6ECh. F - Prob. D.7ECh. F - Prob. D.8ECh. F - Prob. D.9ECh. F - Prob. D.10ECh. F - Prob. D.11ECh. F - Prob. D.12ECh. F - Prob. D.13ECh. F - Prob. D.14ECh. F - Prob. D.15ECh. F - Prob. D.16ECh. F - Prob. D.17ECh. F - Prob. D.18ECh. F - Prob. D.19ECh. F - Prob. D.20ECh. F - Prob. D.21ECh. F - Prob. D.22ECh. F - Prob. D.23ECh. F - Prob. D.24ECh. F - Prob. D.25ECh. F - Prob. D.26ECh. F - Prob. D.27ECh. F - Prob. D.28ECh. F - Prob. D.29ECh. F - Prob. D.30ECh. F - Prob. D.31ECh. F - Prob. D.32ECh. F - Prob. D.33ECh. F - Prob. D.34ECh. F - Prob. D.35ECh. F - Prob. D.36ECh. F - Prob. E.1ASTCh. F - Prob. E.1BSTCh. F - Prob. E.2ASTCh. F - Prob. E.2BSTCh. F - Prob. E.3ASTCh. F - Prob. E.3BSTCh. F - Prob. E.4ASTCh. F - Prob. E.4BSTCh. F - Prob. E.5ASTCh. F - Prob. E.5BSTCh. F - Prob. E.6ASTCh. F - Prob. E.6BSTCh. F - Prob. E.1ECh. F - Prob. E.2ECh. F - Prob. E.3ECh. F - Prob. E.4ECh. F - Prob. E.5ECh. F - Prob. E.6ECh. F - Prob. E.7ECh. F - Prob. E.8ECh. F - Prob. E.9ECh. F - Prob. E.10ECh. F - Prob. E.11ECh. F - Prob. E.12ECh. F - Prob. E.13ECh. F - Prob. E.14ECh. F - Prob. E.15ECh. F - Prob. E.16ECh. F - Prob. E.17ECh. F - Prob. E.18ECh. F - Prob. E.19ECh. F - Prob. E.20ECh. F - Prob. E.21ECh. F - Prob. E.22ECh. F - Prob. E.23ECh. F - Prob. E.24ECh. F - Prob. E.25ECh. F - Prob. E.26ECh. F - Prob. E.27ECh. F - Prob. E.28ECh. F - Prob. E.29ECh. F - Prob. E.30ECh. F - Prob. E.31ECh. F - Prob. E.32ECh. F - Prob. E.33ECh. F - Prob. E.34ECh. F - Prob. F.1ASTCh. F - Prob. F.1BSTCh. F - Prob. F.2ASTCh. F - Prob. F.2BSTCh. F - Prob. F.3ASTCh. F - Prob. F.3BSTCh. F - Prob. F.4ASTCh. F - Prob. F.4BSTCh. F - Prob. F.1ECh. F - Prob. F.2ECh. F - Prob. F.3ECh. F - Prob. F.4ECh. F - Prob. F.5ECh. F - Prob. F.6ECh. F - Prob. F.7ECh. F - Prob. F.8ECh. F - Prob. F.9ECh. F - Prob. F.10ECh. F - Prob. F.11ECh. F - Prob. F.12ECh. F - Prob. F.13ECh. F - Prob. F.14ECh. F - Prob. F.15ECh. F - Prob. F.16ECh. F - Prob. F.17ECh. F - Prob. F.18ECh. F - Prob. F.19ECh. F - Prob. F.20ECh. F - Prob. F.21ECh. F - Prob. F.22ECh. F - Prob. F.23ECh. F - Prob. F.24ECh. F - Prob. F.25ECh. F - Prob. F.26ECh. F - Prob. F.27ECh. F - Prob. F.28ECh. F - Prob. G.1ASTCh. F - Prob. G.1BSTCh. F - Prob. G.2ASTCh. F - Prob. G.2BSTCh. F - Prob. G.3ASTCh. F - Prob. G.3BSTCh. F - Prob. G.4ASTCh. F - Prob. G.4BSTCh. F - Prob. G.1ECh. F - Prob. G.2ECh. F - Prob. G.3ECh. F - Prob. G.4ECh. F - Prob. G.5ECh. F - Prob. G.6ECh. F - Prob. G.7ECh. F - Prob. G.8ECh. F - Prob. G.9ECh. F - Prob. G.10ECh. F - Prob. G.11ECh. F - Prob. G.12ECh. F - Prob. G.13ECh. F - Prob. G.14ECh. F - Prob. G.15ECh. F - Prob. G.16ECh. F - Prob. G.17ECh. F - Prob. G.18ECh. F - Prob. G.19ECh. F - Prob. G.20ECh. F - Prob. G.21ECh. F - Prob. G.22ECh. F - Prob. G.23ECh. F - Prob. G.24ECh. F - Prob. G.25ECh. F - Prob. G.27ECh. F - Prob. G.28ECh. F - Prob. G.30ECh. F - Prob. H.1ASTCh. F - Prob. H.1BSTCh. F - Prob. H.1ECh. F - Prob. H.2ECh. F - Prob. H.3ECh. F - Prob. H.4ECh. F - Prob. H.5ECh. F - Prob. H.6ECh. F - Prob. H.7ECh. F - Prob. H.8ECh. F - Prob. H.9ECh. F - Prob. H.10ECh. F - Prob. H.11ECh. F - Prob. H.12ECh. F - Prob. H.13ECh. F - Prob. H.14ECh. F - Prob. H.15ECh. F - Prob. H.16ECh. F - Prob. H.17ECh. F - Prob. H.18ECh. F - Prob. H.19ECh. F - Prob. H.20ECh. F - Prob. H.21ECh. F - Prob. H.22ECh. F - Prob. H.23ECh. F - Prob. H.24ECh. F - Prob. H.25ECh. F - Prob. H.26ECh. F - Prob. I.1ASTCh. F - Prob. I.1BSTCh. F - Prob. I.2ASTCh. F - Prob. I.2BSTCh. F - Prob. I.3ASTCh. F - Prob. I.3BSTCh. F - Prob. I.1ECh. F - Prob. I.2ECh. F - Prob. I.3ECh. F - Prob. I.4ECh. F - Prob. I.5ECh. F - Prob. I.6ECh. F - Prob. I.7ECh. F - Prob. I.8ECh. F - Prob. I.9ECh. F - Prob. I.10ECh. F - Prob. I.11ECh. F - Prob. I.12ECh. F - Prob. I.13ECh. F - Prob. I.14ECh. F - Prob. I.15ECh. F - Prob. I.16ECh. F - Prob. I.17ECh. F - Prob. I.18ECh. F - Prob. I.19ECh. F - Prob. I.20ECh. F - Prob. I.21ECh. F - Prob. I.22ECh. F - Prob. I.23ECh. F - Prob. I.24ECh. F - Prob. I.25ECh. F - Prob. I.26ECh. F - Prob. J.1ASTCh. F - Prob. J.1BSTCh. F - Prob. J.2ASTCh. F - Prob. J.2BSTCh. F - Prob. J.1ECh. F - Prob. J.2ECh. F - Prob. J.3ECh. F - Prob. J.4ECh. F - Prob. J.5ECh. F - Prob. J.6ECh. F - Prob. J.7ECh. F - Prob. J.8ECh. F - Prob. J.9ECh. F - Prob. J.10ECh. F - Prob. J.11ECh. F - Prob. J.12ECh. F - Prob. J.13ECh. F - Prob. J.14ECh. F - Prob. J.15ECh. F - Prob. J.16ECh. F - Prob. J.17ECh. F - Prob. J.18ECh. F - Prob. J.19ECh. F - Prob. J.20ECh. F - Prob. J.21ECh. F - Prob. J.22ECh. F - Prob. J.23ECh. F - Prob. J.24ECh. F - Prob. K.1ASTCh. F - Prob. K.1BSTCh. F - Prob. K.2ASTCh. F - Prob. K.2BSTCh. F - Prob. K.3ASTCh. F - Prob. K.3BSTCh. F - Prob. K.4ASTCh. F - Prob. K.4BSTCh. F - Prob. K.5ASTCh. F - Prob. K.5BSTCh. F - Prob. K.1ECh. F - Prob. K.2ECh. F - Prob. K.3ECh. F - Prob. K.4ECh. F - Prob. K.5ECh. F - Prob. K.6ECh. F - Prob. K.7ECh. F - Prob. K.8ECh. F - Prob. K.9ECh. F - Prob. K.10ECh. F - Prob. K.11ECh. F - Prob. K.12ECh. F - Prob. K.13ECh. F - Prob. K.14ECh. F - Prob. K.15ECh. F - Prob. K.16ECh. F - Prob. K.17ECh. F - Prob. K.18ECh. F - Prob. K.19ECh. F - Prob. K.20ECh. F - Prob. K.21ECh. F - Prob. K.22ECh. F - Prob. K.23ECh. F - Prob. K.24ECh. F - Prob. K.25ECh. F - Prob. K.26ECh. F - Prob. L.1ASTCh. F - Prob. L.1BSTCh. F - Prob. L.2ASTCh. F - Prob. L.2BSTCh. F - Prob. L.3ASTCh. F - Prob. L.3BSTCh. F - Prob. L.1ECh. F - Prob. L.2ECh. F - Prob. L.3ECh. F - Prob. L.4ECh. F - Prob. L.5ECh. F - Prob. L.6ECh. F - Prob. L.7ECh. F - Prob. L.8ECh. F - Prob. L.9ECh. F - Prob. L.10ECh. F - Prob. L.11ECh. F - Prob. L.12ECh. F - Prob. L.13ECh. F - Prob. L.14ECh. F - Prob. L.15ECh. F - Prob. L.16ECh. F - Prob. L.17ECh. F - Prob. L.18ECh. F - Prob. L.19ECh. F - Prob. L.20ECh. F - Prob. L.21ECh. F - Prob. L.22ECh. F - Prob. L.23ECh. F - Prob. L.24ECh. F - Prob. L.25ECh. F - Prob. L.29ECh. F - Prob. L.30ECh. F - Prob. L.31ECh. F - Prob. L.32ECh. F - Prob. L.33ECh. F - Prob. L.34ECh. F - Prob. L.35ECh. F - Prob. L.37ECh. F - Prob. L.38ECh. F - Prob. L.39ECh. F - Prob. L.40ECh. F - Prob. L.41ECh. F - Prob. L.42ECh. F - Prob. M.1ASTCh. F - Prob. M.1BSTCh. F - Prob. M.2ASTCh. F - Prob. M.2BSTCh. F - Prob. M.3ASTCh. F - Prob. M.3BSTCh. F - Prob. M.4ASTCh. F - Prob. M.4BSTCh. F - Prob. M.1ECh. F - Prob. M.2ECh. F - Prob. M.3ECh. F - Prob. M.4ECh. F - Prob. M.5ECh. F - Prob. M.6ECh. F - Prob. M.7ECh. F - Prob. M.8ECh. F - Prob. M.9ECh. F - Prob. M.10ECh. F - Prob. M.11ECh. F - Prob. M.12ECh. F - Prob. M.13ECh. F - Prob. M.14ECh. F - Prob. M.15ECh. F - Prob. M.16ECh. F - Prob. M.17ECh. F - Prob. M.18ECh. F - Prob. M.19ECh. F - Prob. M.20ECh. F - Prob. M.21ECh. F - Prob. M.22ECh. F - Prob. M.23ECh. F - Prob. M.25ECh. F - Prob. M.26ECh. F - Prob. M.27ECh. F - Prob. M.28E
Knowledge Booster
Similar questions
- R lactam or lactone considering as weak acid or weak base and whyarrow_forward81. a. Propose a mechanism for the following reaction: OH CH2=CHCHC=N b. What is the product of the following reaction? HO H₂O N=CCH2CH2CH OH HO CH3CCH=CH2 H₂O C=N 82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium uliaarrow_forwardFor each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HEarrow_forward
- Predicting As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: H₂N O H 1. ? 2. H3O+ If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. 0 If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. فا Explanation Check Click and drag to start drawing a structure.arrow_forwardHighlight the chirality (or stereogenic) center(s) in the given compound. A compound may have one or more stereogenic centers. OH OH OH OH OH OHarrow_forwardUsing wedge-and-dash bonds, modify the bonds on the chiral carbon in the molecule below so the molecule has R stereochemical configuration. NH H Br X टेarrow_forward
- Provide photos of models of the following molecules. (Include a key for identification of the atoms) 1,2-dichloropropane 2,3,3-trimethylhexane 2-bromo-3-methybutanearrow_forwardPlease draw the structure in the box that is consistent with all the spectral data and alphabetically label all of the equivalent protons in the structure (Ha, Hb, Hc....) in order to assign all the proton NMR peaks. The integrations are computer generated and approximate the number of equivalent protons. Molecular formula: C13H1802 14 13 12 11 10 11 (ppm) Structure with assigned H peaks 2.08 3.13arrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 10.0 mL of the base solution, what is the pH of the resulting solution?arrow_forward
- Firefly luciferin exhibits three rings. Identify which of the rings are aromatic. Identify which lone pairs are involved in establishing aromaticity. The lone pairs are labeled A-D below.arrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 10.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardGiven a complex reaction with rate equation v = k1[A] + k2[A]2, what is the overall reaction order?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning