Concept explainers
(a)
Interpretation:
The given skeletal chemical equation has to be balanced.
Concept Introduction:
Chemical equation is a short form representation of a
(a)

Answer to Problem H.6E
Balanced chemical equation is
Explanation of Solution
Given skeletal equation is shown below;
Balancing oxygen atoms: In the reactant side, there are three oxygen atoms while on the product side, there are two oxygen atoms. Adding coefficient
Balancing potassium atoms: In the reactant side, there are two potassium atoms while on the product side there is only one potassium atom. Adding coefficient
(b)
Interpretation:
The given skeletal chemical equation has to be balanced.
Concept Introduction:
Refer part (a).
(b)

Answer to Problem H.6E
Balanced chemical equation is
Explanation of Solution
Given skeletal equation is shown below;
Balancing oxygen atoms: In the reactant side, there are three oxygen atoms while on the product side, there are four oxygen atoms. Adding coefficient
(c)
Interpretation:
The given skeletal chemical equation has to be balanced.
Concept Introduction:
Refer part (a).
(c)

Answer to Problem H.6E
Balanced chemical equation is
Explanation of Solution
Given skeletal equation is shown below;
Balancing hydrogen atoms: In the reactant side, there are four hydrogen atoms while on the product side, there is only one hydrogen atom. Adding coefficient
Balancing iodine atoms: In the reactant side, there are two iodine atoms while on the product side there are four iodine atom. Adding coefficient
(d)
Interpretation:
The given skeletal chemical equation has to be balanced.
Concept Introduction:
Refer part (a).
(d)

Answer to Problem H.6E
Balanced chemical equation is
Explanation of Solution
Given skeletal equation is shown below;
Balancing phosphorus atoms: In the reactant side, there are four phosphorus atoms while on the product side, there is only one phosphorus atom. Adding coefficient
Balancing hydrogen atoms: In the reactant side, there is only two hydrogen atoms while on the product side there are twelve hydrogen atoms. Adding coefficient
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Chapter F Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
- need help finding the product of these reactionsarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism 1) Bakelite like polymer Using: Resorcinol + NaOH + Formalin 2) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerol 3) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium boratearrow_forwardUsing the table of Reactants and Products provided provide the correct letter that corresponds with the Carboxylic acid that is formed in the reaction below. 6 M NaOH Acid-workup WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR PHRASES A) Pool of Reagents for Part B CI B) OH C) E) CI J) racemic F) K) OH N) OH P) G) OH D) HO H) L) M) HO Q) R) CI Aarrow_forward
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- 3. The explosive decomposition of 2 mole of TNT (2,4,6-trinitrotoluene) is shown below: Assume the C(s) is soot-basically atomic carbon (although it isn't actually atomic carbon in real life). 2 CH3 H NO2 NO2 3N2 (g)+7CO (g) + 5H₂O (g) + 7C (s) H a. Use bond dissociation energies to calculate how much AU is for this reaction in kJ/mol.arrow_forwardPart I. Draw reaction mechanism for the transformations of benzophenone to benzopinacol to benzopinaco lone and answer the ff: Pinacol (2,3-dimethyl, 1-3-butanediol) on treatment w/ acid gives a mixture of pina colone and (3,3-dimethyl-2-butanone) 2,3-dimethyl-1,3-butadiene. Give reasonable mechanism the formation of the products Forarrow_forwardShow the mechanism for these reactionsarrow_forward
- Draw the stepwise mechanismarrow_forwardDraw a structural formula of the principal product formed when benzonitrile is treated with each reagent. (a) H₂O (one equivalent), H₂SO₄, heat (b) H₂O (excess), H₂SO₄, heat (c) NaOH, H₂O, heat (d) LiAlH4, then H₂Oarrow_forwardDraw the stepwise mechanism for the reactionsarrow_forward
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