Chapter F, Problem G.8E

Interpretation Introduction

Interpretation:

The mass of solution that is needed has to be calculated which contains $\text{0}\text{.453}\text{g}$ of ${\text{CuSO}}_{\text{4}}$ that is $5.16\%$ of ${\text{CuSO}}_{\text{4}}$ by mass has to be calculated.

Concept Introduction:

Molarity of the solution is defined as the number of moles of solute that is dissolved in the volume of solution in liters.  Unit of molarity is $\text{mol}\cdot {\text{L}}^{-1}$.  The equation for molarity is given as follows;

    $\text{Molarity (M)}=\frac{\text{Amount of solute in moles}}{\text{Volume of solution in liters}}$

Molar concentration of solute is used for calculating the amount of solute in solution as given below;

    $n=c\times V$

The equation to calculated the mass of solute dissolved in solution is given as follows;

    $m=cMV$

Where,

    $m$ is the mass of solute.

    $c$ is the concentration of solution.

    $M$ is the molar mass of solute.

    $V$ is the volume of solution.