A solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l)  E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 V

Fundamentals Of Analytical Chemistry
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Chapter26: Molecular Absorption Spectrometry
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Problem 26.20QAP
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A solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell:

calomel electrode (saturated)//titration solution/Hg(l)

Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E.

Hg2+(aq) + 2e- = Hg(l)  E0= 0.852 V

E' (calomel electrode, saturated KCl) = 0.241 V

 

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