Chapter F, Problem G.4AST

Interpretation Introduction

Interpretation:

Volume of $\text{0}\text{.0155}\text{M}$ solution of $\text{HCl(aq)}$ that has to be prepared must be calculated if the use is $\text{100}\text{mL}$ of $5.23\times {10}^{-4}\text{M}\text{HCl(aq)}$.

Concept Introduction:

Dilution is addition of water to a substance that is soluble in water.  This process does not change the number of solute particles present in the solution, instead the concentration of the solution is alone changed.  Dilution increases the volume of solution.