Molecular formula of oxalic acid has to be deduced if its molar mass is 90.0 g ⋅ mol − 1 and the empirical formula is CHO 2 . Concept Introduction: Empirical formula is the one that can be determined from the molar mass of the elements that is present in the compound and the mass percentage of the elements. The mass percentage of the elements present in the compound is converted into the moles of each element considering the molar mass of each element. The relative number of moles for each type of atoms is found out finally. Molecular formula of a compound can be found if the empirical formula and molar mass of the compound is known. The molar mass of compound is divided by the molar mass of the empirical formula in order to obtain the factor which is multiplied with the coefficients of empirical formula in order to obtain the molecular formula.

Question

Want to see the full answer?

Answer 1

Question

Chapter F, Problem F.4BST

Interpretation Introduction

Interpretation:

Molecular formula of oxalic acid has to be deduced if its molar mass is 90.0 g⋅mol−1 and the empirical formula is CHO2.

Concept Introduction:

Empirical formula is the one that can be determined from the molar mass of the elements that is present in the compound and the mass percentage of the elements. The mass percentage of the elements present in the compound is converted into the moles of each element considering the molar mass of each element. The relative number of moles for each type of atoms is found out finally.

Molecular formula of a compound can be found if the empirical formula and molar mass of the compound is known. The molar mass of compound is divided by the molar mass of the empirical formula in order to obtain the factor which is multiplied with the coefficients of empirical formula in order to obtain the molecular formula.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. • If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T G OH де OH This transformation can't be done in one step.

Macmillan Leaming Draw the major organic product of the reaction. 1. CH3CH2MgBr 2. H+ - G Select Draw Templates More H о QQ

Draw the condensed structure of 3-hydroxy-2-butanone. Click anywhere to draw the first atom of your structure.