a)
Interpretation:
Given that the final step in the hydration of an
Concept introduction:
The enol picks up a proton from H3O+ using the unshared pair of electrons on oxygen and the π electrons in the double bond to yield a carbocation. The carbocation ion then loses a proton and the electrons in the O-H bond are moved towards the positively charged carbon to yield the ketone.
To propose:
A mechanism for the tautomerization reaction shown.
b)
Interpretation:
Given that the final step in the hydration of an alkyne under acidic conditions is the tautomerization of the enol intermediate to give the corresponding ketone. The mechanism involves protonation followed by deprotonation. Based on this information a mechanism for the tautomerization reaction shown is to be drawn.
Concept introduction:
The enol picks up a proton from H3O+ using the unshared pair of electrons on oxygen and the π electrons in the double bond to yield a carbocation. The carbocation then loses a proton and the electrons in the O-H bond are moved towards the positively charged carbon to yield the ketone.
To propose:
A mechanism for the tautomerization reaction shown.
c)
Interpretation:
Given that the final step in the hydration of an alkyne under acidic conditions is the tautomerization of the enol intermediate to give the corresponding ketone. The mechanism involves protonation followed by deprotonation. Based on this information a mechanism for the tautomerization reaction shown is to be drawn.
Concept introduction:
The enol picks up a proton from H3O+ using the unshared pair of electrons on oxygen and the π electrons in the double bond to yield a carbocation. The carbocation then loses a proton and the electrons in the O-H bond are moved towards the positively charged carbon to yield the ketone.
To propose:
A mechanism for the tautomerization reaction shown.
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Chapter 9 Solutions
Organic Chemistry
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Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning