Consider the circuit in Figure 8.34. The supply voltages are
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Microelectronics: Circuit Analysis and Design
- A left-sided signal x(t)=-e¯bt u(-t): 0 == X(s) -e-bu(t)e-st dt =- -Le-c 1 -(b+o+jw)t dt = = -00 -∞ (a + b) + jw 1 s+b For this integral to converge, it is necessary that b +σ <0; i.e., ROC: Re[s]=σ < −b. 2 How ?arrow_forwardA left-sided signal x(t)=-ebt u(-t): A right-sided signal x(t)=e¯at u(t) Find Laplace transform of x(t)=u(t)arrow_forwardFind Laplace transform of x(t) = −e¯btu(−t) + e¯atu(t) Find Laplace transform of x(t) = u(t)arrow_forward
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