Chapter 7.3, Problem 32PP

Interpretation Introduction

Interpretation:

The name of compound ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}$ needs to be determined.

Concept introduction:

The name of a compound containing a metal ion and oxyanion can be written such that name of cation is written first followed by the oxidation state written in Roman numbers and then the name of anion is written. The suffix depends on the charge of the anion. For example Cl- ion has suffix −ide which makes it chloride.

Answer to Problem 32PP

The name of ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}$ compound is Silver Chromate.

Explanation of Solution

The given compound ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}$ uses an ionic bond between silver and chromate. Here, silver has positive charge and oxygen has negative charge. In ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}$, each silver atom has a +1 charge and chromate has a -2 charge.

The given compound, ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}$, is Silver Chromate.

Conclusion

The name of compound, ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}$, is Silver Chromate.