Concept explainers
Interpretation:
The compound formed between elements Zinc and Oxygen needs to be explained.
Concept introduction:
Molecules are bound together by different types of bonds namely ionic and covalent. Ionic bonds are formed when there is complete transfer of electrons from one atom to another. These atoms either lose or gain electrons to become negatively or positively charged ions. The forces of attraction between these ions causes the ionic bond formation.

Answer to Problem 69A
The compound formed between elements Zinc and Oxygen is ZnO.
Explanation of Solution
Ionic bonds involve the transfer of electrons from one atom to the other. The metal atoms, an electrons donor, loses electrons to form a positively charged ion while the non-metal atoms, electron acceptor, gains electrons to form negatively charged ions. During the process of donating or gaining electrons, the atoms follow octet rule to attain a stable noble gas configuration. Therefore, the charges on the anion and cation depends on the electrons lost or gained giving net charge of zero.
Zinc has
Oxygen has atomic number as 8 with electronic configuration as 1s22s22p4. It has 6 valence electrons and needs two electrons to get octet configuration. It will gain two electrons to form O2-.
The compound between Zinc and oxygen is Zinc oxide in which the anion is O2- and cation is Zn2+. The ionic compound formed is ZnO where the ratio between cation to anion is 2:2 or 1:1.
The compound between Zinc and Oxygen is ZnO.
Chapter 7 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Cosmic Perspective Fundamentals
Anatomy & Physiology (6th Edition)
Organic Chemistry (8th Edition)
Human Anatomy & Physiology (2nd Edition)
Campbell Biology (11th Edition)
Microbiology: An Introduction
- Draw a stepwise mechanism for the following reaction. OHarrow_forwardHelp with annotating the labeled peaks in the 'H NMR (solvent CDCls) spectra and 'H NMR (solvent Acetone-D6) spectra Also help with Calculating the keto-enol tautomerization Ka constant for the product in both solvents.Two solvents and two different Kaarrow_forwardDraw a Haworth projection of a common cyclic form of this monosaccharide CH₂OH HO H HO H H OH CH₂OHarrow_forward
- Can you explain how I get these here and show the steps plz?arrow_forwardGive the IUPAC name for this compound Hydrocarbon Condensed Formulas Hint C2H5 CH2CH3 expand that in all the formula Part A: (CH3)2CHCH(C2H5)CH2CH2CH3 Give the IUPAC name for this compound. Part B: CH2=C(C2H5)CH2CH2CH3 Give the IUPAC name for this compound. Part C: (CH3)2C=CHC(C2H5)=CH2 Give the IUPAC name for this compound. Part D: CH3C=CCH(C2H5)2 Give the IUPAC name for this compound. Part E: (CH3)3CC=CCH2CH=C(CH3)2arrow_forwardSelect/ Match the correct letter from the image below for the IUPAC names given below: A B C D 3 E F G H K L Part 1. 4-methylheptane For example.mmmm Answer Letter H _for part 1 Part 2. 2,4-dimethylhexane Part 3. 2,3-dimethylpentane Part 4. 2,2-dimethylhexane Part 5. 2-ethyl-1,1,3,3-tetramethylcyclopentane Part 6. 3-ethyl-2-methylpentanearrow_forward
- Can u show the process as to how to get these?arrow_forwardSketch the expected 'H NMR spectra for the following compound. Label all of the H's in the structure and the corresponding signal for the spectra you sketch. Make sure you include the integration value and the splitting pattern for each signal Indicate how many signals you would expect in the 13C NMRarrow_forwardUse IUPAC naming rules to name the following hydrocarbon compounds: CH2-CH3 | a) CH-CH-CH2-CH-CH-CH3 b) | CH2 CH3 | CH3 CH3 \ / C=C H 1 H CH2-CH3 c) d) CH=C-CH3 e) CH3-CH2-CH2-CH=CH-CH3 f) CH2=CH-CH2-CH=CH-CH3 g) CH3-CH2-C = C-CH2-CH3 h)arrow_forward
- Q5 Name the following : a. b. C. d. e.arrow_forward25. Predict the major product of the following reaction. 1 equivalent of each of the starting materials was used. H₂C CH3 CH3 H3C H3C H3C. CH2 + H3C. heat CH3 CH H.C. CH3 H.C H.C CH3 CH CH3 CH3 A B C Earrow_forwardFind chemical structures based on the below information. a) Chemical formula C6H8O Compound is aromatic plus has two 1H NMR peaks that integrated for 3 each that are singlets (it could have more peaks in the 1H NMR b) Chemical Formula: C6H100 Compounds is conjugated 'H NMR has a signal that integrates for 6 and is a doublet IR spectra has a signal at 1730 cm-1arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





