Interpretation:
The conditions required for ionic compounds to conduct electricity and reason for it not being used as conductor always needs to be explained.
Concept introduction:
Molecules are bound together by different types of bonds namely ionic and covalent. Ionic bonds are formed when there is complete transfer of electrons from one atom to another. These atoms either lose or gain electrons to become negatively or positively charged ions. The forces of attraction between these ions causes the ionic bond formation. When molten, the ionic compounds will dissociate to release ions which are free to move around the semi liquid state and hence will be able to conduct electricity.

Answer to Problem 72A
The ionic compound will conduct electricity only in molten form or when dissolved in water.
Explanation of Solution
Ionic bonds involve the transfer of electrons from one atom to the other. The metal atoms loses electrons to form a positively charged ion while the non-metal atoms gains electrons to form negatively charged ions. During the process of donating or gaining electrons, the atoms follow octet rule to attain a stable noble gas configuration.
The ionic compound is a solid but when heated the bonds holding the ions are free to move within the structure. Also, when the solid is dissolved in water, it will break free the lattice points. The ions held at the lattice points are dissociated to free ions. Now, when current is passed through the ions, it will carry the charges. Hence, when electricity is passed through molten or solution containing ionic solids, it is found to conduct electricity.
Therefore, ionic compounds will conduct electricity only in molten form or when dissolved in water.
The ionic compound will conduct electricity only in molten form or when dissolved in water.
Chapter 7 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Introductory Chemistry (6th Edition)
College Physics: A Strategic Approach (3rd Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Campbell Biology: Concepts & Connections (9th Edition)
Human Anatomy & Physiology (2nd Edition)
Biology: Life on Earth (11th Edition)
- The following is a two groups (Regular tomato sauce & Salt Reduced Tomato Sauce) of data recorded by a team analysising salt content in tomato sauce using the MOHR titration method: Regular Tomato Sauce Salt Reduced Tomato Sauce 340.0 262.7 QUESTION: For both groups of data provide answers to the calculations attached in the imagearrow_forward7. Concentration and uncertainty in the estimate of concentration (class data) Class mean for sample (Regular) |[Cl-] (mmol/L) class mean Sn za/2 95% Confidence Interval (mmol/L) [Na+] (mg/100 mL) 95% Confidence Interval (mg/100 mL)arrow_forwardThe following is a two groups (Regular tomato sauce & Salt Reduced Tomato Sauce) of data recorded by a team analysising salt content in tomato sauce using the MOHR titration method: Regular Tomato Sauce Salt Reduced Tomato Sauce 223.4 148.7 353.7 278.2 334.6 268.7 305.6 234.4 340.0 262.7 304.3 283.2 244.7 143.6 QUESTION: For both groups of data calculate the answers attached in the image.arrow_forward
- Give reason(s) for six from the followings [using equations if possible] a. Addition of sodium carbonate to sulfanilic acid in the Methyl Orange preparation. b. What happened if the diazotization reaction gets warmed up by mistake. c. Addition of sodium nitrite in acidified solution in MO preparation through the diazotization d. Using sodium dithionite dihydrate in the second step for Luminol preparation. e. In nitroaniline preparation, addition of the acid mixture (nitric acid and sulfuric acid) to the product of step I. f. What is the main reason of the acylation step in nitroaniline preparation g. Heating under reflux. h. Fusion of an organic compound with sodium. HAND WRITTEN PLEASEarrow_forwardedict the major products of the following organic reaction: u A + ? CN Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Te LMUNDARYarrow_forwardSketch the intermediates for A,B,C & D.arrow_forward
- Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? O ? A . If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. . If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. ㅇ 80 F5 F6 A 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cente FIGarrow_forwardIn methyl orange preparation, if the reaction started with 0.5 mole of sulfanilic acid to form the diazonium salt of this compound and then it converted to methyl orange [0.2 mole]. If the efficiency of the second step was 50%, Calculate: A. Equation(s) of Methyl Orange synthesis: Diazotization and coupling reactions. B. How much diazonium salt was formed in this reaction? C. The efficiency percentage of the diazotization reaction D. Efficiency percentage of the whole reaction.arrow_forwardHand written equations pleasearrow_forward
- Hand written equations pleasearrow_forward> each pair of substrates below, choose the one that will react faster in a substitution reaction, assuming that: 1. the rate of substitution doesn't depend on nucleophile concentration and 2. the products are a roughly 50/50 mixture of enantiomers. Substrate A Substrate B Faster Rate X Ś CI (Choose one) (Choose one) CI Br Explanation Check Br (Choose one) © 2025 McGraw Hill LLC. All Rights Farrow_forwardNMR spectrum of ethyl acetate has signals whose chemical shifts are indicated below. Which hydrogen or set of hydrogens corresponds to the signal at 4.1 ppm? Select the single best answer. The H O HỌC—C—0—CH, CH, 2 A ethyl acetate H NMR: 1.3 ppm, 2.0 ppm, 4.1 ppm Check OA B OC ch B C Save For Later Submit Ass © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center |arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





