Chapter 7, Problem 7.43QE

Interpretation Introduction

Interpretation:

The wavelength of the electron with velocity $2.19\times {10}^6\text{ m/s}$ has to be determined. Also, the wavelength of electron has to be compared with the circumference of orbit with $n$ equals to 1.

Concept Introduction:

de Broglie established a relation for particles of matter that they also can behave as a wave and has a wavelength. The wavelength of the particle is inversely related to its mass. The smaller the mass, the larger will be its wavelength.

The expression given by the de Broglie is as follows:

  $\text{λ}=\frac{h}{mv}$        (1)

Here,

$\text{λ}$ is a wavelength of particle.

$h$ is a Plank’s constant.

$m$ is a mass of particle.

$v$ is a velocity of mass.