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Concept explainers
(a)
Interpretation:
The
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Addition Reaction: It is defined as
Electrophilic addition: It is a type of addition reaction in which the pi bond present in the molecule breaks as the electrophile approaches and results in the formation of product with sigma bond.
Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms.
(b)
Interpretation:
The other set of enantiomers for the given compound should be determined.
Concept introduction:
Enantiomers: They are chiral molecules whose mirror images are not superimposable.
R and S nomenclature: it is used to assign the molecule using CIP rules.
The CIP rules are as follows:
Select the chiral carbon and assign the numbers according to the decreasing
If the numbering follows clockwise direction then the molecule is termed as R and if it follows anti-clockwise direction then molecule is termed as S.
E configuration: The geometric isomers are given E configuration if high priority groups are placed on opposite sides of the bond.
Z configuration: The geometric isomers are given Z configuration if high priority groups are placed on same sides of the bond.
(c)
Interpretation:
The configuration for the given compounds should be determined.
Concept introduction:
Enantiomers: They are chiral molecules whose mirror images are not superimposable.
R and S nomenclature: it is used to assign the molecule using CIP rules.
The CIP rules are as follows:
Select the chiral carbon and assign the numbers according to the decreasing atomic mass of atoms attached to it.
If the numbering follows clockwise direction then the molecule is termed as R and if it follows anti-clockwise direction then molecule is termed as S.
E configuration: The geometric isomers are given E configuration if high priority groups are placed on opposite sides of the bond.
Z configuration: The geometric isomers are given Z configuration if high priority groups are placed on same sides of the bond.
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Chapter 6 Solutions
EBK ORGANIC CHEMISTRY
- Use the literature Ka value of the acetic acid, and the data below to answer these questions. Note: You will not use the experimental titration graphs to answer the questions that follow. Group #1: Buffer pH = 4.35 Group #2: Buffer pH = 4.70 Group #3: Buffer pH = 5.00 Group #4: Buffer pH = 5.30 Use the Henderson-Hasselbalch equation, the buffer pH provided and the literature pKa value of acetic acid to perform the following: a) calculate the ratios of [acetate]/[acetic acid] for each of the 4 groups buffer solutions above. b) using the calculated ratios, which group solution will provide the best optimal buffer (Hint: what [acetate]/[acetic acid] ratio value is expected for an optimal buffer?) c) explain your choicearrow_forwardHow would you prepare 1 liter of a 50 mM Phosphate buffer at pH 7.5 beginning with K3PO4 and 1 M HCl or 1 M NaOH? Please help and show calculations. Thank youarrow_forwardDraw the four most importantcontributing structures of the cation intermediate thatforms in the electrophilic chlorination of phenol,(C6H5OH) to form p-chlorophenol. Put a circle aroundthe best one. Can you please each step and also how you would approach a similar problem. Thank you!arrow_forward
- A 100mM lactic acid/lactate buffer was found to have a lactate to lactic acid ratio of 2 and a pH of 4.2. What is the pKa of lactic acid? Can you please help show the calculations?arrow_forwardUsing line angle formulas, draw thestructures of and name four alkanes that have total of 7carbons, one of which is tertiary.Please explain this in detail and can you also explain how to approach a similar problem like this as well?arrow_forwardUsing dashed line wedge projections drawthe indicated compounds and indicate whether thecompound you have drawn is R or S.(a) The two enantiomers of 2-chlorobutane. Can you please explain your steps and how you would approach a similar problem. Thank you!arrow_forward
- 5) There are no lone pairs shown in the structure below. Please add in all lone pairs and then give the hybridization scheme for the compound. (8) 10,11 7) 1.2.3 H 4 | 14 8) COC 12 13 H 16 15 H7 9) - 5.6 C 8 H 10) H 1). 2) 3)_ 11) 12) 13) 4)_ 14) 5) 15) 16) 6)arrow_forwardThe sum of the numbers in the name of isA. 11; B. 13; C. 10; D. 12; E. none of the other answers iscorrect. I believe the awnser should be E to this problem but the solution to this problem is D 12. I'm honestly unsure how that's the solution. If you can please explain the steps to this type of problem and how to approach a problem like this it would be greatly appreciated!arrow_forwardConsider the following data for phosphorus: g atomic mass 30.974 mol electronegativity 2.19 kJ electron affinity 72. mol kJ ionization energy 1011.8 mol kJ heat of fusion 0.64 mol You may find additional useful data in the ALEKS Data tab. Does the following reaction absorb or release energy? 2+ + (1) P (g) + e → P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? 00 release absorb Can't be decided with the data given. yes no ☐ kJ/mol (²) P* (8) + + + e →>> P (g) Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): ☐ release absorb Can't be decided with the data given. yes no kJ/mol аarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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