
(a)
Interpretation:
The number of nitrogen‑hydrogen bonds present in primary amine has to be given.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the
(b)
Interpretation:
The number of nitrogen‑hydrogen bonds present in secondary amine has to be given.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,
(c)
Interpretation:
The number of nitrogen‑hydrogen bonds present in tertiary amine has to be given.
Concept Introduction:
Amine is an organic derivative. If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine. Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine. Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group. Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group. Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group. The generalized structural formula for all the amines is,

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Chapter 6 Solutions
Organic And Biological Chemistry
- Propose a synthesis of 1-butanamine from the following: (a) a chloroalkane of three carbons (b) a chloroalkane of four carbonsarrow_forwardSelect the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forward
- b. H3C CH3 H3O+ ✓ H OHarrow_forward2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forward
- Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forwardInstructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forward
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