Organic And Biological Chemistry
Organic And Biological Chemistry
7th Edition
ISBN: 9781305081079
Author: STOKER, H. Stephen (howard Stephen)
Publisher: Cengage Learning,
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 6, Problem 6.10EP

(a)

Interpretation Introduction

Interpretation:

The compound has to be indicated whether it contains an amino group, a monosubstituted amino group, a disubstituted amino group, or not an amine.

Concept Introduction:

Amine is an organic derivative.  If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine.  Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine.  Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group.  Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group.  Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group.  The generalized structural formula for all the amines is,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  1

Amides are also organic derivative.  In an amide, the nitrogen atom is bonded to a carbonyl group.  The general structural formula of amide can be given as shown below,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  2

The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain.  In case of amides, the nitrogen atom is bonded to a carbonyl group.

(b)

Interpretation Introduction

Interpretation:

The compound has to be indicated whether it contains an amino group, a monosubstituted amino group, a disubstituted amino group, or not an amine.

Concept Introduction:

Amine is an organic derivative.  If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine.  Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine.  Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group.  Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group.  Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group.  The generalized structural formula for all the amines is,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  3

Amides are also organic derivative.  In an amide, the nitrogen atom is bonded to a carbonyl group.  The general structural formula of amide can be given as shown below,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  4

The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain.  In case of amides, the nitrogen atom is bonded to a carbonyl group.

(c)

Interpretation Introduction

Interpretation:

The compound has to be indicated whether it contains an amino group, a monosubstituted amino group, a disubstituted amino group, or not an amine.

Concept Introduction:

Amine is an organic derivative.  If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine.  Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine.  Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group.  Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group.  Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group.  The generalized structural formula for all the amines is,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  5

Amides are also organic derivative.  In an amide, the nitrogen atom is bonded to a carbonyl group.  The general structural formula of amide can be given as shown below,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  6

The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain.  In case of amides, the nitrogen atom is bonded to a carbonyl group.

(d)

Interpretation Introduction

Interpretation:

The compound has to be indicated whether it contains an amino group, a monosubstituted amino group, a disubstituted amino group, or not an amine.

Concept Introduction:

Amine is an organic derivative.  If in ammonia one or more alkyl, cycloalkyl, or aryl groups are substituted instead of hydrogen atom then it is known as amine.  Depending on the number of substitution the amines are classified as primary, secondary or tertiary amine.  Primary amine is the one in which only one hydrogen atom in ammonia is replaced by a hydrocarbon group.  Secondary amine is the one in which only two hydrogen atoms in ammonia is replaced by a hydrocarbon group.  Tertiary amine is the one in which all three hydrogen atoms in ammonia is replaced by a hydrocarbon group.  The generalized structural formula for all the amines is,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  7

Amides are also organic derivative.  In an amide, the nitrogen atom is bonded to a carbonyl group.  The general structural formula of amide can be given as shown below,

Organic And Biological Chemistry, Chapter 6, Problem 6.10EP , additional homework tip  8

The difference between amine and amide is that in amine, the nitrogen atom is bonded to a hydrocarbon chain.  In case of amides, the nitrogen atom is bonded to a carbonyl group.

Blurred answer
Students have asked these similar questions
The table includes macrostates characterized by 4 energy levels (&) that are equally spaced but with different degrees of occupation. a) Calculate the energy of all the macrostates (in joules). See if they all have the same energy and number of particles. b) Calculate the macrostate that is most likely to exist. For this macrostate, show that the population of the levels is consistent with the Boltzmann distribution. macrostate 1 macrostate 2 macrostate 3 ε/k (K) Populations Populations Populations 300 5 3 4 200 7 9 8 100 15 17 16 0 33 31 32 DATO: k = 1,38×10-23 J K-1
Don't used Ai solution
In an experiment, the viscosity of water was measured at different temperatures and the table was constructed from the data obtained. a) Calculate the activation energy of viscous flow (kJ/mol). b) Calculate the viscosity at 30°C. T/°C 0 20 40 60 80 η/cpoise 1,972 1,005 0,656 0,469 0,356

Chapter 6 Solutions

Organic And Biological Chemistry

Ch. 6.4 - Prob. 1QQCh. 6.4 - Prob. 2QQCh. 6.5 - Prob. 1QQCh. 6.5 - Prob. 2QQCh. 6.5 - Prob. 3QQCh. 6.6 - Prob. 1QQCh. 6.6 - Prob. 2QQCh. 6.6 - Prob. 3QQCh. 6.7 - Prob. 1QQCh. 6.7 - Prob. 2QQCh. 6.7 - Prob. 3QQCh. 6.8 - Prob. 1QQCh. 6.8 - Prob. 2QQCh. 6.8 - Prob. 3QQCh. 6.8 - Prob. 4QQCh. 6.9 - Prob. 1QQCh. 6.9 - Prob. 2QQCh. 6.10 - Prob. 1QQCh. 6.10 - Prob. 2QQCh. 6.10 - Prob. 3QQCh. 6.10 - Prob. 4QQCh. 6.11 - Prob. 1QQCh. 6.11 - Prob. 2QQCh. 6.11 - Prob. 3QQCh. 6.12 - Prob. 1QQCh. 6.12 - Prob. 2QQCh. 6.12 - Prob. 3QQCh. 6.12 - Prob. 4QQCh. 6.13 - Prob. 1QQCh. 6.13 - Prob. 2QQCh. 6.13 - Prob. 3QQCh. 6.13 - Prob. 4QQCh. 6.14 - Prob. 1QQCh. 6.14 - Prob. 2QQCh. 6.14 - Prob. 3QQCh. 6.15 - Prob. 1QQCh. 6.15 - Prob. 2QQCh. 6.16 - Prob. 1QQCh. 6.16 - Prob. 2QQCh. 6.16 - Prob. 3QQCh. 6.17 - Prob. 1QQCh. 6.17 - Prob. 2QQCh. 6.17 - Prob. 3QQCh. 6.18 - Prob. 1QQCh. 6.18 - Prob. 2QQCh. 6.18 - Prob. 3QQCh. 6.19 - Prob. 1QQCh. 6.19 - Prob. 2QQCh. 6.19 - Prob. 3QQCh. 6.19 - Prob. 4QQCh. 6 - Prob. 6.1EPCh. 6 - Prob. 6.2EPCh. 6 - Prob. 6.3EPCh. 6 - Prob. 6.4EPCh. 6 - Prob. 6.5EPCh. 6 - Prob. 6.6EPCh. 6 - Prob. 6.7EPCh. 6 - Indicate whether or not each of the following...Ch. 6 - Indicate whether each of the compounds in Problem...Ch. 6 - Prob. 6.10EPCh. 6 - Prob. 6.11EPCh. 6 - Prob. 6.12EPCh. 6 - Prob. 6.13EPCh. 6 - Prob. 6.14EPCh. 6 - Prob. 6.15EPCh. 6 - Prob. 6.16EPCh. 6 - Prob. 6.17EPCh. 6 - Assign an IUPAC name to each of the following...Ch. 6 - Prob. 6.19EPCh. 6 - Prob. 6.20EPCh. 6 - Prob. 6.21EPCh. 6 - Prob. 6.22EPCh. 6 - Prob. 6.23EPCh. 6 - Prob. 6.24EPCh. 6 - Prob. 6.25EPCh. 6 - Classify each of the following compounds as a 1...Ch. 6 - Prob. 6.27EPCh. 6 - Prob. 6.28EPCh. 6 - Prob. 6.29EPCh. 6 - Prob. 6.30EPCh. 6 - Prob. 6.31EPCh. 6 - Prob. 6.32EPCh. 6 - Prob. 6.33EPCh. 6 - Prob. 6.34EPCh. 6 - Determine the maximum number of hydrogen bonds...Ch. 6 - Prob. 6.36EPCh. 6 - Although they have similar molecular masses (73...Ch. 6 - Prob. 6.38EPCh. 6 - Prob. 6.39EPCh. 6 - Prob. 6.40EPCh. 6 - Show the structures of the missing substance(s) in...Ch. 6 - Prob. 6.42EPCh. 6 - Prob. 6.43EPCh. 6 - Prob. 6.44EPCh. 6 - Prob. 6.45EPCh. 6 - Prob. 6.46EPCh. 6 - Prob. 6.47EPCh. 6 - Prob. 6.48EPCh. 6 - Prob. 6.49EPCh. 6 - Prob. 6.50EPCh. 6 - Prob. 6.51EPCh. 6 - Prob. 6.52EPCh. 6 - Prob. 6.53EPCh. 6 - Prob. 6.54EPCh. 6 - Prob. 6.55EPCh. 6 - Prob. 6.56EPCh. 6 - Prob. 6.57EPCh. 6 - Prob. 6.58EPCh. 6 - Prob. 6.59EPCh. 6 - Prob. 6.60EPCh. 6 - Prob. 6.61EPCh. 6 - Prob. 6.62EPCh. 6 - Prob. 6.63EPCh. 6 - Prob. 6.64EPCh. 6 - Prob. 6.65EPCh. 6 - Prob. 6.66EPCh. 6 - Prob. 6.67EPCh. 6 - Prob. 6.68EPCh. 6 - Prob. 6.69EPCh. 6 - Prob. 6.70EPCh. 6 - Prob. 6.71EPCh. 6 - Prob. 6.72EPCh. 6 - Prob. 6.73EPCh. 6 - Prob. 6.74EPCh. 6 - Name each of the salts in Problem 17-71. a....Ch. 6 - Prob. 6.76EPCh. 6 - Indicate whether or not each of the following...Ch. 6 - Prob. 6.78EPCh. 6 - Prob. 6.79EPCh. 6 - Prob. 6.80EPCh. 6 - Prob. 6.81EPCh. 6 - Prob. 6.82EPCh. 6 - Prob. 6.83EPCh. 6 - Prob. 6.84EPCh. 6 - Prob. 6.85EPCh. 6 - Prob. 6.86EPCh. 6 - Prob. 6.87EPCh. 6 - Prob. 6.88EPCh. 6 - Prob. 6.89EPCh. 6 - Prob. 6.90EPCh. 6 - Prob. 6.91EPCh. 6 - Indicate whether each of the following statements...Ch. 6 - Prob. 6.93EPCh. 6 - Prob. 6.94EPCh. 6 - Prob. 6.95EPCh. 6 - Prob. 6.96EPCh. 6 - Prob. 6.97EPCh. 6 - Prob. 6.98EPCh. 6 - Indicate whether or not each of the following...Ch. 6 - Prob. 6.100EPCh. 6 - Classify each of the following amides as...Ch. 6 - Classify each of the following amides as...Ch. 6 - Prob. 6.103EPCh. 6 - Prob. 6.104EPCh. 6 - Prob. 6.105EPCh. 6 - Prob. 6.106EPCh. 6 - Prob. 6.107EPCh. 6 - Assign an IUPAC name to each of the following...Ch. 6 - Prob. 6.109EPCh. 6 - Prob. 6.110EPCh. 6 - Prob. 6.111EPCh. 6 - Prob. 6.112EPCh. 6 - Prob. 6.113EPCh. 6 - Prob. 6.114EPCh. 6 - Prob. 6.115EPCh. 6 - Prob. 6.116EPCh. 6 - Prob. 6.117EPCh. 6 - Prob. 6.118EPCh. 6 - Prob. 6.119EPCh. 6 - Prob. 6.120EPCh. 6 - Prob. 6.121EPCh. 6 - Prob. 6.122EPCh. 6 - Prob. 6.123EPCh. 6 - Prob. 6.124EPCh. 6 - Prob. 6.125EPCh. 6 - Prob. 6.126EPCh. 6 - Prob. 6.127EPCh. 6 - Prob. 6.128EPCh. 6 - Prob. 6.129EPCh. 6 - Prob. 6.130EPCh. 6 - Prob. 6.131EPCh. 6 - Prob. 6.132EPCh. 6 - Prob. 6.133EPCh. 6 - Prob. 6.134EPCh. 6 - Prob. 6.135EPCh. 6 - Prob. 6.136EPCh. 6 - Prob. 6.137EPCh. 6 - Prob. 6.138EPCh. 6 - Prob. 6.139EPCh. 6 - Prob. 6.140EPCh. 6 - Prob. 6.141EPCh. 6 - Prob. 6.142EPCh. 6 - Prob. 6.143EPCh. 6 - Prob. 6.144EPCh. 6 - Prob. 6.145EPCh. 6 - Draw the structure of the nitrogen-containing...Ch. 6 - Prob. 6.147EPCh. 6 - Prob. 6.148EPCh. 6 - Prob. 6.149EPCh. 6 - Prob. 6.150EPCh. 6 - Prob. 6.151EPCh. 6 - Prob. 6.152EPCh. 6 - Prob. 6.153EPCh. 6 - Prob. 6.154EP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Organic And Biological Chemistry
Chemistry
ISBN:9781305081079
Author:STOKER, H. Stephen (howard Stephen)
Publisher:Cengage Learning,
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Nomenclature: Crash Course Chemistry #44; Author: CrashCourse;https://www.youtube.com/watch?v=U7wavimfNFE;License: Standard YouTube License, CC-BY