Chapter 5, Problem 5.60P

Interpretation Introduction

Interpretation: The molar mass of the unknown gas that effuses in 11.1 min needs to be determined.

Concept Introduction:

Graham's Law of effusion of gases states that at same conditions, the effusion rate of two gases vary inversely with the square roots of molar masses of the gases. The mathematical expression for the Graham’s law for two gases ‘a’ and ‘b’ can be written as:

  $\frac{{\text{Rate}}_{\text{(a)}}}{{\text{Rate}}_{\text{(b}}{}_{\text{)}}}=\sqrt{\frac{{\text{Molar mass }}_{\text{(b)}}}{{\text{Molar mass}}_{\text{(a}}{}_{\text{)}}}}$