Concept explainers
(a)
Interpretation:Whethercurve 1 or 2 isa better representation of the behavior of Argon gas needs to be determined.
Concept Introduction:
The ideal gas equation can be used to calculate P, V, T and number of moles of gases. It is the combination of different
Kinetic-molecular theory of gases states that:
- Gases are composed of hard, spherical particles.
- These particles remain in a state of constant, random motion in a straight line.
- The collision between gas particles and the wall of the container causes gas pressure.
- The gas particles are very small with no force of attraction between them.
- The volume of gas particles is negligible as compared to the volume of the container because there is a large space between gas particles.
(b)
Interpretation:Whether curve 1 or 2 represents the gas that effuses more slowly needs to be determined.
Concept Introduction:
The ideal gas equation can be used to calculate P, V, T and number of moles of gases. It is the combination of different gas laws such as Boyle’s law, Charles’s law, Gay-Lussac
Kinetic-molecular theory of gases states that:
- Gases are composed of hard, spherical particles.
- These particles remain in a state of constant, random motion in a straight line.
- The collision between gas particles and the wall of the container causes gas pressure.
- The gas particles are very small with no force of attraction between them.
- The volume of gas particles is negligible as compared to the volume of the container because there is a large space between gas particles.
(c)
Interpretation:Curve 1 or 2 which represents the behavior of fluorine gas needs to be determined.
Concept Introduction:
The ideal gas equation can be used to calculate P, V, T and number of moles of gases. It is the combination of different gas laws such as Boyle’s law, Charles’s law, Gay-Lussac
Kinetic-molecular theory of gases states that:
- Gases are composed of hard, spherical particles.
- These particles remain in a state of constant, random motion in a straight line.
- The collision between gas particles and the wall of the container causes gas pressure.
- The gas particles are very small with no force of attraction between them.
- The volume of gas particles is negligible as compared to the volume of the container because there is a large space between gas particles.
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Chapter 5 Solutions
Principles of General Chemistry
- Complete boxes in the flow chart. Draw the structure of the organic compound foundin each layer after adding 3M NaOH and extraction. Make sure to include any charges. Provide explanation on answers.arrow_forward== Vid4Q2 Unanswered ☑ Provide IUPAC name of product in the reaction below A 3,4-dimethylcyclohexene B 1,2-dimethylcyclohexane C 1,2-dimethylcyclohexene D 3,4-dimethylcyclohexane H₂ Pdarrow_forward5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.arrow_forward
- Nonearrow_forwardStereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)arrow_forwardNonearrow_forward
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