Chapter 5, Problem 5.16P

Interpretation Introduction

Interpretation:

The temperature in $°\text{C}$ should be determined which is required to reduce the volume to 2.50 L.

Concept Introduction:

Charles’s Law gives the relationship between Volume (V) and Temperature (T)

According to Charles’s Law, the volume of gas has direct relationship with temperature of the gas if pressure and amount of a gas are constant.

  $\frac{\text{V}}{\text{T}}$ = constant

  $\text{VαT}$

If the temperature or volume of a gas changes without any change in amount of a gas and pressure, then the final volume and temperature will give the same $\frac{\text{V}}{\text{T}}$ as the initial volume and temperature. Then, a relationship between initial and final $\frac{\text{V}}{\text{T}}$ can be set as equal to each other.

Charles’s Law can be written as:

  $\frac{{\text{V}}_{\text{1}}}{{\text{T}}_{\text{1}}}\text{=}\frac{{\text{V}}_{\text{2}}}{{\text{T}}_{\text{2}}}$ (Pressure and amount of a gas remain constant)

Where, T₁ and V₁ are the initial temperature and volume.

T₂ and V₂ are the final temperature and volume.