University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 38, Problem 38.9DQ
To determine
The reason for the photocurrent to have the same value for large positive values of
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Check out a sample textbook solutionStudents have asked these similar questions
In a photoelectric experiments, a graph of the light frequency f is
plotted against the maximum kinetic energy Kmax of the
photoelectron as shown in Figure below
fx10“Hz
4.83
K (eV)
max
Based on the graph, for the light of frequency 7.14 x1014 Hz, calculate
a. the threshold wavelength,
b. the maximum speed of the photoelectron.
(Given c =3.00x10® m s1, h =6.63 x 1034ª J s, me=9.11 x 1031 kg, mp=1.67 x 1027 kg
and e=1.60x1019 C)
UV radiation having a wavelength of 84 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case, so you can just use the standard formula KE =12mv2.
The correct answer is 1.87E6 m/s how do I get that?
In aphotoelectric effect experiment, light of frequency 1.15x10-15 Hz strikes a metal
surface and electrons are emitted immediately. The work function of the metal is
2.3 eV. Calculate the
8.
(a)
threshold frequency of the metal.
(b)
maximum kinetic energy of the photoelectrons.
(c)
stopping potential of the photoelectrons.
Chapter 38 Solutions
University Physics with Modern Physics (14th Edition)
Ch. 38.1 - Silicon films become better electrical conductors...Ch. 38.2 - Prob. 38.2TYUCh. 38.3 - Prob. 38.3TYUCh. 38.4 - Prob. 38.4TYUCh. 38 - Prob. 38.1DQCh. 38 - Prob. 38.2DQCh. 38 - Prob. 38.3DQCh. 38 - Prob. 38.4DQCh. 38 - Prob. 38.5DQCh. 38 - Prob. 38.6DQ
Ch. 38 - Prob. 38.7DQCh. 38 - Prob. 38.8DQCh. 38 - Prob. 38.9DQCh. 38 - Prob. 38.10DQCh. 38 - Prob. 38.11DQCh. 38 - Prob. 38.12DQCh. 38 - Prob. 38.13DQCh. 38 - Prob. 38.14DQCh. 38 - Prob. 38.15DQCh. 38 - Prob. 38.16DQCh. 38 - Prob. 38.17DQCh. 38 - Prob. 38.1ECh. 38 - Prob. 38.2ECh. 38 - Prob. 38.3ECh. 38 - Prob. 38.4ECh. 38 - Prob. 38.5ECh. 38 - Prob. 38.6ECh. 38 - Prob. 38.7ECh. 38 - Prob. 38.8ECh. 38 - Prob. 38.9ECh. 38 - Prob. 38.10ECh. 38 - Prob. 38.11ECh. 38 - Prob. 38.12ECh. 38 - Prob. 38.13ECh. 38 - Prob. 38.14ECh. 38 - Prob. 38.15ECh. 38 - Prob. 38.16ECh. 38 - Prob. 38.17ECh. 38 - Prob. 38.18ECh. 38 - Prob. 38.19ECh. 38 - Prob. 38.20ECh. 38 - Prob. 38.21ECh. 38 - An electron and a positron are moving toward each...Ch. 38 - Prob. 38.23ECh. 38 - Prob. 38.24ECh. 38 - Prob. 38.25ECh. 38 - Prob. 38.26PCh. 38 - Prob. 38.27PCh. 38 - Prob. 38.28PCh. 38 - Prob. 38.29PCh. 38 - Prob. 38.30PCh. 38 - Prob. 38.31PCh. 38 - Prob. 38.32PCh. 38 - Prob. 38.33PCh. 38 - Prob. 38.34PCh. 38 - Prob. 38.35PCh. 38 - Prob. 38.36PCh. 38 - Prob. 38.37PCh. 38 - Prob. 38.38PCh. 38 - Prob. 38.39PCh. 38 - Prob. 38.40CPCh. 38 - Prob. 38.41PPCh. 38 - Prob. 38.42PPCh. 38 - Prob. 38.43PPCh. 38 - Prob. 38.44PPCh. 38 - Prob. 38.45PP
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- s) The cutoff frequency of a specific metal is known to be 0.72x1015Hz. During a photoelectric experiment, 3.7x102º photons with a wavelength of 167nm are striking a plate every second. What is the power of the photons and what is the maximum kinetic energy of the ejected electrons?arrow_forwardd) In a photoelectric experiment using a photocell, the graph of stopping potential Vs against frequency f of incident light as shown in FIGURE 6 is obtained. From the graph, deduce (i) the threshold frequency. (ii) the value of maximum kinetic energy when incident light frequency is 5.0✕1014 Hz. (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C) (iii) Determine the value of stopping potential Vs. (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C)arrow_forwardThe work function for aluminum is 4.08 eV. Ultraviolet light of wavelength 156 nm is incident on the clean surface of an aluminum sample.(a). What is the maximum kinetic energy of the ejected photoelectrons?(b). What stopping voltage would be required to arrest the current of photoelectrons?(c). Calculate the cut off frequency of aluminum.arrow_forward
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