Concept explainers
(a)
The number of photoelectrons will most likely be reduced by a factor of
(b)
The maximum kinetic energy of the ejected photoelectrons will most likely be reduced by a factor of
(c)
The maximum speed of the ejected photoelectrons will most likely be reduced by a factor of
(d)
The maximum speed of the ejected photoelectrons will most likely be reduced by a factor of
(e)
The time for the first photoelectron to be ejected will be increased by a factor of
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University Physics with Modern Physics (14th Edition)
- The work function of a photoelectric surface is 2.00 eV. What is the maximum speed of the photoelectrons emitted from this surface when a 450-nm light falls on it?arrow_forwardWhen monochromatic light of an unknown wavelength falls on a sample of silver, a minimum potential of 2.50 V is required to stop all of the ejected photoelectrons. Determine the (a) maximum kinetic energy and (b) maximum speed of the ejected photoelectrons. (c) Determine the wavelength in nm of the incident light. (The work function for silver is 4.73 eV.)arrow_forwardThe graph below shows the maximum kinetic energy of emitted photoelectrons as a function of the energy of the photons that are incident on a particular surface. From this graph, determine the following: a) the work function (in eV) 2) the threshold frequency (in Hz) Thank you for the help!arrow_forward
- Explain giving reasons for the following: (a) Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation. (b) The stopping potential (V0) varies linearly with the frequency (v) of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces. (c) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.arrow_forwardA light of wavelength 352 nm with an intensity 2.00 W/m' is directed at a metallic surface. Only 0.60% of incident photons will produce photoelectrons. Calculate the number of photoelectrons emitted per second if the metallic surface has area of 2.00 cm². (a) 4.26x10 photoelectron/s (b) 7.09x10" photoelectron/s (c) 7.09x10 photoelectron/s (d) 4.26x10 photoelectron/sarrow_forwardWhen monochromatic light of an unknown wavelength falls on a sample of silver, a minimum potential of 2.69 V is required to stop all of the ejected photoelectrons. (The work function for silver is 4.73 eV.) HINT (a) Determine the maximum kinetic energy (in eV) of the ejected photoelectrons. eV (b) Determine the maximum speed (in m/s) of the ejected photoelectrons. m/s (c) Determine the wavelength in nm of the incident light. nmarrow_forward
- When ultraviolet light with a wavelength of 400.0 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 eV. (a) What is the work function of the metal surface? (b) What is the maximum kinetic energy of the photoelectrons when light of wavelength 300.0 nm falls on the same surface?arrow_forward(a) In a photoelectric effect experiment, a target material is irradiated with a beam of monochromatic light. State one factor that causes the rate of emission of photoelectrons to increase. (b) Explain how the photoelectric effect was conducted with a diagram. (c) The energy of an ultraviolet light is 3.28 eV. (i) What is its wavelength? (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C). (ii) Based on the de Broglie's hypothesis, determine the velocity of the electron. (Given: h=6.63✕10-34 Js ; me=9.11✕10-31 kg) d) In a photoelectric experiment using a photocell, the graph of stopping potential Vs against frequency f of incident light as shown in FIGURE 6 is obtained. From the graph, deduce (i) the threshold frequency. (ii) the value of maximum kinetic energy when incident light frequency is 5.0✕1014 Hz. (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C) (iii) Determine the value of stopping potential Vs. (Given: h=6.63✕10-34 Js ; e=1.602✕10-19 C)arrow_forwardA metal surface is illuminated with light of different wavelengths and the corresponding stopping potentials of the photoelectrons are shown in the Table below. A (A) 5581 61566731 V (V)1,05 0,86 0,67 Using the Table, determine the photoelectric threshold wavelength (in Å).arrow_forward
- A 90nm radiation falls on a photoelectric surface, and the work function of photoelectrode is 4.3 ev. The Plank's constant is 6.625 x 1034 J.s and mass of electron is 9.11 x 1031 kg. Determine ) The maximum kinetic energy of the electrons in Joules: () The velocity of the photoelectrons in m/s:| (C) The stopping potential in Volts. when the same surface is illuminated with light of wavelength 205 nmarrow_forwardA source emits monochromatic light of frequency 5.0 × 1014 Hz at a rate of 0.20W. Of the photons given out, 0.25% falls on the cathode of photocell which gives a current of 9.0µA in an external circuit. You may assume this current consists of all the photoelectrons emitted. Calculate:(i.) the energy of a photon,(ii.) the number of photons leaving the source per second,(iii.) the percentage of photons falling on the cathode which produce photoelectrons.arrow_forwardThe energy conservation principle that applies to the photoelectric experiment is Ephoton = (KE)electron + W, where W is the “work function” for the metal. (The work function is the minimum energy required to eject an electron from the metal surface.) The work function for calcium metal is 4.60 10−19 J. If calcium is irradiated with 400-nm photons, what is the de Broglie wavelength of the resulting photoelectron beam?arrow_forward
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