University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 38, Problem 38.21E
To determine
The scattering angle of the scattered x-rays.
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In a Compton scattering experiment, the incident X-rays have a wavelength of 0.2686 nm, and the scattered X-rays have a wavelength of 0.2707 nm. Through what angle θ in the drawing are the X-rays scattered?
You use 0.124 nm x-ray photons in a Compton-scattering experiment. (a) At what angle is the wavelength of the scattered x rays 1.0% longer than that of the incident x rays? (b) At what angle is it 0.050% longer?
37
Chapter 38 Solutions
University Physics with Modern Physics (14th Edition)
Ch. 38.1 - Silicon films become better electrical conductors...Ch. 38.2 - Prob. 38.2TYUCh. 38.3 - Prob. 38.3TYUCh. 38.4 - Prob. 38.4TYUCh. 38 - Prob. 38.1DQCh. 38 - Prob. 38.2DQCh. 38 - Prob. 38.3DQCh. 38 - Prob. 38.4DQCh. 38 - Prob. 38.5DQCh. 38 - Prob. 38.6DQ
Ch. 38 - Prob. 38.7DQCh. 38 - Prob. 38.8DQCh. 38 - Prob. 38.9DQCh. 38 - Prob. 38.10DQCh. 38 - Prob. 38.11DQCh. 38 - Prob. 38.12DQCh. 38 - Prob. 38.13DQCh. 38 - Prob. 38.14DQCh. 38 - Prob. 38.15DQCh. 38 - Prob. 38.16DQCh. 38 - Prob. 38.17DQCh. 38 - Prob. 38.1ECh. 38 - Prob. 38.2ECh. 38 - Prob. 38.3ECh. 38 - Prob. 38.4ECh. 38 - Prob. 38.5ECh. 38 - Prob. 38.6ECh. 38 - Prob. 38.7ECh. 38 - Prob. 38.8ECh. 38 - Prob. 38.9ECh. 38 - Prob. 38.10ECh. 38 - Prob. 38.11ECh. 38 - Prob. 38.12ECh. 38 - Prob. 38.13ECh. 38 - Prob. 38.14ECh. 38 - Prob. 38.15ECh. 38 - Prob. 38.16ECh. 38 - Prob. 38.17ECh. 38 - Prob. 38.18ECh. 38 - Prob. 38.19ECh. 38 - Prob. 38.20ECh. 38 - Prob. 38.21ECh. 38 - An electron and a positron are moving toward each...Ch. 38 - Prob. 38.23ECh. 38 - Prob. 38.24ECh. 38 - Prob. 38.25ECh. 38 - Prob. 38.26PCh. 38 - Prob. 38.27PCh. 38 - Prob. 38.28PCh. 38 - Prob. 38.29PCh. 38 - Prob. 38.30PCh. 38 - Prob. 38.31PCh. 38 - Prob. 38.32PCh. 38 - Prob. 38.33PCh. 38 - Prob. 38.34PCh. 38 - Prob. 38.35PCh. 38 - Prob. 38.36PCh. 38 - Prob. 38.37PCh. 38 - Prob. 38.38PCh. 38 - Prob. 38.39PCh. 38 - Prob. 38.40CPCh. 38 - Prob. 38.41PPCh. 38 - Prob. 38.42PPCh. 38 - Prob. 38.43PPCh. 38 - Prob. 38.44PPCh. 38 - Prob. 38.45PP
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- A photon undergoes Compton scattering off a stationary free electron. The photon scatters at 90.0° from its initial direction; its initial wavelength is 3.00*10-12 m. What is the electron’s kinetic energy?arrow_forwardA photon with wavelength X scatters off an electron at rest, at an angle with the incident direction. The Compton wavelength of the electron Ac = 0.0024 nm. a) For λ = 0.0006 nm and 0 = 53 degrees, find the wavelength X' of the scattered photon in nanometres. b) Obtain a formula for the energy of the electron Ee after collision, in terms of the universal constants h, c and the variables X, X' and Ac. The answer must be expressed in terms of these variables only. (Please enter an algebraic expression using latex format; do not input any numerical values) c) Using the energy conservation condition, find the value of the electron energy Ee after scattering in units of keV. d) Write an algebraic expression for the electron's momentum pe in terms of its energy Ee, its mass me and the speed of light c. e) What is the de Broglie wavelength of the scattered electron ? Express your answer in terms of Ee, me, and X and c. f) Find the value of the de Broglie wavelength of the scattered electron…arrow_forwardX-ray with wavelength 0.2 nm are scattered from a carbon block. The scattered radiation is viewed at right angle to the direction of the incident beam. What is the Compton shift?arrow_forward
- X-ray with wavelength 0.2 nm are scattered from a carbon block. The scattered radiation is viewed at 600 to the direction of the incident beam. What is the Compton shift?arrow_forwardX-rays with a wavelength of 120.0 pm undergo Compton scattering. Find the wavelengths of the photons scattered at angle of 30.0°?arrow_forwardYou use 0.124 nm x-ray photons in a Compton-scattering experiment. At what angle is the wavelength of the scattered x rays 1.0% longer than that of the incident x rays? 70.6° 67.0° 60.7° 56.5°arrow_forward
- A beam of neutrons that all have the same energy scatters from atoms that have a spacing of 0.0910 nm in the surface plane of a crystal. The m = 1 intensity maximum occurs when the angle u in Fig. is 28.6°. What is the kinetic energy (in electron volts) of each neutron in the beam?arrow_forwardIn a Rutherford scattering experiment a target nucleus has a diameter of 1.4×10-14 m. The incoming has a mass of 6.64×10-27 kg. What is the kinetic energy of an particle that has a de Broglie wavelength equal to the diameter of the target nucleus? Ignore relativistic effects.arrow_forwardAfter a 0.8 mm x-ray photon scatters from a free electron, the electron recoils at 1.4 x 106 m/s. (a) What is the Compton shift in the photon's wavelength? (b) Through what angle is the photon scattered?arrow_forward
- You are working in an x-ray laboratory. You have a source of x-rays with a wavelength of 0.115 nm. In the experiment you are performing, you need x-rays with a slightly longer wavelength than this. You decide to use Compton scattering from electrons to increase the wavelength of the x-rays. For theexperiment, you need to determine (a) at what angle x-rays with a wavelength 1.2% larger than those from your source will be scattered. (b) You also need to determine the longest possible wavelength you can achieve with Compton scattering.arrow_forwardX-ray photons of wavelength 0.0248 nm are incident on a target and the Compton-scattered photons are observed at 80.0° above the photons' incident line of travel. [Use relativistic units for this problem!] (a) What is the wavelength of the scattered photons? nm (b) What is the momentum of the incident photons? eV/c What is the momentum of the scattered photons? eV/c (c) What is the kinetic energy of the scattered electrons? eV (d) What is the momentum (magnitude and angle) of the scattered electrons? eV/carrow_forwardPhotons that have a wavelength of 0.00226 nm are Compton scattered off stationary electrons at 33.0 degrees. What is the energy E of the scattered photons? E = ? Jarrow_forward
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