Chapter 23, Problem 30P

To determine

The angle of refraction.

Answer to Problem 30P

Solution:

The angle of refraction $\angle r={50.1}^o$

Explanation of Solution

Given Info:

Refractive index of air $n_{air}=1.0$

Refractive index of water $n_{water}=1.33$

Angle of incident $\angle i={35.2}^o$

Let the angle of refraction be $\angle r$

Formula Used:

Apply Snell’s Law

$n_{water}\sin \angle i=n_{air}\sin \angle r$

Here, all alphabets are in their usual meanings.

Calculation:

Apply Snell’s Law

$\begin{array}{l}{n}_{water}\sin \angle i=n_{air}\sin \angle r\\ or,\sin \angle r=\frac{n_{water}\sin \angle i}{n_{air}}\\ or,\sin \angle r=\frac{\left(1.33\right)\sin {35.2}^o}{1.0}\\ or,\angle r={50.1}^o\end{array}$