Chapter 23, Problem 26P

To determine

The refractive index of ice.

Answer to Problem 26P

Solution:

The refractive index of ice $n=1.31$

Explanation of Solution

Given Info:

Speed of light in ice $v_i=2.29\times {10}^8\text{m/s}$

Speed of light in vacuum $c=3.0\times {10}^8\text{m/s}$

Let the refractive index of ice be ‘n’.

Formula Used:

The refractive index of ice $n=\frac{c}{v_i}$

Here, all alphabets are in their usual meanings.

Calculation:

The refractive index of ice $n=\frac{c}{v_i}$

$\begin{array}{l}n=\frac{\text{3}{\text{.0×10}}^{\text{8}}\text{m/s}}{\text{2}{\text{.29×10}}^{\text{8}}\text{m/s}}\\ n=1.31\end{array}$