Concept explainers
(a) To Determine:
the distance by which the image is shifted if the object is moved closer to the lens.
Answer to Problem 53P
Solution:
Explanation of Solution
Given:
Initially object is located from a lens i.e., Object distance, . Power, .
Formula used:
Lens equation,
and are lens to object and lens to image distances respectively, negative when opposite to optical path and positive when in the direction of optical path.
Magnification:
Power,
Where f is in mm
Calculation:
Given that , thus we can calculate focal length using the formula
Thus, the position of the image formed can be calculated using Lens formula-
Here value of and are given, i.e., and . Thus substituting them in formula we get-
If the object is moved closer to the lens,
Thus, the position of the image formed after the shift can be calculated using Lens formula-
Here value of and are given, i.e., and . Thus substituting them in formula we get-
Change is
(Image moves further)
(b) To Determine:
the distance by which the image is shifted if the object is moved farther from the lens.
Answer to Problem 53P
Solution:
Explanation of Solution
Given:
Initially object is located from a lens i.e., Object distance, . Power, .
Formula used:
Lens equation,
and are lens to object and lens to image distances respectively, negative when opposite to optical path and positive when in the direction of optical path.
Magnification:
Power,
Where f is in mm
Calculation:
If the object is moved farther from the lens,
Thus, the position of the image formed after the shift can be calculated using Lens formula-
Here value of and are given, i.e., and . Thus substituting them in formula we get-
Change is
(Image moves closer to the lens)
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Physics: Principles with Applications
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