Concept explainers
(a) To Determine:
A ray diagram and estimate the location and the relative size of the final image
Answer to Problem 65P
Solution:
Explanation of Solution
Given:
A lighted candle is placed in front of a converging lens of focal length , which in in front of another converging lens of focal length .
Formula used:
Lens equation,
and are lens to focal, lens to object and lens to image distances repectively, negative when opposite to optical path and positive when in the direction of optical path.
Magnification,
Calculation:
Ray diagram logic of the location and the relative size of the final image when a lighted candle is placed in front of a converging lens of focal length , which in in front of another converging lens of focal length is shown below-
Here we can observe that image is real and diminished.
(b)
The value of position and relative size of the final image.
Answer to Problem 65P
Solution:
Final image will be formed at the right of 2nd lens with magnification of .
Explanation of Solution
Given:
A lighted candle is placed in front of a converging lens of focal length , which in in front of another converging lens of focal length .
Formula used:
Lens equation,
and are lens to focal, lens to object and lens to image distances repectively, negative when opposite to optical path and positive when in the direction of optical path.
Magnification,
Calculation:
Positions of the candle and its first image with respect to first lens are and .Using lens equation,
This gives,
Position of the first image with respect to second lens is
Considering to be the position of the final image with respect to second lens,
This gives,
The total magnification i.e. the relative size of the candle is
.
Chapter 23 Solutions
Physics: Principles with Applications
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