Concept explainers
Part (a) To Determine:
The nature of lens and its focal length if the image is at 8.20 cm in front of the lens.
Answer to Problem 86GP
Solution:
The lens will be diverging or concave and its focal length will be also the nature of image will be virtual, if the image is at 8.20 cm in front of the lens.
Explanation of Solution
Given Info:
Object distance
Image distance
Let the focal length of lens be ‘f’
Formula Used:
Apply focal length formula for lens
Here, all alphabets are in their usual meanings.
Calculation:
Since Object and image both are on the same side of the lens and . Hence, the given lens must be diverging or concave lens.
Apply focal length formula for lens.
Since the given lend is diverging lens and its focal length is negative. Hence, the image will always be virtual.
Part (b) To Determine:
The nature of lens and its focal length if the image is at 44.5 cm in front of the lens.
Answer to Problem 86GP
Solution:
The lens will be converging or convex and its focal length will be also the nature of image will be virtual, if the image is at 8.20 cm in front of the lens.
Explanation of Solution
Given Info:
Object distance
Image distance
Let the focal length of lens be ‘f’
Formula Used:
Apply focal length formula for lens
Here, all alphabets are in their usual meanings.
Calculation:
Since Object and image both are on the same side of the lens and . Hence, the given lens must be converging or convex lens.
Apply focal length formula for lens.
Since the given lend is converging lens and its focal length is positive also . Hence the image will again be virtual.
Chapter 23 Solutions
Physics: Principles with Applications
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