Concept explainers
The position and magnification of the final image when an object is placed is placed 96.5 cm from a glass lens (n=1.52)with one concave surface of radius 22 cm and one convex surface of radius 18.5 cm.
Answer to Problem 71P
Solution:
The image position is 169.75 cm from the lens in the object side and the magnification is 1.75
Explanation of Solution
Formula used:
lens maker’s formula where f is the focal length, r1 is the radius of curvature of first surfce and r2 is radius of curvature (RoC)of second surface of the lens. n is the refractive index of the lens material.
Lens equation,
u and v are lens to object and lens to image distances repectively, negative when opposite to optical path and positive when in the direction of optical path.
Magnification,
Calculation:
For first concave surface the sign of RoC is negative as it is opposite to optical path.
Thus, r1=-22 cm
For second convex surface the sign of RoC is negative as it is opposite to optical path.
Thus, r2=-18.5 cm
n=1.52
Thus,
u=-96.5 cm
Using lens equation,
This gives, v=-169.75 cm
Magnification, m=169.75/96.5=1.76.
Chapter 23 Solutions
Physics: Principles with Applications
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