Concept explainers
To Explain:
A white beam of parallel light enters water at an angle, the beam broadens.
Answer to Problem 11Q
Solution:
A beam of white light, each undergoes the above explained refraction, collectively produces the broader beam of refracted rays. Hence, the resultant refracted rays are the broader beam.
Explanation of Solution
The parallel light beams tend to move towards normal as they enter water from air due to the refraction. Since light is falling on the surface at an angle, hence there are beams which fall on the surface first while there are beams which travel longer in the air. Hence different light rays refract at different times and all bend towards normal, causing a spread in the refracted beam of light.
The white light comprises of the seven rays each having different wavelength. In air, the speed is only slightly less. In other transparent materials, such asglass and water, the speed is always less than that in vacuum. The constituent colors are moving with different velocities as it enters the water. Hence, each white ray bents in the water at different angle giving cluster of rays.
Chapter 23 Solutions
Physics: Principles with Applications
Additional Science Textbook Solutions
Campbell Biology (11th Edition)
Campbell Biology in Focus (2nd Edition)
Chemistry: The Central Science (14th Edition)
Human Physiology: An Integrated Approach (8th Edition)
Applications and Investigations in Earth Science (9th Edition)
Organic Chemistry (8th Edition)
- Helicobacter pylori (H. pylori) is a helically-shaped bacterium that is usually found in the stomach. It burrows through the gastric mucous lining to establish an infection in the stomach's epithelial cells (see photo). Approximately 90% of the people infected with H. pylori will never experience symptoms. Others may develop peptic ulcers and show symptoms of chronic gastritis. The method of motility of H. pylori is a prokaryotic flagellum attached to the back of the bacterium that rigidly rotates like a propeller on a ship. The flagellum is composed of proteins and is approximately 40.0 nm in diameter and can reach rotation speeds as high as 1.50 x 103 rpm. If the speed of the bacterium is 10.0 μm/s, how far has it moved in the time it takes the flagellum to rotate through an angular displacement of 5.00 * 10² rad? Zina Deretsky, National Science Foundation/Flickr H. PYLORI CROSSING MUCUS LAYER OF STOMACH H.pylori Gastric Epithelial mucin cells gel Number i 318 Units um H.pylori…arrow_forwardT1. Calculate what is the received frequency when the car drives away from the radar antenna at a speed v of a) 1 m/s ( = 3.6 km/h), b) 10 m/s ( = 36 km/h), c) 30 m /s ( = 108 km/h) . The radar transmission frequency f is 24.125 GHz = 24.125*10^9 Hz, about 24 GHz. Speed of light 2.998 *10^8 m/s.arrow_forwardNo Chatgpt please will upvotearrow_forward
- No Chatgpt pleasearrow_forwardNo Chatgpt pleasearrow_forward3. A measurement taken from the UW Jacobson Observatory (Latitude: 47.660503°, Longitude: -122.309424°, Altitude: 220.00 feet) when its local sidereal time is 120.00° makes the following observations of a space object (Based on Curtis Problems 5.12 + 5.13): Azimuth: 225.00° Azimuth rate: 2.0000°/s. Elevation: 75.000° Elevation rate: -0.5000°/s Range: 1500.0 km Range rate: -1.0000 km/s a. What are the r & v vectors (the state vector) in geocentric coordinates? (Answer r = [-2503.47 v = [17.298 4885.2 5.920 5577.6] -2.663]) b. Calculate the orbital elements of the satellite. (For your thoughts: what type of object would this be?) (Partial Answer e = 5.5876, 0=-13.74°) Tip: use Curtis algorithms 5.4 and 4.2.arrow_forward
- Consider an isotope with an atomic number of (2(5+4)) and a mass number of (4(5+4)+2). Using the atomic masses given in the attached table, calculate the binding energy per nucleon for this isotope. Give your answer in MeV/nucleon and with 4 significant figures.arrow_forwardA: VR= 2.4 cm (0.1 V/cm) = 0.24 V What do Vector B an C represent and what are their magnitudesarrow_forward4. Consider a cubesat that got deployed below the ISS and achieved a circular orbit of 410 km altitude with an inclination of 51.600°. What is the spacing, in kilometers, between successive ground tracks at the equator: a. Ignoring J2 (Earth's oblateness) effects b. Accounting for J2 effects c. Compare the two results and comment [Partial Answer: 35.7km difference]arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON