Chapter 23, Problem 29P

To determine

The angle of refraction.

Answer to Problem 29P

Solution:

The angle of refraction $\angle r={36.2}^o$

Explanation of Solution

Given Info:

Refractive index of air $n_{air}=1.0$

Refractive index of glass $n_{glass}=1.56$

Angle of incident $\angle i={67}^o$

Let the angle of refraction be $\angle r$

Formula Used:

Apply Snell’s Law

$n_{air}\sin \angle i=n_{glass}\sin \angle r$

Here, all alphabets are in their usual meanings.

Calculation:

Apply Snell’s Law

$\begin{array}{l}{n}_{air}\sin \angle i=n_{glass}\sin \angle r\\ or,\sin \angle r=\frac{n_{air}\sin \angle i}{n_{glass}}\\ or,\sin \angle r=\frac{\left(1.0\right)\sin {67}^o}{1.56}\\ or,\angle r={36.2}^o\end{array}$