Concept explainers
Interpretation:
The structure of melibiose based on the given information is to be identified.
Concept introduction:
舧 Chair conformations: It is the most stable conformation, which accurately shows the spatial arrangement of atoms.
舧 Equatorial bonds are parallel to the average plane of the ring, while axial bonds are perpendicular to the average plane of the ring.
舧 The conformation having bonds at the equatorial positions are more stable than those with bonds at the axial position.
舧 On flipping the cyclohexane ring, axial bonds become equatorial bonds and equatorial bonds becomes axial bond.
舧 Bulkier group acquires equatorial positions to form stable conformer due to steric factors.
舧 The most stable configuration of aldopyranoses is when the
舧 Stereochemistry: The equatorial orientation refers to the spatial arrangement of
舧 The anomeric effect is lowest for sugars with equatorial orientation, which results in lower energetic state, and consequently this type of orientation confers higher stability.
舧 The anomeric effect is highest for sugars with axial orientation, which results in higher energetic state, and consequently this type of orientation confers lower stability.
舧 A carbohydrate is a
舧
舧 Carbohydrates are oxidized by
舧 Aldaric acids are carbohydrates having two carboxylic acids. They are formed due to oxidation reaction of aldoses with dilute
舧 Monosaccharides containing six carbon atoms and an aldehyde group are called aldohexoses.
舧 Alditols are compounds produced from aldoses or ketoses on reduction with certain reagents such as sodium borohydride (
舧
舧 Compounds formed by the reaction of reducing sugars with excess of phenyl hydrazine are called osazones. Osazones are products of oxidation and are produced by all reducing sugars.
舧
舧 Fischer projection is a way of representing the structural formulae of compounds through cross formulation of their open chain structures.
舧 Bromine water is an effective reagent that selectively oxidizes the
舧 Melibiose is a disaccharide carbohydrate with the molecular formula
舧 The aldehyde group of an aldose reacts with three moles of phenylhydrazine to produce phenylosazone at
舧 In aqueous solution, the two anomers and the straight-chain structure of a monosaccharide form an equilibrium mixture between them through the process of mutarotation.
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Organic Chemistry
- An unknown disaccharide is subjected to methylation with CH3I followed by acid hydrolysis. The reaction yields 2,3,4,6-tetra-O-methyl-D-glucose and 2,3,4-tri-O- methyl-D-glucose. Draw the structure of the unknown disaccharide.arrow_forwardCellobiose, a disaccharide obtained by the hydrolysis of cellulose, is composed of two glucose units joined together in a 1→4-β-glycoside bond. What is the structure of cellobiose?arrow_forward(a) Draw the condensed structural formula, and give the name for the dipeptide Pro-Asn. (b) Draw the disaccharide formed by the following two monosaccharide via 1,4-linkage. In your disaccharide structure, circle and label the anomeric carbon and indicate whether you have an alpha (a) or a beta (B) anomer. CH2OH CH₂OH ОН ОН ОН ОН, ОН ОН ОН ОНarrow_forward
- 14. (a) Identify the acetal and the ketal group in the following disaccharide. (b) Decide whether the compound is a non-reducing or reducing sugar. OH НО HƠ HO Н HO Н НО HO 15. (a) Identify the glycosidic bond in the following disaccharide. (b) Decide whether the compound is a non-reducing or reducing sugar. (c) Polysaccharide units are usually bonded together with a or B 1, 6 or 1, 4 linkages. What linkage is used in the disaccharide shown below? s) НО НО НО HO НО -OH OH -H OH CH2OH 16. Draw the structure for 1,4-B-D-galactopyranosyl-D-glucose. ( но- 17. Assign an R/S designation to each chirality center in the following compound: ( CHO НО -OHarrow_forwardIn an aqueous solution, d-glucose exists in equilibrium with two six-membered ring compounds. Draw the structures of these compounds.arrow_forwardDescribe the glycosidic bond in this repeating disaccharide unitarrow_forward
- Which of the following statements about the monosaccharide shown below is correct?arrow_forwardMonosaccharides are cyclic hemiacetals that can react with alcohols to form acetals. The bond between the anomeric carbon atom of the monosaccharide and the oxygen atom of the -OR group is called a glycosidic bond. The name of the linkage contains the designation alpha (a) or beta (B) (from the anomeric carbon in the glycosidic bond) and the carbon numbers for the carbons from the two sugars. For this example, the linkage is an a-1,4 glycosidic bond. Н НО HO اب تاب است H OH H OH -OH Н Н OH H + OH HO a anomer CH₂OH H Н H О OH H2C OH Н H Classify the glycosidic linkage in the disaccharide. Н OH Н H OH OH OH - HO Н H HO OH OH Н CH₂OH H -OH H OH он H H -OH Н OH an a glycosidic bond Н OH + H2O о о о о В-1,6 a-1,6 a-1,1 B-1,5 I DON'T KNOW YET submitarrow_forwardHumans are able to digest amylose, but not cellulose. What structural features of these polysaccharides might be responsible for this? O amylose contains only beta glycosidic bonds where cellulose contains alpha glycosidic bonds O amylose contains only beta glycosidic bonds where cellulose contains alpha glycosidic bonds amylose contains only alpha peptide bonds where cellulose contains beta peptide bonds amylose contains only alpha glycosidic bonds where cellulose contains beta glycosidic bondsarrow_forward
- In solution, glucose is mostly found in the cyclic hemiacetal state, which lacks an aldehyde group. How are mild oxidising agents able to oxidise glucose?arrow_forwardDraw the structures (using chair conformations of pyranoses) of the following disaccharides. a-d-fructofuranosyl-b-d-mannopyranoside(arrow_forward
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