Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 22, Problem 24P
Interpretation Introduction
Interpretation:
The understanding of the specificity of bacterial oxidation for commercial synthesis of the compound vitamin C is to be explained.
Concept Introduction:
▸ The chemical name for vitamin C is L-ascorbic acid. It is obtained commercially by converting the D-sorbitol into the L-ascorbic acid with the formation of an
▸ The process involves two major steps which are the formation of
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One step in the gluconeogenesis pathway for the biosynthesis of glucose is the partial reduction of 3-phosphoglycerate to give glyceraldehyde 3-phosphate. The process occurs by phosphorylation with ATP to give 1,3-bisphosphoglycerate,
reaction with a thiol group on the enzyme to give an enzyme-bound thioester, and reduction with NADH.
-OPO3²- Enz-SH
H-C-OH
ATP
CH₂OPO3²-
3-phosphoglycerate
O
0-0--0
O
ADP
CH₂CH3
substitute for
1,3-bisphosphoglycerate
C
H-C-OH
CH₂OPO3²-
1,3-bisphosphoglycerate
O=C
CH3-SH
substitute for
Enz-SH
H
H-C-OH
|
CH₂OPO3²-
PO4³-
O.
S-Enz
H-C-OH
glyceraldehyde 3-phosphate
Propose a structure for the first intermediates in the reaction of 1,3-bisphosphoglycerate with a thiol group on the enzyme to form an enzyme-bound thioester. Assume a basic group on the enzyme catalyzes the formation of this
intermediate.
To simplify the drawing process, substitute the structures below for the 1,3-bisphosphoglycerate and Enz-SH.
CH₂OPO3²-
(Enzyme-bound
thioester)
NADH/H*
NAD*,…
Carbonic anhydrase facilitates the dissolution of carbon dioxide gas into water by catalyzing its hydration. Is the catalyzed reaction efficient? By what criterion do you state that?
a) The D-aldopentose A, C5H1005, reacts with HNO3 to yield an optically active aldaric acid B. Kiliani-Fischer
chain extension of A produces a pair of D-aldohexoses C and D. C is converted by HNO3 to an optically active
aldaric acid, but D is converted by HNO3 to an optically inactive aldaric acid. Write acyclic Fischer projections
for A, B, C, D.
b) Disaccharide E is a reducing sugar. It is hydrolyzed by an α-glycosidase enzyme, which means it contains an α-
glycoside link. Treatment of E with Ag2O and excess Mel gives an octamethyl derivative F. Hydrolysis of F in
dilute aqueous acid gives the pair of molecules shown below. Write the structures of E and F. (If the
stereochemistry at a particular carbon is not determined by the above data, indicate this with a wavy line as
shown below.)
HO OMe
OMe
MeO
MeO
MOH
OMe
mOH
OMe
OMe
Chapter 22 Solutions
Organic Chemistry
Ch. 22 - Prob. 1PPCh. 22 - Prob. 2PPCh. 22 - Prob. 3PPCh. 22 - Prob. 4PPCh. 22 - Prob. 5PPCh. 22 - Prob. 6PPCh. 22 - Prob. 7PPCh. 22 - Prob. 8PPCh. 22 - Practice Problem 22.9 What products would you...Ch. 22 - Prob. 10PP
Ch. 22 - Prob. 11PPCh. 22 - Prob. 12PPCh. 22 - Prob. 13PPCh. 22 - Prob. 14PPCh. 22 - Prob. 15PPCh. 22 - Prob. 16PPCh. 22 - Prob. 17PPCh. 22 - Prob. 18PPCh. 22 - Prob. 19PPCh. 22 - Prob. 20PCh. 22 - Prob. 21PCh. 22 - Prob. 22PCh. 22 - Prob. 23PCh. 22 - Prob. 24PCh. 22 - Prob. 25PCh. 22 - Prob. 26PCh. 22 - Prob. 27PCh. 22 - Prob. 28PCh. 22 - Prob. 29PCh. 22 - Prob. 30PCh. 22 - Prob. 31PCh. 22 - Prob. 32PCh. 22 - Prob. 33PCh. 22 - Prob. 34PCh. 22 - Prob. 35PCh. 22 - Prob. 36PCh. 22 - Prob. 37PCh. 22 - Prob. 38PCh. 22 - Arbutin, a compound that can be isolated from the...Ch. 22 - Prob. 40PCh. 22 - Prob. 41PCh. 22 - Prob. 42PCh. 22 - Prob. 43PCh. 22 - 22.44 The following reaction sequence represents...Ch. 22 - 22.45
The NMR data for the two anomers...Ch. 22 - Shikimic acid is a key biosynthetic intermediate...
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- Treatment of -D-glucose with methanol in the presence of an acid catalyst converts it into a mixture of two compounds called methyl glucosides (Section 25.3A). In these representations, the six-membered rings are drawn as planar hexagons. (a) Propose a mechanism for this conversion and account for the fact that only the OH on carbon 1 is transformed into an OCH3 group. (b) Draw the more stable chair conformation for each product. (c) Which of the two products has the chair conformation of greater stability? Explain.arrow_forwarda) The D-aldopentose A, C5H1005, reacts with HNO3 to yield an optically active aldaric acid B. Kiliani-Fischer chain extension of A produces a pair of D-aldohexoses C and D. C is converted by HNO3 to an optically active aldaric acid, but D is converted by HNO3 to an optically inactive aldaric acid. Write acyclic Fischer projections for A, B, C, D.arrow_forwardAn aldopentose "O", is oxidized with HNO3 to a diacid "P" which is optically active. The compound "O", is also degraded to an aldotetrose "Q" which undergoes another oxidation to an optically inactive diacid "R". Assuming that "O" has the configuration D-(4R); what are the structures of "O" to "R"?arrow_forward
- Prostaglandins are a class of eicosanoids, fatty acid derivatives involved in a variety of important phenomena, including fever, inflammation, and pain. The first step in prostaglandin synthesis involves the conversion of the 20-carbon fatty acid arachidonic acid to PGG2 by the enzyme prostaglandin endoperoxide synthase, or cyclooxy: Ibuprofen is one of several inhibitors of cyclooxogenase used therapeutically. Arachidonic acid 20₂ 0.5 1.0 1.5 2.5 3.5 cyclooxrygenase PGG₂ JOH محمد The following kinetic data were obtained for the enzyme cyclooxygenase in the absence of any inhibitor (1), and in the presence of ibuprofen (2) at a concentration of 48 [arachidonic acid] (uM) (1) v(uM/min) (2) v(uM/min) 23.5 32.2 36.9 41.8 44.0 16.67 25.25 30.49 37.04 38.91 Ibuprofen A. Plot the data in standard Michaelis-Menten form as well as in double-reciprocal form. B. Determine Vmax and Km for the enzyme. C. Based on this limited data set, what type of inhibition does ibuprofen likely exhibit?…arrow_forward1. Trehalose is a disaccharide that can be obtained from fungi, sea urchins and insects. Acid hydrolysis of trehalose yields only D-glucose. Trehalose is hydrolysed by α-glucosidase and not by β-glucosidase enzymes. Methylation of trehalose followed by hydrolysis yields two molar equivalents of 2,3,4,6-tetra-O-methyl-D-glucopyranose.From the following experimental data, deduce the structure of trehalose.What will be the effect of trehalose on Fehling’s solution? 2.Suggest a test you will use to show that a given food substance contains proteinarrow_forwardRibose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. When D-ribose is treated with methanol in the presence of an acid catalyst, two cyclic acetals, A and B, are formed, both with molecular formula C,H,0, These are separated, and each is treated with sodium periodate (Section 10.8C) followed by dilute aqueous acid. Both A and B yield the same three products in the same ratios. он о CHO СНО H+ CH,OH A +B ÕH 1. NalO, 2. H,0* НО CHO + CHOH + CH,OH ÕH CH,OH Isomeric cyclic acetals with molecular formula CH12O, D-Ribose (C;H1605) From this information, deduce whether the cyclic hemiacetal formed by D-ribose is four- membered, five-membered, or six-membered.arrow_forward
- rivatives: Nucleophilic Acyl Substitution Reactions - EOC O C-O [References] One step in the gluconeogenesis pathway for the biosynthesis of glucose is the partial reduction of 3-phosphoglycerate to give glyceraldehyde 3-phosphate. The process occurs by phosphorylation with ATP to give 1,3-bisphosphoglycerate, reaction with a thiol group on the enzyme to give an enzyme-bound thioester, and reduction with NADH. H-C-OH ATP ADP CH₂OPO32- 3-phosphoglycerate 0= OPO32- C H-C-OH CH₂OPO32 1,3-bisphosphoglycerate Enz-SH PO43- O= C S-Enz H-C-OH CH₂OPO3² (Enzyme-bound thioester) NADH/H+ O=C NAD*, Enz-SH H H-C-OH CH₂OPO3²- glyceraldehyde 3-phosphate Propose a structure for the first intermediate in the reaction of the enzyme-bound thioester with NADH to form glyceraldehyde 3-phosphate. To simplify the drawing process, substitute the structure below for the enzyme-bound thioester. S-CH3 substitute for the CH2CH3 enzyme-bound thioester You do not have to consider stereochemistry. • You do not have…arrow_forwardCompound A is a D-aldopentose that can be oxidized to an optically inactive aldaric acid B. On Kiliani-Fischer chain extension, A is converted into C and D; C can be oxidized to an optically active aldaric acid E, but D is oxidized to an optically inactive aldaric acid F. What is the structure of compound F? • Use the wedge/hash bond tools to indicate stereochemistry where it exists. You do not have to explicitly draw H atoms. If a group is achiral, do not use wedged or hashed bonds on it. • Show stereochemistry in a meso compound. • Do not include lone pairs in your answer. They will not be considered in the grading.arrow_forwardIsoerythrogenic acid, C18H26O2, is a acetylic fatty acid that turns vivid vle on exposure to UV light. On Catalytic hydrogenation over a palladium catalyst, five molar equivalents of hydrogen are absorbed, and stearic acidarrow_forward
- Raffinose is a trisaccharide (found in sugar beets) containing D-galactose ,D-glucose ,and D-fructose ,the enzyme a-galactase catalyze the hydrolysis of raffinose a to galactose and ysucrose. Draw the structure of raffinose .(the bond from galactose to the glucose moiety is a-1,6)arrow_forwardRibose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. To determine which ring is formed, ribose is treated with methanol in the presence of an acid catalyst. The products are then isolated and treated with NaIO, then with H₂O*. HO OH OH OH Ribose, C5H10O5 H 9.81 ** MeOH H* A & B isomeric cyclic acetals with formula C6H12O5 Assuming that ribose formed a five-membered ring cyclic hemiacetal, draw the structure of the sodium periodate digestion products. ▼ • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. 1. NalO4, 2. H₂O* MeOH products 4 SIF Previous Nextarrow_forwardTrehalose, C12H22O11, is a nonreducing sugar that is only 45% as sweet as sugar. When hydrolyzed by aqueous acid or the enzyme maltase, it formsonly d-glucose. When it is treated with excess methyl iodide in the presence of Ag2O and then hydrolyzed with water under acidic conditions, only2,3,4,6-tetra-O-methyl-d-glucose is formed. Draw the structure of trehalose.arrow_forward
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