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Concept explainers
Interpretation:
The structure of the anhydrous sugar (
Concept introduction:
舧 Chair conformations: It is the most stable conformation, which accurately shows the spatial arrangement of atoms.
舧 Equatorial bonds are parallel to the average plane of the ring, while axial bonds are perpendicular to the average plane of the ring.
舧 The conformation having bonds at the equatorial positions are more stable than those with bonds at the axial position.
舧 On flipping the cyclohexane ring, axial bonds become equatorial bonds and equatorial bonds becomes axial bond.
舧 Bulkier group acquires equatorial positions to form stable conformer due to steric factors.
舧 Sugars that have moisture content below 0.5% are said to be anhydrous sugars. They are usually high purity crystalline sugars obtained from
舧 Altrose is an aldohexose sugar with the chemical formula
舧 The most stable configuration of aldopyranoses is when the
舧 Stereochemistry: The equatorial orientation refers to the spatial arrangement of
舧 The anomeric effect is lowest for sugars with equatorial orientation, which results in lower energetic state, and consequently this type of orientation confers higher stability.
舧 The anomeric effect is highest for sugars with axial orientation, which results in higher energetic state, and consequently this type of orientation confers lower stability.
舧 The anhydrous sugar is produced when the axial
舧 Anhydrous sugar is an acetal, it is a nonreducing sugar, and therefore it is called anhydrous non-reducing sugar.
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Chapter 22 Solutions
Organic Chemistry
- So I need help with understanding how to solve these types of problems. I'm very confused on how to do them and what it is exactly, bonds and so forth that I'm drawing. Can you please help me with this and thank you very much!arrow_forwardSo I need help with this problem, can you help me please and thank you!arrow_forwardDraw the reaction mechanism to predict the product of the transformation below: N H ? H₂Oarrow_forward
- Draw a structural formula for the major product of the acid-base reaction shown. H 0 N + HCI (1 mole) CH3 N' (1 mole) CH3 You do not have to consider stereochemistry. ● • Do not include counter-ions, e.g., Na+, I, in your answer. . In those cases in which there are two reactants, draw only the product from 989 CH3 344 ? [Farrow_forwardQuestion 15 What is the major neutral organic product for the following sequence? 1. POCI₂ pyridine ? 2. OsO4 OH 3. NaHSO Major Organic Product ✓ OH OH 'OH OH 'OH 'CIarrow_forwardURGENT! PLEASE HELP!arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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