Organic Chemistry
Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 22, Problem 34P
Interpretation Introduction

Interpretation:

The structure of the disaccharide trehalose based on the given information’s provided is to be identified.

Concept introduction:

舧 Chair conformations: It is the most stable conformation, which accurately shows the spatial arrangement of atoms.

舧 Equatorial bonds are parallel to the average plane of the ring, while axial bonds are perpendicular to the average plane of the ring.

舧 The conformation having bonds at the equatorial positions are more stable than those with bonds at the axial position.

舧 On flipping the cyclohexane ring, axial bonds become equatorial bonds and equatorial bonds becomes axial bond.

舧 Bulkier group acquires equatorial positions to form stable conformer due to steric factors.

舧 The most stable configuration of aldopyranoses is when the CH2OH group exists in equatorial conformation.

舧 Stereochemistry: The equatorial orientation refers to the spatial arrangement of CH2OH group at C-2 in the same plane, and the axial orientation refers to the spatial arrangement of CH2OH group at C-2 along the axis.

舧 The anomeric effect is lowest for sugars with equatorial orientation, which results in lower energetic state, and consequently this type of orientation confers higher stability.

舧 The anomeric effect is highest for sugars with axial orientation, which results in higher energetic state, and consequently this type of orientation confers lower stability.

舧 A carbohydrate is a biomolecule consisting of carbon (C), hydrogen (H) and oxygen (O) atoms, usually with a hydrogen-oxygen atom ratio of 2:1

HNO3 is an oxidizing agent.

舧 Carbohydrates are oxidized by HNO3 to give aldaric acid as a product.

舧 Aldaric acids are carbohydrates having two carboxylic acids. They are formed due to oxidation reaction of aldoses with dilute HNO3 and their general reaction can be represented as:

Organic Chemistry, Chapter 22, Problem 34P , additional homework tip  1

舧 Monosaccharides containing six carbon atoms and an aldehyde group are called aldohexoses.

舧 Alditols are compounds produced from aldoses or ketoses on reduction with certain reagents such as sodium borohydride (NaBH4) and hydrogen along with a catalyst.

Organic Chemistry, Chapter 22, Problem 34P , additional homework tip  2

舧 Compounds formed by the reaction of reducing sugars with excess of phenyl hydrazine are called osazones. Osazones are products of oxidation and are produced by all reducing sugars.

Organic Chemistry, Chapter 22, Problem 34P , additional homework tip  3

舧 Fischer projection is a way of representing the structural formulae of compounds through cross formulation of their open chain structures.

舧. Bromine water is an effective reagent that selectively oxidizes the CHO group to COOH moiety, and thereby, converts an aldose into aldonic acid.

Organic Chemistry, Chapter 22, Problem 34P , additional homework tip  4

舧 Trehalose is a disaccharide found in yeasts, fungi, sea urchins, algae and insects. Its molecular formula is C12H22O11, consisting of two molecules of glucose. Mycose and trehalose are its other names.

舧 Sugars that react positively with Tollen’s reagent or Benedict’s solution are called reducing sugars, while those that do not react with Tollen’s reagent are called nonreducing sugars.

舧 The aldehyde group of an aldose reacts with three moles of phenylhydrazine to produce phenylosazone at C2 position. Osazones are products of oxidation.

舧 Mutarotation is the change in values of specific rotation of each anomer while attaining equilibrium in an aqueous solution.

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this is an organic chemistry question please answer accordindly!! please post the solution draw the figures and post, answer the question in a very simple and straight forward manner thanks!!!!! please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures or diagrams, please draw them on a paper and post clearly!! answer the full question with all details EACH PART CLEARLY please thanks!! im reposting this kindly solve all parts and draw it not just word explanations!!
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Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Select to Edit Arrows H H Select to Add Arrows > H CFCI: Select to Edit Arrows H Select to Edit Arrows
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