Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Chapter 21, Problem 57E
Interpretation Introduction
Interpretation:
The Lewis structure of all the isomers with the formula
Concept introduction:
Lewis diagram is the representation of the molecule or ion. It shows the bonding between the atoms and also shows the unshared pairs of electrons on an atom if any.
Alcohol is an organic compound in which a hydroxyl group is attached to the carbon chain. The general representation of alcohol is
Ether is an organic compound in which oxygen atom is attached with two alkyl groups. The general representation of ether is
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Draw Lewis structures and condensed structural formulas for the four alcohols with the molecular formula C4H10O. Classify each alcohol as primary, secondary, or tertiary. (Hint: First consider the connectivity of the four carbon atoms; they can be bonded either four in a chain or three in a chain with the fourth carbon as a branch on the middle carbon. Then consider the points at which the iOH group can be bonded to each carbon chain.)
Chapter 21 Solutions
Introductory Chemistry: An Active Learning Approach
Ch. 21 - Prob. 1ECh. 21 - Prob. 2ECh. 21 - Prob. 3ECh. 21 - Prob. 4ECh. 21 - Prob. 5ECh. 21 - Prob. 6ECh. 21 - Prob. 7ECh. 21 - Prob. 8ECh. 21 - Prob. 9ECh. 21 - Prob. 10E
Ch. 21 - Prob. 11ECh. 21 - Prob. 12ECh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Prob. 15ECh. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Prob. 19ECh. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Is the general formula of a cycloalkanes the same...Ch. 21 - Prob. 24ECh. 21 - Draw the skeleton diagram of cyclopentane.Ch. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - What is the difference in bonding and in the...Ch. 21 - Prob. 38ECh. 21 - Draw the structural formula of trichloroethene, a...Ch. 21 - Prob. 40ECh. 21 - Prob. 41ECh. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - Give the IUPAC name of the following molecule:Ch. 21 - Give the IUPAC name of the following molecule:Ch. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Prob. 49ECh. 21 - Prob. 50ECh. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Prob. 53ECh. 21 - Prob. 54ECh. 21 - Write an equation for the hydrogenation of...Ch. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Explain why the ether with formula C2H6O is very...Ch. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Prob. 70ECh. 21 - Prob. 71ECh. 21 - Prob. 72ECh. 21 - Prob. 73ECh. 21 - Prob. 74ECh. 21 - Prob. 75ECh. 21 - Prob. 76ECh. 21 - Prob. 77ECh. 21 - Prob. 78ECh. 21 - Prob. 79ECh. 21 - Prob. 80ECh. 21 - Prob. 81ECh. 21 - Prob. 82ECh. 21 - Prob. 83ECh. 21 - Prob. 84ECh. 21 - Prob. 85ECh. 21 - Prob. 86ECh. 21 - Prob. 87ECh. 21 - Prob. 88ECh. 21 - Prob. 89ECh. 21 - Prob. 90ECh. 21 - Prob. 91ECh. 21 - Prob. 92ECh. 21 - Prob. 93ECh. 21 - Prob. 94ECh. 21 - Distinguish precisely, and in scientific terms,...Ch. 21 - Prob. 96ECh. 21 - What is the difference in bonding and in general...Ch. 21 - Draw all isomers of C4H8.Ch. 21 - Prob. 99ECh. 21 - Prob. 100ECh. 21 - Prob. 101ECh. 21 - Prob. 102ECh. 21 - Prob. 103ECh. 21 - Prob. 104ECh. 21 - Prob. 105ECh. 21 - Prob. 106ECh. 21 - Prob. 107ECh. 21 - Prob. 21.1TCCh. 21 - Prob. 21.2TCCh. 21 - Prob. 21.3TCCh. 21 - Prob. 21.4TCCh. 21 - Prob. 21.5TCCh. 21 - Prob. 21.6TCCh. 21 - Prob. 21.7TCCh. 21 - Prob. 21.8TCCh. 21 - Prob. 21.9TCCh. 21 - Prob. 21.10TCCh. 21 - Prob. 21.11TCCh. 21 - Prob. 21.12TCCh. 21 - Prob. 1CLECh. 21 - Prob. 2CLECh. 21 - Prob. 3CLECh. 21 - Prob. 4CLECh. 21 - Prob. 5CLECh. 21 - Prob. 6CLECh. 21 - Prob. 7CLECh. 21 - Prob. 8CLECh. 21 - Prob. 9CLECh. 21 - Prob. 10CLE
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Alcohols A, B and C all have the composition C4H 100. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidized to a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor a ketone. Write the Lewis structures of these molecules.arrow_forwardThe chemical formula C4H10O results in four alcohols and three ethers for a total of seven structuralisomers. Draw pairs of structural formulas for these molecules that illustrate positional and functional isomerism on a sheet of paper. You will be drawing a total of four formulas. Label each pair as positional or functional.arrow_forwardTwo of the three isomers of C3H8O are alcohols and one is an ether. Draw Lewis structures for these three isomers.arrow_forward
- How does the structure of an alcohol differ from an ether? Describe how an aldehyde differs in structure from a ketone. Thiols are compounds which resemble alcohols, except that the oxygen atom is replaced by a sulfur atom. Draw the analogous thiol for the four carbon alcohol in Table 1. Describe the structural difference between carboxylic acids and esters. Are ethers polar molecules? Would you expect ethers to have higher or lower boiling points than alkanes (circle one)? Explain. Pentane (an alkane) has a boiling point of 36 °C. Does the data agree with your prediction? explain why this could be the casearrow_forwardGiven the molecular formula C5H12O, give the structures (any form) and names of a primary, secondary, and tertiary alcohol, and an ether (ether can be named for EC).arrow_forwardAlcohols A, B, and C all have the composition C4H10O. Molecules of alcohol A contain a branched carbon chain and can be oxidized to an aldehyde; molecules of alcohol B contain a linear carbon chain and can be oxidizedto a ketone; and molecules of alcohol C can be oxidized to neither an aldehyde nor a ketone. Write the Lewis structures of these molecules.arrow_forward
- 12. Write bond-line structural formulas for (a.) two primary alcohols, (b.) a secondary alcohol, and (c.) a tertiary alcohol-all having the molecular formula CaH100.arrow_forward1. The chemical formula C4H100 results in four alcohols and three ethers for a total of seven structural isomers. Draw pairs of structural formulas for these molecules that illustrate positional and functional isomerism on a sheet of paper. You will be drawing a total of four formulas. Label each pair as positional or functional.arrow_forwardDraw the structure(s) of the alcohols with the molecular formula C5H12O that have a four-carbon chain.arrow_forward
- 2. Write bond-line structural formulas for (a.) two primary alcohols, (b.) a secondary alcohol, and (c.) atertiary alcohol—all having the molecular formula C4H10O.arrow_forwardPlease draw the structures and provide the names of all the isomeric alcohols that have the molecular formula C4H10Oarrow_forwardTRUE OR FALSE (a) A functional group is a group of atoms in an organic molecule that undergoes a predictable set of chemical reactions. (b) The functional group of an alcohol, an aldehyde, and a ketone have in common the fact that each contains a single oxygen atom. (c) A primary alcohol has one —OH group, a secondary alcohol has two —OH groups, and a tertiary alcohol has three —OH groups. (d) There are two alcohols with the molecular formula C3H8O. (e) There are three amines with the molecular formula C3H9N. (f) Aldehydes, ketones, carboxylic acids, and esters all contain a carbonyl group. (g) A compound with the molecular formula of C3H6O may be either an aldehyde, a ketone, or a carboxylic acid. (h) Bond angles about the carbonyl carbon of an aldehyde, a ketone, a carboxylic acid, and an ester are all approximately 109.5°. (i) The molecular formula of the smallest aldehyde is C3H6O, and that of the smallest ketone is also C3H6O. (j) The molecular formula of the smallest carboxylic…arrow_forward
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