Chapter 21, Problem 21.30P

Interpretation Introduction

Interpretation:

It is to be shown how to synthesize $\text{hexan-1-one}$ from acetoacetic ester.

Concept introduction:

In case of active methylene compounds, the protons on the α${\text{CH}}_{\text{2}}$ group, which is flanked between the two electron-withdrawing groups, are significantly more acidic than normal ketones and esters. It is because the formed enolate conjugate base is stabilized by resonance as well as inductive effect. This negatively charged enolate anion is highly nucleophilic and reacts with electrophiles. This enolate anion reacts with an alkyl halide to produce the alkylated product via ${\text{S}}_{\text{N}}\text{2}$ reaction. An ester on acid or base-catalyzed hydrolysis produces corresponding carboxylic acid. $\text{β-Keto}$ acid, on heating, undergoes decarboxylation reaction to produce corresponding keto compound and gaseous carbon dioxide (${\text{CO}}_{\text{2}}$) is liberated from the solution.