Organic Chemistry
Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
bartleby

Concept explainers

Question
Book Icon
Chapter 20, Problem 48P
Interpretation Introduction

Interpretation:

The structure is to be proposed for compound B, which is an isomer of compound A(Problem20.47) containing the molecular formula C10H15N.

Concept Introduction:

Carbon nuclear magnetic resonance (13CNMR) is considered homologous to the nuclear magnetic resonance (1HNMR).

In NMR spectroscopy, the proton nuclear magnetic resonance (1HNMR) is used to find out the structure of molecules with the help of 1H atom within the molecules.

The splitting of the molecules is determined by (n+1) peaks in an NMR resonance, where n is the number of hydrogens on the adjacent atom.

Nuclear Magnetic Resonance (NMR) is one of the most capable analytical techniques used for determining the functional groups and how the atoms are structured and arranged in a molecule.

Few elements, such as 13C and 1H, have nuclei behaving as magnets about an axis. These elements are placed in magnetic field irradiated with electromagnetic energy of specific frequency and the nuclei tend to absorb energy via magnetic resonance. There is this graph that shows energy absorption frequencies and intensities of a sample kept in the magnetic field called nuclear magnetic resonance (NMR).

In NMR spectroscopy, the proton nuclear magnetic resonance (1HNMR) is used to find out the structure of molecules with the help of 1H atom within the molecules.

Induced magnetic field consists of electricity generated from movement in a magnetic field.

The position of a signal on x-axis in the NMR spectrum depicts the chemical shift expressed in δ or ppm.

The number of signals in H1 NMR spectrum represents the number of different chemical environments for the protons.

The area covered by the signal is proportional to the number of equivalent protons causing the signal.

The hydrogen atoms on adjacent carbon atoms split the signal into two or more peaks. One, two or three hydrogen atoms split the signal into two, three or four peaks described as doublet, triplet or quartet respectively.

A decrease in the electron density around a proton deshields the signal downfield at a larger value of chemical shift.

An increase in electron density shields the signal upfield at a lower value of chemical shift.

13C NMR is only used in the observation of isotopes of carbon atoms.

Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various functional groups.

It depends on the interactions of atoms or molecules with the electromagnetic radiation.

Infrared spectroscopy is most commonly used in the identification of the structure of the compound.

Infrared spectroscopy is the examination of the infrared light interacting with a molecule. The examination can be done in three ways, that is, by measuring absorption, emission, and reflection, and it can also measure the vibration of atoms.

Blurred answer
Students have asked these similar questions
Indicate the correct option.a) Graphite conducts electricity, being an isotropic materialb) Graphite is not a conductor of electricityc) Both are false
(f) SO: Best Lewis Structure 3 e group geometry:_ shape/molecular geometry:, (g) CF2CF2 Best Lewis Structure polarity: e group arrangement:_ shape/molecular geometry: (h) (NH4)2SO4 Best Lewis Structure polarity: e group arrangement: shape/molecular geometry: polarity: Sketch (with angles): Sketch (with angles): Sketch (with angles):
1. Problem Set 3b Chem 141 For each of the following compounds draw the BEST Lewis Structure then sketch the molecule (showing bond angles). Identify (i) electron group geometry (ii) shape around EACH central atom (iii) whether the molecule is polar or non-polar (iv) (a) SeF4 Best Lewis Structure e group arrangement:_ shape/molecular geometry: polarity: (b) AsOBr3 Best Lewis Structure e group arrangement:_ shape/molecular geometry: polarity: Sketch (with angles): Sketch (with angles):

Chapter 20 Solutions

Organic Chemistry

Ch. 20 - Practice Problem 20.11 In the preceding examples...Ch. 20 - Prob. 12PPCh. 20 - Prob. 13PPCh. 20 - Practice Problem 20.14 Outline a synthesis of...Ch. 20 - Prob. 15PPCh. 20 - Prob. 16PPCh. 20 - Prob. 17PPCh. 20 - Prob. 18PPCh. 20 - Prob. 19PCh. 20 - 20.20 Give common or systematic names for each of...Ch. 20 - Which is the most basic nitrogen in each compound?...Ch. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Show how you might synthesize each of the...Ch. 20 - Prob. 25PCh. 20 - 20.26 Provide the major organic product from each...Ch. 20 - Prob. 27PCh. 20 - 20.28 What products would you expect to be formed...Ch. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Write equations for simple chemical rests or state...Ch. 20 - Prob. 33PCh. 20 - Explain the following, including mention of key...Ch. 20 - 20.35 Provide a detailed mechanism for each of the...Ch. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - 20.40 Give structures for compounds R-W: Ch. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Diethylpropion (shown here) is a compound used in...Ch. 20 - Prob. 44PCh. 20 - 20.45 Compound W is soluble in dilute aqueous HCI...Ch. 20 - 20.46 Propose structures for compounds X, Y, and...Ch. 20 - Compound A(C10H15N) is soluble in dilute HCI. The...Ch. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - For each of the following, identify the product...Ch. 20 - 20.51 Develop a synthesis for the following...Ch. 20 - 20.52 When phenyl isochiocyanatc, , is reduced...Ch. 20 - Prob. 53PCh. 20 - 20.54 Propose a mechanism that can explain the...Ch. 20 - When acetone is treated with anhydrous ammonia in...Ch. 20 - Prob. 56P
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Text book image
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT